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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#612288#9449. New School Termucup-team896#WA 2ms3996kbC++203.0kb2024-10-05 10:16:212024-10-05 10:16:21

Judging History

你现在查看的是最新测评结果

  • [2024-10-05 10:16:21]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3996kb
  • [2024-10-05 10:16:21]
  • 提交

answer

#include <bits/stdc++.h>

#define rep(i, j, k) for (int i = (j); i <= (k); ++i)
#define per(i, j, k) for (int i = (j); i >= (k); --i)
#define SZ(v) int((v).size())
#define ALL(v) (v).begin(),(v).end()
#define fi first
#define se second
using ll = long long;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;

template<class T>inline void chkmn(T &x, T y) { if (y < x) x = y; }
template<class T>inline void chkmx(T &x, T y) { if (y > x) x = y; }

using namespace std;

template <int P>
class mod_int {
  using Z = mod_int;

private:
  static int mo(int x) { return x < 0 ? x + P : x; }

public:
  int x;
  int val() const { return x; }
  mod_int() : x(0) {}
  template <class T>
  mod_int(const T &x_) : x(x_ >= 0 && x_ < P ? static_cast<int>(x_) : mo(static_cast<int>(x_ % P))) {}
  bool operator==(const Z &rhs) const { return x == rhs.x; }
  bool operator!=(const Z &rhs) const { return x != rhs.x; }
  Z operator-() const { return Z(x ? P - x : 0); }
  Z pow(long long k) const {
    Z res = 1, t = *this;
    while (k) {
      if (k & 1) res *= t;
      if (k >>= 1) t *= t;
    }
    return res;
  }
  Z &operator++() {
    x < P - 1 ? ++x : x = 0;
    return *this;
  }
  Z &operator--() {
    x ? --x : x = P - 1;
    return *this;
  }
  Z operator++(int) {
    Z ret = x;
    x < P - 1 ? ++x : x = 0;
    return ret;
  }
  Z operator--(int) {
    Z ret = x;
    x ? --x : x = P - 1;
    return ret;
  }
  Z inv() const { return pow(P - 2); }
  Z &operator+=(const Z &rhs) {
    (x += rhs.x) >= P && (x -= P);
    return *this;
  }
  Z &operator-=(const Z &rhs) {
    (x -= rhs.x) < 0 && (x += P);
    return *this;
  }
  Z &operator*=(const Z &rhs) {
    x = 1ULL * x * rhs.x % P;
    return *this;
  }
  Z &operator/=(const Z &rhs) { return *this *= rhs.inv(); }
#define setO(T, o)                                 \
  friend T operator o(const Z &lhs, const Z &rhs) {\
    Z res = lhs;                                   \
    return res o## = rhs;                          \
  }
  setO(Z, +) setO(Z, -) setO(Z, *) setO(Z, /)
#undef setO
};
const int P = 998244353;
using Z = mod_int<P>;

struct mat {
  Z a[50][50];
  friend mat operator*(mat x, mat y) {
    mat res;
    rep (i, 0, 49) rep (k, 0, 49) {
      if (!x.a[i][k].val()) continue;
      rep (j, 0, 49) res.a[i][j] += x.a[i][k] * y.a[k][j];
    }
    return res;
  }
} e, pw[30];

int id(int x, int y) {
  return 7 * x + y;
}

void work() {
  int n;
  cin >> n;
  mat res; res.a[0][id(0, 0)] = 1;
  per (i, 29, 0) if (n >> i & 1) res = res * pw[i];
  cout << res.a[0][id(6, 6)].val() << '\n';
}

int main() {
  cin.tie(nullptr) -> ios::sync_with_stdio(false);
  rep (i, 0, 6) rep (j, 0, 6) {
    e.a[id(i, j)][id(min(i + 1, 6), j)] += 1;
    e.a[id(i, j)][id(i, min(j + 1, 6))] += 1;
    e.a[id(i, j)][id(i, j)] += 50;
  }
  pw[0] = e;
  rep (i, 1, 29) pw[i] = pw[i - 1] * pw[i - 1];
  int t; cin >> t;
  while (t--) work();
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 2ms
memory: 3996kb

input:

2 4
1 3
2 4
1 4
1 2

output:

0
0

result:

wrong answer The size of S must be 2N.