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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#609817 | #9412. Stop the Castle | Kanate# | WA | 2ms | 12780kb | C++14 | 4.8kb | 2024-10-04 14:08:15 | 2024-10-04 14:08:17 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
typedef long long ll ;
const int INF = 1e9 + 7;
const int M = 1e6 + 7;
const int N = 1e5 + 7;
int n , m , s , t , cnt =1 ;
int T;
int lv[N],cur[N];
struct edge{
int v , nex , flow;
}e[M];int head[N];
int X[N],Y[N];
int fx[N],fy[N];
bool bfs(){
memset(lv,-1,sizeof lv);
lv[s] = 0 ;
memcpy(cur,head,sizeof cur);
queue<int>q;
q.push(s);
while(!q.empty()){
int x = q.front();
q.pop();
for(int i = head[x];i;i = e[i].nex){
int v = e[i].v;
int val = e[i].flow;
if(val > 0 && lv[v] == -1){
lv[v] = lv[x] + 1;
q.push(v);
}
}
}
return lv[t] != -1;
}
int dfs(int x=s,int flow = INF){
if(x==t) return flow;
int rmn = flow;
for(int i=cur[x];i && rmn;i=e[i].nex){
cur[x] = i;
int v = e[i].v;
int val = e[i].flow;
if(val > 0 && lv[v] == lv[x] + 1){
int c = dfs(v,min(val,rmn));
rmn -= c;
e[i].flow -= c;
e[i^1].flow += c;
}
}
return flow - rmn;
}
void add(int u,int v,int flow){
e[++cnt].v = v;
e[cnt].nex = head[u];
head[u] = cnt;
e[cnt].flow = flow;
}
void add_edge(int u,int v,int flow){
//cout <<"ADD " << u << " " << v << " " << flow << endl;
add(u,v,flow);
add(v,u,0);
}
vector<int>h,r;
unordered_map<int,int> recal_R;
unordered_map<int,int> recal_H;
int pd[2001][2001];
int id[2001][2001];
struct wqweqweq{
int x , y;
}qwq[M];
int mx,my;
int tot = 0 ;
int GET_id(int x,int y){
return (x-1) * (my+1) + y;
}
void print(){
for(int i=1;i<=mx;i++){
int las = - 1;
for(int j=1;j<=my;j++){
if(pd[i][j] == 1) {
if(las == -1) las = j;
else {
pd[i][j-1] = 3;
las = j;
}
}
if(pd[i][j] == 2 || pd[i][j] == 3){
las = -1;
}
}
}
for(int j = 1;j<=my;j++){
int las = - 1;
for(int i=1;i<=mx;i++){
if(pd[i][j] == 1){
if(las==-1) las = i;
else {
pd[i-1][j] = 3;
las = i;
}
}
if(pd[i][j] == 2 || pd[i][j] == 3){
las = -1;
}
}
}
for(int i=1;i<=mx;i++)
for(int j=1;j<=my;j++)
if(pd[i][j] == 3){
cout << h[i-1] << " " << r[j-1] << endl;
}
}
map<pair<int,int>,pair<int,int>>nowmp;
void solve(){
nowmp.clear();
int ans = 0 ;
for(int i=1;i<=mx;i++){
int las = - 1;
for(int j=1;j<=my;j++){
if(pd[i][j] == 1) {
if(las == -1) las = j;
else {
if(las == j-1){
cout << -1 << endl;
return ;
}
++ tot;
qwq[tot] = {i,j};
ans ++ ;
for(int k= las+1;k<=j-1;k++) id[i][k] = tot;
add_edge(0,tot,1);
}
}
if(pd[i][j] == 2){
las = -1;
}
}
}
t = ++ tot;
for(int j = 1;j<=my;j++){
int las = - 1;
for(int i=1;i<=mx;i++){
if(pd[i][j] == 1){
if(las==-1) las = i;
else {
if(las == i-1) {
cout << -1 << endl;
return ;
}
++ tot;
ans ++ ;
for(int k=las+1;k<=i-1;k++)
if(id[k][j]){
add_edge(id[k][j],tot,1);
nowmp[make_pair(id[k][j],tot)] = make_pair(k,j);
}
add_edge(tot,t,1);
}
}
if(pd[i][j] == 2){
las = - 1;
}
}
}
while(bfs()){
// cout << ans << endl;
ans -= dfs();
}
for(int i = head[0];i;i=e[i].nex) {
int v = e[i].v;
for(int j=head[v];j;j=e[j].nex){
int w = e[j].v;
if(w==0 || e[j].flow==1) continue;
pair<int,int> nod = nowmp[make_pair(v,w)];
pd[nod.first][nod.second] = 3;
}
}
cout << ans << endl;
print();
for(int i=0;i<=tot;i++) head[i] = 0 ;
for(int i=1;i<=mx;i++)
for(int j=1;j<=my;j++)
pd[i][j] = id[i][j] = 0 ;
tot = 0;
//cout << ans << endl;
}
signed main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> T;
while(T-->0){
cin >> n ;
h.clear();recal_R.clear();
r.clear();recal_H.clear();cnt = 1;
for(int i=1;i<=n;i++){
int x , y;
cin >> x >> y;
X[i] = x;
Y[i] = y;
h.emplace_back(x);
r.emplace_back(y);
}
cin >> m;
for(int i=1;i<=m;i++){
cin >> fx[i] >> fy[i];
h.emplace_back(fx[i]);
r.emplace_back(fy[i]);
}
sort(h.begin(),h.end());
sort(r.begin(),r.end());
r.resize(unique(r.begin(),r.end())-r.begin());
h.resize(unique(h.begin(),h.end())-h.begin());
int rs = (int)r.size() - 1;
int hs = (int)h.size() - 1;
for(int i=0;i<rs;i++)
if(r[i]+1 != r[i+1]) r.emplace_back(r[i]+1);
for(int i=0;i<hs;i++)
if(h[i]+1 != h[i+1]) h.emplace_back(h[i]+1);
sort(h.begin(),h.end());
sort(r.begin(),r.end());
for(int i=0;i<r.size();i++)
recal_R[r[i]] = i+1;
my = (int)r.size() ;
for(int i=0;i<h.size();i++)
recal_H[h[i]] = i+1;
mx = (int)h.size() ;
for(int i=1;i<=n;i++)
pd [recal_H[X[i]]][recal_R[Y[i]]] = 1;
for(int i=1;i<=m;i++)
pd [recal_H[fx[i]]][recal_R[fy[i]]] = 2;
solve();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 2ms
memory: 12780kb
input:
4 7 1 3 6 6 4 7 2 1 6 3 4 1 2 6 3 3 4 6 4 3 1 2 1 1 2 2 0 3 1 1 1 3 3 3 1 1 2 3 1 1 1 3 2 3 0
output:
2 2 3 4 6 0 1 2 3 -1
result:
ok ok 4 cases (4 test cases)
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 12700kb
input:
21 11 3 5 18 6 19 12 27 48 28 38 30 12 33 18 42 18 43 38 45 46 48 34 3 2 6 24 4 41 45 15 11 6 15 27 16 9 16 14 16 48 19 26 25 12 27 26 28 4 31 40 32 6 33 50 37 50 46 11 50 29 17 1 49 4 9 9 15 9 22 11 31 11 46 14 28 17 5 17 49 18 43 20 31 30 46 33 11 33 33 34 15 36 6 47 10 2 16 46 36 30 11 7 34 7 41 ...
output:
3 29 12 41 18 42 38 5 16 13 16 47 26 26 31 6 36 50 0 1 42 10 0 1 43 31 5 1 10 1 38 33 47 43 44 44 46 0 5 10 1 27 41 29 40 30 15 44 35 1 32 12 0 0 0 0 6 12 40 23 10 23 45 29 33 34 46 35 34 0 3 20 31 34 17 43 32 0 -1 -1 -1
result:
wrong answer Participant does not find an answer but the jury finds 3 (test case 20)