QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#616823#5414. Stop, Yesterday Please No MoreGodwangAC ✓91ms48636kbC++237.2kb2024-10-06 12:16:212024-10-06 12:16:21

Judging History

你现在查看的是最新测评结果

  • [2024-10-06 12:16:21]
  • 评测
  • 测评结果:AC
  • 用时:91ms
  • 内存:48636kb
  • [2024-10-06 12:16:21]
  • 提交

answer

#include <iostream>
using namespace std;
#include <set>
#include <algorithm>
#include <cmath>
#include <map>
#include <cstdio>
#include <string>
#include <cstring>
#include <string.h>
#include <stdlib.h>
#include <iomanip>
#include <fstream>
#include <stdio.h>
#include <stack>
#include <queue>
#include <ctype.h>
#include <vector>
#include <random>
#include<list> 
#define ll long long
#define ull unsigned long long
#define pb push_back
#define rep(i, a, n) for (int i = a; i <= n; i++)
#define per(i, a, n) for (int i = n; i >= a; i--)
#define pii pair<int, int>
#define pli pair<ll, int>
#define pil pair<int, ll>
#define pll pair<ll, ll>
#define lowbit(x) ((x)&(-x))
ll extend_gcd(ll a, ll b, ll &x, ll &y)
{
    if (b == 0)
    {
        x = 1;
        y = 0;
        return a;
    }
    ll d = extend_gcd(b, a % b, y, x);
    y -= a / b * x;
    return d;
}
ll fastpow(ll a, ll n, ll mod)
{
    ll ans = 1;
    a %= mod;
    while (n)
    {
        if (n & 1)
            ans = (ans * a) % mod; //% mod
        a = (a * a) % mod;         //% mod
        n >>= 1;
    }
    return ans;
}

inline void write(__int128 x)
{
    if (x > 9)
    {
        write(x / 10);
    }
    putchar(x % 10 + '0');
}
__int128 sqrt(__int128 m)
{
    __int128 leftt = 0, rightt = ((__int128)1) << 51, ret = -1, mid;
    while (leftt < rightt)
    {
        mid = (leftt + rightt) / 2;
        if (mid * mid > m)
        {
            rightt = mid;
        }    
        else
        {
            leftt = mid + 1;
            ret = mid;
        }
    }
    return ret;
}

const double eps = 1e-6;
int sgn(double x)
{
    if(fabs(x)<eps)
    {
        return 0;
    }
    else return x<0?-1:1;
}

struct Point
{
    double x,y;
    Point()
    {

    }
    Point(double x,double y):x(x),y(y)
    {

    }
    Point operator + (Point B)
    {
        return Point(x+B.x,y+B.y);
    }
    Point operator - (Point B)
    {
        return Point(x-B.x,y-B.y);
    }
    bool operator == (Point B)
    {
        return sgn(x-B.x)==0&&sgn(y-B.y)==0;
    }
    bool operator < (Point B)
    {
        return sgn(x-B.x)<0||(sgn(x-B.x)==0&&sgn(y-B.y)<0);
    }
};
typedef Point Vector;
double Cross(Vector A,Vector B)//叉积
{
    return A.x*B.y-A.y*B.x;
}
double Distance(Point A,Point B)
{
    return hypot(A.x-B.x,A.y-B.y);
}
int Convex_hull(Point *p,int n,Point *ch)
{
    n=unique(p,p+n)-p;
    sort(p,p+n);
    int v=0;

    for(int i=0;i<n;i++)
    {
        while (v>1&&sgn(Cross(ch[v-1]-ch[v-2],p[i]-ch[v-1]))<=0)
        {
            v--;
        }
        ch[v++]=p[i];
    }

    int j=v;

    for(int i=n-2;i>=0;i--)
    {
        while (v>j&&sgn(Cross(ch[v-1]-ch[v-2],p[i]-ch[v-1]))<=0)
        {
            v--;
        }
        ch[v++]=p[i];
    }
    if(n>1)
    {
        v--;
    }
    return v;
}

int kmp(string s, string p)
{
    int ans = 0, lastt = -1;
    int lenp = p.size();
    vector<int > Next(lenp+3,0);
    rep(i, 1, lenp - 1)
    {
        int j = Next[i];
        while (j && p[j] != p[i])
        {
            j = Next[j];
        }
        if (p[j] == p[i])
        {
            Next[i + 1] = j + 1;
        }
        else
        {
            Next[i + 1] = 0;
        }
    }
    int lens = s.size();
    int j = 0;
    rep(i, 0, lens - 1)
    {
        while (j && s[i] != p[j])
        {
            j = Next[j];
        }
        if (s[i] == p[j])
        {
            j++;
        }
        if (j == lenp)
        {
            ans++;
        }
    }
    return ans;
}

int dir[4][2] =
    {
        {-1, 0}, {0, 1}, {1, 0}, {0, -1}}; // 左右上下
// int dir[8][2]={
//         {-1, 0}, {0, 1}, {1, 0}, {0, -1},{-1,-1},{-1,1},{1,-1},{1,1}
// };
        
#define endl '\n'//交互题请删除本行
const ll inf = 1000000000000000000ll;
const ll mod1 = 998244353ll, P1 = 131, mod2 = 1e9 + 7ll, P2 = 13331;
ll inverse(ll x)
{
    return fastpow(x,mod1-2,mod1);
}

const int N = 1e4 + 10, M = 1e6 + 10;

///////////////////////////////////

int tt;

int n,m,k;

int shang,xia,zuo,you;

int d[N][N];

///////////////////////////////////

bool judge()
{
    if(shang>n||zuo>m||xia<1||you<1||shang>xia||zuo>you)
    {
        return 0;
    }
    return 1;
}

void solve(int x1,int x2,int y1,int y2)
{
    d[x1][y1]++;
    d[x2+1][y1]--;
    d[x1][y2+1]--;
    d[x2+1][y2+1]++;
}

///////////////////////////////////

void init()
{
    shang=1;
    xia=n;
    zuo=1;
    you=m;
    rep(i,0,n+1)
    {
        rep(j,0,m+1)
        {
            d[i][j]=0;
        }
    }
}

///////////////////////////////////

int main()
{
    ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);//交互题请删除本行
    //freopen("ain.txt", "r", stdin); freopen("aout.txt", "w", stdout);
    
    cin>>tt;
    while (tt--)
    {
        cin>>n>>m>>k;
        init();
        string s;
        cin>>s;
        int lens=s.size();
        s=' '+s;
        bool flag=1;
        int nowshu=0,nowheng=0;
        rep(i,1,lens)
        {
            if(s[i]=='D')
            {
                nowshu--;
            }
            else if(s[i]=='U')
            {
                nowshu++;
            }
            else if(s[i]=='R')
            {
                nowheng--;
            }
            else
            {
                nowheng++;
            }
            shang=max(shang,1+nowshu);
            xia=min(xia,n+nowshu);
            zuo=max(zuo,1+nowheng);
            you=min(you,m+nowheng);
            //
            //cout<<shang<<" "<<xia<<" "<<zuo<<" "<<you<<endl;
            flag=judge();
            if(flag==0)
            {
                break;
            }
        }

        if(flag==0)
        {
            if(k==0)
            {
                cout<<n*m<<endl;
            }
            else
            {
                cout<<0<<endl;
            }
            continue;
        }

        map<pii,bool > ma;
        solve(shang,xia,zuo,you);
        ma[{0,0}]=1;
        int shu=0,heng=0;
        rep(i,1,lens)
        {
            if(s[i]=='U')
            {
                shu--;
            }
            else if(s[i]=='D')
            {
                shu++;
            }
            else if(s[i]=='L')
            {
                heng--;
            }
            else
            {
                heng++;
            }
            if(ma.count({shu,heng})==0)
            {
                ma[{shu,heng}]=1;
                solve(shang+shu,xia+shu,zuo+heng,you+heng);
            }
        }
        int ans=0;
        int now=(xia-shang+1)*(you-zuo+1);
        //
        //cout<<now<<endl;

        rep(i,1,n)
        {
            rep(j,1,m)
            {
                d[i][j]+=d[i-1][j]+d[i][j-1]-d[i-1][j-1];
                //
                //cout<<d[i][j]<<" ";
                if(now-d[i][j]==k)
                {
                    ans++;
                }
            }
            //
           // cout<<endl;
        }
        //
        //cout<<shang<<" "<<xia<<" "<<zuo<<" "<<you<<endl;
        cout<<ans<<endl;
    }
    


    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3736kb

input:

3
4 5 3
ULDDRR
4 5 0
UUUUUUU
4 5 10
UUUUUUU

output:

2
20
0

result:

ok 3 number(s): "2 20 0"

Test #2:

score: 0
Accepted
time: 7ms
memory: 8056kb

input:

1060
19 12 0
UDLDDUUUUDDDLLRDUDUURULUUUDRDUDRDRLRLRLULULLLDLDDRLUUUURUUUDDRLLRUUUDULURUULLRDRLRDDURDUUURRRLURLRUULRRUDURDLUUURDLURDDLUUURDDRLLURRDLRUDLRDRLLRRDRDDLDRURRRLUDULLLRUUDLRRURRDLLRRRDLLRDDDLRLRURURDDDL
11 1 0
UR
3 18 33
UDRLR
17 11 132
RLDRDLDRUU
6 10 13
UULUDDLRDLUUDLDD
1 15 0
D
6 20 50
D...

output:

228
11
20
99
18
15
34
240
15
0
0
13
14
18
26
16
1
19
108
8
2
2
3
7
0
30
16
21
0
8
10
9
15
5
320
11
7
3
0
0
12
0
11
0
0
14
0
22
36
51
23
7
6
4
2
48
28
8
63
22
49
13
10
4
108
10
18
44
0
15
9
0
4
30
14
99
105
10
14
17
0
66
10
11
28
52
34
56
33
14
56
90
14
0
121
3
48
30
36
13
0
30
7
8
3
11
16
45
20
34
0...

result:

ok 1060 numbers

Test #3:

score: 0
Accepted
time: 0ms
memory: 42900kb

input:

1
1000 1000 979065
DDUULULUDULLULLDLUULURRLDURLRDLRRUURUUUDLRLUUDUUDUDLLDDDULU

output:

958416

result:

ok 1 number(s): "958416"

Test #4:

score: 0
Accepted
time: 4ms
memory: 42616kb

input:

1
1000 1000 943471
LRLDLURLDLRDRDUULULRDDLLRURDUURLLDDLDLDDLLLUUURLDRUDRLLUUUUUDLUUDLURURRDLRLRRRLULRRULURLRRDLDRLUDRRLDDLUDRRLLUDLLLRDULRRRRLDUUDRDLULUUUUDRRDULUDLLUUDLDURDRRLRRLDRLDDRURURLUULRRLDLLRLRDRRUULDLDLULLDLLRULLRUULURDURRLUUDUULLULDLRUDDLRLRLLUDDDLLLUDRRLDDULRRURRDURDDRDLLULRLULURLRDLLURD...

output:

889224

result:

ok 1 number(s): "889224"

Test #5:

score: 0
Accepted
time: 91ms
memory: 48636kb

input:

1
1000 1000 315808
LLRURURRDDDULLDDUDRDLRLLLDDDLUDRDURLDULRLRULUUDLUULUUDULLLLDDURLDUULUUDLLDLLDRUDUULRLLRLRUURLRLULLDDLLDUDLLRUUDRLDLUULDLLDRRRURDULLDRRRDURURDRLDURURUDLURLDURRLRRUDUDURDRLRRRDLRRURLURUDRRLDLRULLDLUURDURLURLLRDLRDRUURURDRUDUUUDLRRLUDLUUDUDDRRDUULUUDDRLLULDUUDRURRDRLULRLULDURLURUDLLD...

output:

426

result:

ok 1 number(s): "426"

Test #6:

score: 0
Accepted
time: 6ms
memory: 42900kb

input:

1
1000 1000 986018
LLULDRRRDDURRUDRUURRRDDLUUDUULRULRDULLD

output:

972180

result:

ok 1 number(s): "972180"

Test #7:

score: 0
Accepted
time: 4ms
memory: 42868kb

input:

1
1000 1000 945431
DDRRURUUDLDULLDLDDLRULDLLDDRRLUDRLUURRLDRDLURUURRRRLRURLURULLLDRDDDRRRLDLDRLRDDUURRURDDDLRUURLUURLRDUDDDLLDUURLDLUDLLRRDUUDRLUULLUULDLURRUDLUURLRLRURDUDRRRDRLRUDLLLLURLULRLRLRRDDUDLRLDUUUULUDLLURRLURRDLRURRRULDDLLLRLRDLUDLLDDRULDUULRDDUUDDUDLURDULLDUDDLULRULDRLDDULDULLUDLULUDRURRR...

output:

893000

result:

ok 1 number(s): "893000"

Test #8:

score: 0
Accepted
time: 83ms
memory: 45676kb

input:

1
1000 1000 460035
RDDUURDULDDLDDLDDLDRRULLRLUURLURRRDRUDDDRDLDLDULUDLRLLRRLRRURRRDLRLUDRDURULDRRDDDDDDLRLDULUULDUDRLLUUUURUUDRURLRRULDRDRUUUUULULRURDDRLRULLLRDRRULUDDUDDLLLRDRUULUUDDRLURDLDURRDLRRLDRRUDLUULRDLURULLDLRLLDDURDUDLDULDLLRULRDLRLUULLUDRUDDDLRRDULULLRUURLUURRLLLLRLDRURLLRLDRRDDDRLUUUUDUL...

output:

417

result:

ok 1 number(s): "417"

Test #9:

score: 0
Accepted
time: 4ms
memory: 42588kb

input:

1
1000 1000 992010
LLLLLDLDRRLUDRR

output:

1999

result:

ok 1 number(s): "1999"

Test #10:

score: 0
Accepted
time: 6ms
memory: 42756kb

input:

1
1000 1000 919600
LLDLRUDRLURRUDRDRRDLRUDLRRRUUULDLDURDDDRUURRRLLURULDRLRLULLULDRULULRLRRRURLDDDRUUULUDLLLLRRLLRDDRDULUDLRLRLDRLUDUDURRULUULLDULUULDLLDRDULUDLDULDDUULDDRRURDRDULRRLDRRDUURURRLUUUDRRLDRRDDLULRDDLDLLRLRLLLRULUUUURRRLDLRUDRRLRURDRLDULLLUDRULLDLDRRUUDLRRLLRLDDLUDLRLRRURUUDUULUDURDURRLUU...

output:

944

result:

ok 1 number(s): "944"

Test #11:

score: 0
Accepted
time: 65ms
memory: 44428kb

input:

1
1000 1000 804351
DLRLDLLLLUDRDURRLDDRRLRUULURURDDDRDLRUDDULRRLLULURDRUUDRURRLURRRDRURRDRLULRDLRRDRRDDUDLUDLDULRUURRLRUUDRLDDRDDUUDULUULUUUDLRURULLRDUUDDDRRLDRUDDUUDRURLRDRUDLRLDDRRLLRLRDUDDULLULRLLDDUDDDUULDULLRRULULDUUULUDRRDRLUDLRRDDUDLRRDDLDLDRUULRRRRRLRLULLRDDRDDDULDRRURUDDLURLRLURLRDRULUDULUU...

output:

640000

result:

ok 1 number(s): "640000"