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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#620630#1869. Power Station of ArtcaijianhongRE 1ms3812kbC++201.8kb2024-10-07 19:55:372024-10-07 19:55:37

Judging History

你现在查看的是最新测评结果

  • [2024-10-07 19:55:37]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3812kb
  • [2024-10-07 19:55:37]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#define debug(...) (void)fprintf(stderr, ##__VA_ARGS__)
#else
#define endl "\n"
#define debug(...) (void)0
#endif
using LL = long long;
int n, m, w1[100010], w2[100010], col[100010];
char col1[100010], col2[100010];
vector<int> g[100010], V;
bool ef;
void ffl(int u) {
  V.push_back(u);
  for (int v : g[u]) if (!col[v]) col[v] = 3 - col[u], ffl(v); else if (col[u] != 3 - col[v]) ef = false;
}
int mian() {
  cin >> n >> m;
  for (int i = 1; i <= n; i++) g[i].clear(), col[i] = 0;
  for (int i = 1, u, v; i <= m; i++) cin >> u >> v, g[u].push_back(v), g[v].push_back(u);
  for (int i = 1; i <= n; i++) cin >> w1[i];
  for (int i = 1; i <= n; i++) cin >> col1[i];
  for (int i = 1; i <= n; i++) cin >> w2[i];
  for (int i = 1; i <= n; i++) cin >> col2[i];
  for (int rt = 1; rt <= n; rt++) if (!col[rt]) {
    col[rt] = 1, ef = true, V.clear(), ffl(rt);
    if (ef) {
      vector<int> lhs, rhs;
      for (int i : V) {
        lhs.push_back(w1[i] << 1 | ((col[i] == 1) ^ (col1[i] == 'R')));
        rhs.push_back(w2[i] << 1 | ((col[i] == 1) ^ (col2[i] == 'R')));
      }
      sort(lhs.begin(), lhs.end());
      sort(rhs.begin(), rhs.end());
      if (lhs != rhs) return 0;
    } else {
      vector<int> lhs, rhs;
      int cnt = 0;
      for (int i : V) {
        lhs.push_back(w1[i]);
        if (col1[i] == 'R') cnt ^= 1;
        rhs.push_back(w2[i]);
        if (col2[i] == 'R') cnt ^= 1;
      }
      sort(lhs.begin(), lhs.end());
      sort(rhs.begin(), rhs.end());
      if (lhs != rhs || cnt) return 0;
    }
  }
  return 1;
}
int main() {
#ifndef LOCAL
#ifdef NF
  freopen("graph.in", "r", stdin);
  freopen("graph.out", "w", stdout);
#endif
  cin.tie(nullptr)->sync_with_stdio(false);
#endif
  int t;
  cin >> t;
  while (t--) cout << (mian() ? "YES" : "NO") << endl;
  return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3812kb

input:

3
2 1
1 2
3 4
RR
4 3
BB
3 2
1 2
2 3
1 1 1
RBR
1 1 1
BBB
3 3
1 2
2 3
3 1
1 1 1
RBR
1 1 1
BBB

output:

YES
NO
YES

result:

ok 3 lines

Test #2:

score: -100
Runtime Error

input:

25054
5 10
4 5
4 2
4 3
4 1
5 2
5 3
5 1
2 3
2 1
3 1
12 2 9 10 7
RRRBB
10 2 9 7 12
RRBRB
1 0
4
R
4
R
8 4
4 3
1 5
8 5
6 5
7 2 11 10 9 6 3 5
RBRBBRBR
7 2 10 11 6 5 3 9
RBRBBRBR
7 4
7 2
5 1
5 6
5 4
12 5 9 14 5 12 12
RRBRBRR
14 12 9 5 12 12 5
RBBRBRB
10 1
4 6
5 3 2 9 7 3 11 11 6 8
RRRBRRBBBR
5 3 2 3 7 9 1...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
NO
NO
YES
YES
YES
NO
YES
NO
YES
YES
NO
YES
YES
NO
YES
NO
YES
YES
YES
YES
NO
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
NO
YES
NO
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
NO
YES
NO
NO...

result: