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| ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
|---|---|---|---|---|---|---|---|---|---|
| #624799 | #5. 在线 O(1) 逆元 | dww_1337 | Compile Error | / | / | C++14 | 323b | 2024-10-09 16:38:51 | 2024-11-05 22:04:45 |
Judging History
你现在查看的是最新测评结果
- [2024-11-05 22:04:45]
- 管理员手动重测本题所有提交记录
- 测评结果：Compile Error
- 用时：0ms
- 内存：0kb
- [2024-10-09 16:38:53]
- 评测
- 测评结果：Compile Error
- 用时：0ms
- 内存：0kb
- [2024-10-09 16:38:51]
- 提交
answer
#include "inv.h"
const int MAXN = 1e8 + 7;
const int MOD = 998244353;
int invt[MAXN];
void init(int p)
{
invt[1] = 1;
for(int i = 2 ; i < MAXN ; i++) invt[i] = p - 1ll * p / i * invt[p % i] % p;
}
int inv(int x)
{
if(x < MAXN) return invt[x]
else return MOD - 1ll * (MOD / x) * inv(MOD % x) % MOD;
}
Details
implementer.cpp: In function ‘int main()’:
implementer.cpp:22:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
22 | scanf("%d", &n);
| ~~~~~^~~~~~~~~~
answer.code: In function ‘int inv(int)’:
answer.code:15:36: error: expected ‘;’ before ‘else’
15 | if(x < MAXN) return invt[x]
| ^
| ;
16 | else return MOD - 1ll * (MOD / x) * inv(MOD % x) % MOD;
| ~~~~