QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#619045 | #5152. Circular Caramel Cookie | Rafat_Kabir | WA | 1ms | 3892kb | C++20 | 3.4kb | 2024-10-07 12:41:59 | 2024-10-07 12:42:01 |
Judging History
answer
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#include <time.h>
#include <cstdlib>
#include <ctime>
#include <cstdio>
#include <cstring>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <iostream>
using namespace __gnu_pbds;
using namespace std;
template <class T>
using Tree =
tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// to erase in multiset-> less_equal<T> and
// s.erase(s.find_by_order(s.order_of_key(x)))
// lower_bound(x)=>(cannot use the stl lower_bound function)
// ll idx = s.order_of_key(x)
// if(idx == s.size()) -> no lower_bound
// else lb = *s.find_by_order(idx) // as 0-indexing
// idx-1 will give highest value which is strictly less than x
// for upper_bound->do the same with (x+1)
typedef long long ll;
typedef long double ld;
typedef pair<int,int> p32;
typedef pair<ll,ll> p64;
typedef tuple<ll, ll, ll> t64;
typedef vector<t64> vt64;
typedef vector<vt64> vvt64;
typedef pair<double,double> pdd;
typedef vector<ll> v64;
typedef vector<int> v32;
typedef vector<vector<int> > vv32;
typedef vector<vector<ll> > vv64;
typedef vector<vector<p64> > vvp64;
typedef vector<p64> vp64;
typedef vector<p32> vp32;
typedef vector<vector<p32> > vvp32;
typedef vector<bool> vb;
ll mod = 1e9+7, MOD = 998244353;
double eps = 1e-12;
// #define forn(i,e) for(ll i = 0; i < e; i++)
#define FOR(s, e, i) for(int i = s; i <= e; i++)
// #define rforn(i,s) for(ll i = s; i >= 0; i--)
#define ROF(s ,e, i) for(int i = s; i >= e; i--)
#define coutAll(A) for(auto asdafas : A) cout << asdafas << " "; cout << "\n";
#define foutAll(A) for(auto asdafas : A) fout << asdafas << " "; cout << "\n";
#define cinAll(A) for(auto &asdafas : A) cin >> asdafas;
#define finAll(A) for(auto &asdafas : A) fin >> asdafas;
#define minpq priority_queue<ll, v64, greater<ll>>
#define maxpq priority_queue<ll>
#define ln "\n"
#define dbg(x) cout<<#x<<" = "<<x<<ln
#define mp make_pair
#define mt make_tuple
#define pb push_back
#define fi first
#define se second
ll inf = LLONG_MAX;
#define fast_cin() ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(x) ((ll)(x).size())
#define yes cout<<"YES\n"
#define no cout<<"NO\n"
using namespace std;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vector<ll>> vvll;
typedef pair<ll, ll> pll;
typedef pair<ll, ll> pii;
//#define MAXN 1000000
const ll maxN = 1e9;
void solve(int it)
{
ll n;
cin >> n;
ll l = 0, r = 1e5;
double ans = 0;
auto ok = [&](ll radius_sq)->bool{
ll cnt = 0;
FOR(1, radius_sq, i){
int Y_sq = radius_sq-i*i;
if(Y_sq > 0) cnt += sqrt(Y_sq);
}
cnt *= 4;
return cnt > n;
};
while(l <= r){
ll mid = (l + r) / 2;
// cout << mid << "->";
if(ok(mid)){
ans = sqrt(mid);
r = mid - 1;
}else{
l = mid + 1;
}
}
cout << fixed << setprecision(20) << ans;
}
int main()
{
// fast_cin();
ll t = 1;
// cin >> t;
for(int it=1; it<=t; it++)
{
//cout << "Case " << it << ": ";
solve(it);
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3708kb
input:
11
output:
2.23606797749978980505
result:
ok found '2.2360680', expected '2.2360680', error '0.0000000'
Test #2:
score: 0
Accepted
time: 0ms
memory: 3872kb
input:
59
output:
5.00000000000000000000
result:
ok found '5.0000000', expected '5.0000000', error '0.0000000'
Test #3:
score: 0
Accepted
time: 0ms
memory: 3892kb
input:
1
output:
1.41421356237309514547
result:
ok found '1.4142136', expected '1.4142136', error '0.0000000'
Test #4:
score: 0
Accepted
time: 0ms
memory: 3868kb
input:
2
output:
1.41421356237309514547
result:
ok found '1.4142136', expected '1.4142136', error '0.0000000'
Test #5:
score: 0
Accepted
time: 0ms
memory: 3884kb
input:
3
output:
1.41421356237309514547
result:
ok found '1.4142136', expected '1.4142136', error '0.0000000'
Test #6:
score: 0
Accepted
time: 0ms
memory: 3872kb
input:
4
output:
2.23606797749978980505
result:
ok found '2.2360680', expected '2.2360680', error '0.0000000'
Test #7:
score: -100
Wrong Answer
time: 1ms
memory: 3872kb
input:
1000000000
output:
228.32214084490360050950
result:
wrong answer 1st numbers differ - expected: '17841.8813190', found: '228.3221408', error = '0.9872030'