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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#620847#8635. 圆wsyear90 978ms3864kbC++233.1kb2024-10-07 21:45:462024-10-07 21:45:47

Judging History

你现在查看的是最新测评结果

  • [2024-10-07 21:45:47]
  • 评测
  • 测评结果:90
  • 用时:978ms
  • 内存:3864kb
  • [2024-10-07 21:45:46]
  • 提交

answer

#include <bits/stdc++.h>

#define rep(i, j, k) for (int i = (j); i <= (k); ++i)
#define per(i, j, k) for (int i = (j); i >= (k); --i)
#define SZ(v) int((v).size())
#define ALL(v) (v).begin(),(v).end()
#define fi first
#define se second
using ll = long long;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;

template<class T>inline void chkmn(T &x, T y) { if (y < x) x = y; }
template<class T>inline void chkmx(T &x, T y) { if (y > x) x = y; }

using namespace std;

template <int P>
class mod_int {
  using Z = mod_int;

private:
  static int mo(int x) { return x < 0 ? x + P : x; }

public:
  int x;
  int val() const { return x; }
  mod_int() : x(0) {}
  template <class T>
  mod_int(const T &x_) : x(x_ >= 0 && x_ < P ? static_cast<int>(x_) : mo(static_cast<int>(x_ % P))) {}
  bool operator==(const Z &rhs) const { return x == rhs.x; }
  bool operator!=(const Z &rhs) const { return x != rhs.x; }
  Z operator-() const { return Z(x ? P - x : 0); }
  Z pow(long long k) const {
    Z res = 1, t = *this;
    while (k) {
      if (k & 1) res *= t;
      if (k >>= 1) t *= t;
    }
    return res;
  }
  Z &operator++() {
    x < P - 1 ? ++x : x = 0;
    return *this;
  }
  Z &operator--() {
    x ? --x : x = P - 1;
    return *this;
  }
  Z operator++(int) {
    Z ret = x;
    x < P - 1 ? ++x : x = 0;
    return ret;
  }
  Z operator--(int) {
    Z ret = x;
    x ? --x : x = P - 1;
    return ret;
  }
  Z inv() const { return pow(P - 2); }
  Z &operator+=(const Z &rhs) {
    (x += rhs.x) >= P && (x -= P);
    return *this;
  }
  Z &operator-=(const Z &rhs) {
    (x -= rhs.x) < 0 && (x += P);
    return *this;
  }
  Z &operator*=(const Z &rhs) {
    x = 1ULL * x * rhs.x % P;
    return *this;
  }
  Z &operator/=(const Z &rhs) { return *this *= rhs.inv(); }
#define setO(T, o)                                 \
  friend T operator o(const Z &lhs, const Z &rhs) {\
    Z res = lhs;                                   \
    return res o## = rhs;                          \
  }
  setO(Z, +) setO(Z, -) setO(Z, *) setO(Z, /)
#undef setO
};
const int P = 998244353;
using Z = mod_int<P>;

const int maxn = 5010;

int n;
Z fac[maxn], ivf[maxn], f[maxn][2][2], g[maxn][2][2], dp[maxn];

Z binom(int x, int y) {
  if (x < 0 || y < 0 || x < y) return 0;
  return fac[x] * ivf[y] * ivf[x - y];
}

int main() {
  fac[0] = 1;
  rep (i, 1, maxn - 1) fac[i] = fac[i - 1] * i;
  ivf[maxn - 1] = fac[maxn - 1].inv();
  per (i, maxn - 1, 1) ivf[i - 1] = ivf[i] * i;
  cin.tie(nullptr) -> ios::sync_with_stdio(false);
  cin >> n;
  rep (o1, 0, 1) rep (o2, 0, 1) {
    rep (i, 0, n) rep (j, 0, 1) rep (k, 0, 1) f[i][j][k] = 0;
    f[0][o1][o2] = 1;
    rep (i, 1, n) {
      rep (p, 0, n) rep (j, 0, 1) rep (k, 0, 1) {
        g[p][j][k] = f[p][j][k], f[p][j][k] = 0;
      }
      rep (p, 0, n) rep (j, 0, 1) rep (k, 0, 1) {
        if (j) f[p][k][0] += g[p][j][k];
        f[p + 1][1][1] += g[p][j][k];
      }
    }
    rep (i, 0, n) dp[i] += f[i][o1][o2];
  }
  Z ans = fac[n] * n;
  rep (i, 1, n - 1) ans -= dp[i] * fac[i] * fac[n - i];
  cout << (ans * ivf[n]).val() << '\n';
}

详细


Pretests


Final Tests

Test #1:

score: 10
Accepted
time: 1ms
memory: 3860kb

input:

3

output:

1

result:

ok 1 number(s): "1"

Test #2:

score: 10
Accepted
time: 0ms
memory: 3832kb

input:

4

output:

2

result:

ok 1 number(s): "2"

Test #3:

score: 10
Accepted
time: 0ms
memory: 3848kb

input:

6

output:

299473309

result:

ok 1 number(s): "299473309"

Test #4:

score: 10
Accepted
time: 0ms
memory: 3852kb

input:

10

output:

487238321

result:

ok 1 number(s): "487238321"

Test #5:

score: 10
Accepted
time: 1ms
memory: 3784kb

input:

100

output:

41620761

result:

ok 1 number(s): "41620761"

Test #6:

score: 10
Accepted
time: 2ms
memory: 3864kb

input:

200

output:

208771764

result:

ok 1 number(s): "208771764"

Test #7:

score: 10
Accepted
time: 6ms
memory: 3832kb

input:

500

output:

888621375

result:

ok 1 number(s): "888621375"

Test #8:

score: 10
Accepted
time: 940ms
memory: 3860kb

input:

4798

output:

319137015

result:

ok 1 number(s): "319137015"

Test #9:

score: 10
Accepted
time: 978ms
memory: 3860kb

input:

4999

output:

818467659

result:

ok 1 number(s): "818467659"

Test #10:

score: 0
Time Limit Exceeded

input:

5000

output:

142907477

result: