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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#625443#7612. Matrix Inverseucup-team3519#TL 0ms3644kbC++175.4kb2024-10-09 19:20:502024-10-09 19:20:50

Judging History

你现在查看的是最新测评结果

  • [2024-10-09 19:20:50]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:3644kb
  • [2024-10-09 19:20:50]
  • 提交

answer

#include <bits/stdc++.h>

template <int m>
class ModInt {
    int raw;
    using mint = ModInt;
    using i64 = int64_t;

public:
    ModInt() : raw(0) {}
    ModInt(const auto &v) {
        raw = v % m;
        if (raw < 0) {
            raw += m;
        }
    }
    int value() const {
        return raw;
    }

    mint &operator+=(const mint &rhs) {
        raw += rhs.raw;
        if (raw >= m) {
            raw -= m;
        }
        return *this;
    }
    mint &operator-=(const mint &rhs) {
        raw -= rhs.raw;
        if (raw < 0) {
            raw += m;
        }
        return *this;
    }
    mint &operator*=(const mint &rhs) {
        raw = (i64)raw * rhs.raw % m;
        return *this;
    }
    mint &operator/=(const mint &rhs) {
        return *this *= qpow(rhs, m - 2);
    }

    friend mint operator+(const mint &lhs, const mint &rhs) {
        return mint{lhs} += rhs;
    }
    friend mint operator-(const mint &lhs, const mint &rhs) {
        return mint{lhs} -= rhs;
    }
    friend mint operator*(const mint &lhs, const mint &rhs) {
        return mint{lhs} *= rhs;
    }
    friend mint operator/(const mint &lhs, const mint &rhs) {
        return mint{lhs} /= rhs;
    }

    static constexpr int mod() {
        return m;
    }

    static mint qpow(mint a, i64 b) {
        mint res = 1;
        while (b) {
            if (b & 1) {
                res *= a;
            }
            a *= a, b >>= 1;
        }
        return res;
    }
};

template <typename T>
int solve_linear_equations(std::vector<std::vector<T>> &a, auto abs, auto is_zero) {
    const int n = a.size();
    for (int i = 0; i < n; ++i) {
        int p = i;
        for (int j = i + 1; j < n; ++j) {
            if (abs(a[j][i]) > abs(a[p][i])) {
                p = j;
            }
        }
        if (i != p) {
            std::swap(a[i], a[p]);
        }
        if (is_zero(a[i][i])) {
            return -1;
        }
        T f = 1 / a[i][i];
        for (int k = i; k <= n; ++k) {
            a[i][k] *= f;
        }
        for (int j = i + 1; j < n; ++j) {
            T f = a[j][i];
            for (int k = i; k <= n; ++k) {
                a[j][k] -= a[i][k] * f;
            }
        }
    }

    for (int i = n - 1; i >= 0; --i) {
        for (int j = i - 1; j >= 0; --j) {
            a[j][n] -= a[j][i] * a[i][n];
            a[j][i] = 0;
        }
    }
    return 0;
}

using mint = ModInt<static_cast<int>(1e9 + 7)>;
constexpr int MAXN = 2e3 + 19;

int buf[MAXN][MAXN];
std::mt19937 rng(std::chrono::steady_clock::now().time_since_epoch().count());

namespace fast
{
    char B[1 << 18], *S = B, *T = B;
    #define getc() (S == T && (T = (S = B) + fread(B, 1, 1 << 18, stdin), S == T) ? 0 : *S++)
    int read() {
        int ret = 0;
        char c;
        while (c = getc(), c < '0' || c > '9');
        for (; c >= '0' && c <= '9'; c = getc()) ret = ret * 10 + c - '0';
        return ret;
    }
}
using fast::read;

int main() {
    int n = read();

    std::vector<std::vector<mint>> a(n), b(n);
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < n; ++j) {
            buf[i][j] = read();
        }
    }
    for (int i = 0; i < n; ++i) {
        a[i].resize(n);
        for (int j = 0; j < n; ++j) {
            a[i][j] = buf[i][j];
        }
    }
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < n; ++j) {
            buf[i][j] = read();
        }
    }
    for (int i = 0; i < n; ++i) {
        b[i].resize(n);
        for (int j = 0; j < n; ++j) {
            b[i][j] = buf[j][i];
        }
    }
    
    std::vector<mint> fac(n);
    std::vector<uint8_t> fault(n);
    for (int _ = 0; _ < 3; ++_) {
        for (int i = 0; i < n; ++i) {
            fac[i] = rng();
        }
        std::vector<mint> e(n);
        for (int i = 0; i < n; ++i) {
            for (int j = 0; j < n; ++j) {
                e[j] += fac[i] * a[i][j];
            }
        }
        for (int col = 0; col < n; ++col) {
            mint expected = fac[col];
            mint actual = 0;
            for (int i = 0; i < n; ++i) {
                actual += e[i] * b[col][i];
            }
            if (expected.value() != actual.value()) {
                fault[col] = true;
            }
        }
    }

    std::vector<std::pair<std::pair<int, int>, int>> ans;
    std::vector<std::vector<mint>> w(n, std::vector<mint>(n + 1));
    for (int col = 0; col < n; ++col) {
        if (!fault[col]) {
            continue;
        }
        for (int i = 0; i < n; ++i) {
            for (int j = 0; j < n; ++j) {
                w[i][j] = a[i][j];
            }
            w[i][n] = (i == col);
        }
        solve_linear_equations(w,
            [](mint x) {
                return x.value();
            },
            [](mint x) {
                return x.value() == 0;
            }
        );
        for (int i = 0; i < n; ++i) {
            if (b[col][i].value() != w[i][n].value()) {
                std::pair<int, int> pos = {i, col};
                int v = w[i][n].value();
                ans.emplace_back(pos, v);
            }
        }
    }

    std::sort(ans.begin(), ans.end());

    std::cout << ans.size() << '\n';
    for (auto [pos, v] : ans) {
        std::cout << pos.first + 1 << ' ' << pos.second + 1 << ' ' << v << '\n';
    }
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3644kb

input:

1
953176428
107682094

output:

0

result:

ok single line: '0'

Test #2:

score: -100
Time Limit Exceeded

input:

1995
586309310 548144807 578573993 437893403 641164340 712256053 172321263 108058526 768610920 123320669 762746291 856047593 979279376 29067913 309867338 292286426 45124325 239705174 675003623 213743652 620561338 116308277 695369179 669459894 682522334 846995555 159510341 999359657 645579085 7499563...

output:


result: