QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#619211#2440. Valentine's Dayuntitledtwo#AC ✓70ms3972kbC++17474b2024-10-07 13:30:532024-10-07 13:30:54

Judging History

This is the latest submission verdict.

  • [2024-10-07 13:30:54]
  • Judged
  • Verdict: AC
  • Time: 70ms
  • Memory: 3972kb
  • [2024-10-07 13:30:53]
  • Submitted

answer

#include <bits/stdc++.h>
using namespace std;
double a[10010];
int main()
{
	int T;
	scanf("%d", &T);
	while(T--)
	{
		int n;
		scanf("%d", &n);
		for(int i = 1; i <= n; i++)
			scanf("%lf", &a[i]);
		sort(a + 1, a + n + 1, greater<double>());
		double ans = a[1], prod = 1 - a[1];
		for(int i = 2; i <= n; i++)
		{
			if(prod - ans < 0)
				break;
			ans += a[i] * (prod - ans);
			prod *= (1 - a[i]);
		}
		printf("%.12lf\n", ans);
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 70ms
memory: 3972kb

input:

100
10
0.020874 0.180969 0.015588 0.043033 0.181293 0.033025 0.163341 0.104341 0.065442 0.129546
10
0.019357 0.210598 0.045487 0.051145 0.014579 0.135566 0.004401 0.008004 0.106695 0.056974
10
0.062679 0.216144 0.010137 0.031823 0.233062 0.042464 0.099544 0.140483 0.201337 0.045349
100
0.116404 0.19...

output:

0.398190071489
0.373683886459
0.410885362758
0.421374044378
0.419872971016
0.421062257019
0.420796858020
0.419890897576
0.419860393202
0.000099990100
0.000000000000
0.003341000000
0.003336000000
0.001427003306
0.003169000000
0.029231252961
0.061862431346
0.022757483568
0.015698496871
0.035934479901
...

result:

ok 100 numbers