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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#61184 | #4828. Four Plus Four | JohnAlfnov | 0 | 0ms | 0kb | C++14 | 2.2kb | 2022-11-11 10:57:00 | 2022-11-11 10:57:02 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
char s0[100005][15],s1[100005][15],s2[100005][15];
char t1[100005][15],t2[100005][15];
int cnt[11144],tnc[11144];
vector<int>g[30005];
int deg[300005];
int vv[30005];
int f[4005][4005];
int wz[30005][3];
int main(){
string florr;
cin>>florr;
int n;
cin>>n;
for(int i=1;i<=n;++i){
if(florr[0]=='p')scanf("%s",s0[i]+1);
else scanf("%s%s",s1[i]+1,s2[i]+1);
}
int n0,n1;
cin>>n0;
for(int i=1;i<=n0;++i)scanf("%s",t1[i]+1);
cin>>n1;
for(int i=1;i<=n1;++i)scanf("%s",t2[i]+1);
for(int i=1;i<=n0;++i){
for(int j=1;j<=8;++j)++cnt[t1[i][j]];
for(int j=1;j<=n1;++j){
int flag=1;
for(int l=1;l<=4;++l){
++tnc[t2[j][l]];
if(tnc[t2[j][l]]>cnt[t2[j][l]]){
flag=0;
break;
}
}
if(flag){
g[i].emplace_back(j);
++deg[j];
}
for(int l=1;l<=4;++l)tnc[t2[j][l]]=0;
}
for(int j=1;j<=8;++j)--cnt[t1[i][j]];
}
for(int i=1;i<=n0;++i)vv[i]=i;
sort(vv+1,vv+n0+1,[&](int a,int b){
return g[a].size()<g[b].size();
});
for(int x=1;x<=n0;++x){
int i=vv[x];
if(g[i].size()<3)continue;
sort(g[i].begin(),g[i].end(),[&](int a,int b){
return deg[a]<deg[b];
});
int flag=0,sz=g[i].size();
for(int A=0;A<sz&&!flag;++A)for(int B=A;B<sz&&!flag;++B){
int a=g[i][A],b=g[i][B];
if(f[a][b])continue;
for(int C=B;C<sz;++C){
int c=g[i][C];
if(f[a][c]||f[b][c])continue;
wz[i][0]=a,wz[i][1]=b,wz[i][2]=c;
f[a][b]=f[b][a]=f[b][c]=f[c][b]=f[c][a]=f[a][c]=i;
flag=1;
break;
}
}
assert(flag);
}
map<string,int>m1,m2;
for(int i=1;i<=n0;++i){
string st;
for(int j=1;j<=8;++j){
st+=t1[i][j];
}
m1[st]=i;
}
for(int i=1;i<=n1;++i){
string st;
for(int j=1;j<=4;++j){
st+=t2[i][j];
}
m2[st]=i;
}
if(florr[0]=='p'){
for(int i=1;i<=n;++i){
string st;
for(int j=1;j<=8;++j)st+=s0[i][j];
int w=m1[st];
printf("%s %s %s\n",t2[wz[w][0]]+1,t2[wz[w][1]]+1,t2[wz[w][2]]+1);
}
}else{
for(int i=1;i<=n;++i){
string st1,st2;
for(int j=1;j<=4;++j)st1+=s1[i][j],st2+=s2[i][j];
int A=m2[st1],B=m2[st2];
printf("%s\n",t1[f[A][B]]+1);
}
}
return 0;
}
详细
Test #1:
score: 0
Stage 1: Program answer Dangerous Syscalls
input:
password 2 password couthier 28558 aardvark aardwolf aasvogel abacuses abalones abampere abandons abapical abasedly abashing abatable abatises abattoir abbacies abbatial abbesses abdicate abdomens abdomina abducens abducent abducing abducted abductee abductor abelmosk aberrant abetment abettals abet...