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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#620392 | #7755. Game on a Forest | Saton | RE | 0ms | 0kb | C++20 | 2.4kb | 2024-10-07 17:55:37 | 2024-10-07 17:55:38 |
answer
///by Saton.
#include<bits/stdc++.h>
#define PI acos(-1)
#define fi first
#define se second
#define sz(a) ((int)a.size())
#define all(a) a.begin(), a.end()
#define LL long long
#define ll __int128
#define DD double double
#define LD long double
#define rep(i,a,b) for(LL i = (a);i <= (b);i ++)
#define lep(i,a,b) for(LL i = (a);i >= (b);i --)
#define FLUSH fflush(stdout)
using namespace std;
const int N = 1e5 + 10,mod = 1e9+7,P = 131;
LL n,m,k;
struct DSU {
std::vector<int> f;
std::vector<int> size;
DSU(int n) : f(n), size(n) {
std::iota(f.begin(), f.end(), 0);
std::fill(size.begin(), size.end(), 1);
}
int find(int x) {
while (x != f[x])
x = f[x] = f[f[x]];
return x;
}
void Union(int x, int y) {
if (find(x) == find(y))
return;
size[find(x)] += size[find(y)];
f[find(y)] = find(x);
}
int blockSize(int x) {
return size[find(x)];
}
};
int sg(int x) {
if (x == 0)
return 0;
return 2 - x % 2;
}
void solve() {
cin >> n >> m;
vector<vector<int>> e(n+1);
DSU dsu(n+1);
rep(i,1,m) {
int u,v;
cin >> u >> v;
e[u].push_back(v);
e[v].push_back(u);
}
int SG = 0;
rep(i,1,n) {
if(i == dsu.find(i)) {
SG ^= sg(dsu.blockSize(i));
}
}
int ans = 0;
vector<int> size(n+1,0);
function<void(int,int)> dfs = [&](int x,int fa) {
int tempSG = 0;
size[x] = 1;
for(int y : e[x]) {
if(y == fa) continue;
dfs(y,x);
tempSG ^= sg(size[y]);
size[x] += size[y];
}
tempSG ^= sg(dsu.blockSize(x) - size[x]);
//删点
if(SG^tempSG == 0) ans ++;
//删边
if(fa!=0 && SG^sg(size[x])^sg(dsu.blockSize(x) - size[x])==0) ans ++;
};
rep(i,1,n) {
if(i == dsu.find(i)) {
SG ^= sg(dsu.blockSize(i));
dfs(i,0);
SG ^= sg(dsu.blockSize(i));
}
}
cout << ans << '\n';
}
int main() {
ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
int T;
cin >> T;
while(T --) {
solve();
}
// solve();
return 0;
}
/* /\_/\
* (= ._.)
* / > \>
*/
詳細信息
Test #1:
score: 0
Runtime Error
input:
3 1 1 2