QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#62338 | #4539. Independent Feedback Vertex Set | qinjianbin | AC ✓ | 253ms | 4264kb | C++ | 4.4kb | 2022-11-18 10:52:06 | 2022-11-18 10:52:09 |
Judging History
answer
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
#include<cctype>
#include<ctime>
#include<queue>
#include<stack>
#include<deque>
#include<map>
#include<unordered_map>
#include<set>
#include<unordered_set>
#include<bitset>
#include<functional>
using namespace std;
//STL库常用(vector, map, set, pair)
#define pii pair<int,int>
#define pdd pair<double,double>
#define F first
#define S second
//常量
#define PI (acos(-1.0))
#define INF 0x3f3f3f3f
//必加
#ifdef TanJI
#include<cassert>
#define dbg(...) do {cerr << #__VA_ARGS__ << " -> "; err(__VA_ARGS__); } while(0)
void err() {cerr << endl;}
template<template<typename...> class T, typename t, typename... A> void err(T<t> a, A... x) {for (auto v: a) cerr << v << ' '; cerr << ", "; err(x...);}
template<typename T, typename... A> void err(T a, A... x) {cerr << a << ' '; err(x...);}
template<typename T> void err(T *a, int len) {for (int i = 0; i < len; i++) cerr << a[i] << ' '; err();}
#else
#define dbg(...)
#define assert(...)
#endif
typedef unsigned long long ull;
typedef long long ll;
typedef double db;
// 快读快输
template<typename T> inline T read() {T x=0; bool f=0; char c=getchar();while(!isdigit(c)){if(c =='-')f= 1; c=getchar();}while(isdigit(c)){x=(x<<3)+(x<<1)+(c^48);c=getchar();}return f?~x+1:x;}
template<typename T> inline void print(T k){ int num = 0,ch[20]; if(k == 0){ putchar('0'); return ; } (k<0)&&(putchar('-'),k = -k); while(k>0) ch[++num] = k%10, k /= 10; while(num) putchar(ch[num--]+48); }
//图论
const int GRAPHN = 1, GRAPHM = 1;
int h[GRAPHN], e[GRAPHM], ne[GRAPHM], wei[GRAPHM], idx;
void AddEdge(int a, int b) {e[idx] = b, ne[idx] = h[a], h[a] = idx++;}
void AddEdge(int a, int b, int c) {e[idx] = b, ne[idx] = h[a], wei[idx] = c, h[a] = idx++;}
void AddEdge(int h[], int a, int b) {e[idx] = b, ne[idx] = h[a], h[a] = idx++;}
void AddEdge(int h[], int a, int b, int c) {e[idx] = b, ne[idx] = h[a], wei[idx] = c, h[a] = idx++;}
// 数学公式
template<typename T> inline T gcd(T a, T b){ return b==0 ? a : gcd(b,a%b); }
template<typename T> inline T lowbit(T x){ return x&(-x); }
template<typename T> inline bool mishu(T x){ return x>0?(x&(x-1))==0:false; }
template<typename T1,typename T2, typename T3> inline ll q_mul(T1 a,T2 b,T3 p){ ll w = 0; while(b){ if(b&1) w = (w+a)%p; b>>=1; a = (a+a)%p; } return w; }
template<typename T,typename T2> inline ll f_mul(T a,T b,T2 p){ return (a*b - (ll)((long double)a/p*b)*p+p)%p; }
template<typename T1,typename T2, typename T3> inline ll q_pow(T1 a,T2 b,T3 p){ ll w = 1; while(b){ if(b&1) w = (w*a)%p; b>>=1; a = (a*a)%p;} return w; }
template<typename T1,typename T2, typename T3> inline ll s_pow(T1 a,T2 b,T3 p){ ll w = 1; while(b){ if(b&1) w = q_mul(w,a,p); b>>=1; a = q_mul(a,a,p);} return w; }
template<typename T> inline ll ex_gcd(T a, T b, T& x, T& y){ if(b == 0){ x = 1, y = 0; return (ll)a; } ll r = ex_gcd(b,a%b,y,x); y -= a/b*x; return r;/*gcd*/ }
template<typename T1,typename T2> inline ll com(T1 m, T2 n) { int k = 1;ll ans = 1; while(k <= n){ ans=((m-k+1)*ans)/k;k++;} return ans; }
template<typename T> inline bool isprime(T n){ if(n <= 3) return n>1; if(n%6 != 1 && n%6 != 5) return 0; T n_s = floor(sqrt((db)(n))); for(int i = 5; i <= n_s; i += 6){ if(n%i == 0 || n%(i+2) == 0) return 0; } return 1; }
/* ----------------------------------------------------------------------------------------------------------------------------------------------------------------- */
const int MAXN = 1e5 + 10;
int T, n;
int a[MAXN];
int val[MAXN];
ll ans[MAXN];
int main() {
#ifdef TanJI
clock_t c1 = clock();
freopen("D:\\Cpp\\1.in", "r", stdin);
freopen("D:\\Cpp\\1.out", "w", stdout);
#endif
//--------------------------------------------
a[1] = 1, a[2] = 2, a[3] = 3;
scanf("%d", &T);
while (T--) {
scanf("%d", &n);
ans[1] = ans[2] = ans[3] = 0;
for (int i = 1; i <= n; i++) scanf("%d", &val[i]);
int u, v;
for (int i = 4; i <= n; i++) {
scanf("%d%d", &u, &v);
a[i] = 6 - a[u] - a[v];
}
for (int i = 1; i <= n; i++)
ans[a[i]] += val[i];
printf("%lld\n", max({ans[1], ans[2], ans[3]}));
}
//--------------------------------------------
#ifdef TanJI
cerr << "Time Used:" << clock() - c1 << "ms" << endl;
#endif
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 253ms
memory: 4264kb
input:
1000 1561 14 78 18 74 80 97 70 49 39 81 79 65 55 1 29 32 91 73 94 41 69 41 79 34 62 81 25 33 76 26 57 69 66 48 37 78 67 50 21 8 27 58 58 32 8 42 31 52 35 36 99 56 61 27 4 64 50 59 43 55 73 53 41 80 94 32 56 59 19 57 28 56 35 73 70 13 18 6 96 47 71 29 16 73 65 27 61 68 50 11 21 96 19 18 33 97 6 43 19...
output:
26477 730 133872218725 206 139 26838 225784601561 409 163907525588 65 27568981002 26830437 612 206 647 3808763 392 39765006630 9823066 71309193 126 10667 93591615 12028 113 12356789 2420359 213 418 223 166 40 5324 219 1419 562 663 22941 14 39 102638547 14199134 58 201 12653791 101 10447 16511 171245...
result:
ok 1000 lines