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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#60596 | #2544. Flatland Currency | 12345678 | RE | 3ms | 3348kb | C++14 | 2.6kb | 2022-11-05 17:21:01 | 2022-11-05 17:21:02 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define mp make_pair
#define inf 1e18
#define pii pair <int, int>
const int mod = 1e9 + 7;
int read () {
int x = 0, f = 1;
char ch = getchar ();
while (ch < '0' || ch > '9') {
if (ch == '-') f = -1;
ch = getchar ();
}
while (ch >= '0' && ch <= '9') {
x = x * 10 + ch - '0';
ch = getchar ();
}
return x * f;
}
void write (int x) {
if (x < 0) x = -x, putchar ('-');
if (x >= 10) write (x / 10);
putchar (x % 10 + '0');
}
int quickmod (int x, int y) {
int Ans = 1;
while (y) {
if (y & 1) Ans = (Ans * x) % mod;
x = (x * x) % mod;
y >>= 1;
}
return Ans;
}
int n, m;
int a[100005];
vector <int> G[5];
int f[400005][5];
inline int get_val(int k, int x) {
if(!x) return 0;
if(x > (int)G[k].size()) return inf;
return G[k][x-1];
}
vector <int> Lst[5];
void solve(int k2, int k, int l, int r, int L, int R) {
if(l > r) return ;
int mid = (l + r) / 2, Mid = L;
f[Lst[k2][mid]][k] = inf;
for(int i = L; i <= min(mid, R); i++) {
int lst = mid - i;
if(f[Lst[k2][i]][k-1] + get_val(k, lst) < f[Lst[k2][mid]][k]) {
f[Lst[k2][mid]][k] = f[Lst[k2][i]][k-1] + get_val(k, lst);
Mid = i;
}
}
solve(k2, k, l, mid - 1, L, Mid), solve(k2, k, mid + 1, r, Mid, R);
}
signed main () {
// freopen (".in", "r", stdin);
// freopen (".out", "w", stdout);
n = read(), m = read();
int bas = m % 5;
m -= bas;
for(int i = 1; i <= n; i++) {
a[i] = read();
G[5-a[i]%5].push_back(a[i]);
}
for(int i = 0; i < 5; i++) {
sort(G[i].begin(), G[i].end());
for(int j = 1; j < (int)G[i].size(); j++) G[i][j] += G[i][j-1];
}
f[0][0] = 0;
for(int i = 1; i <= 4 * n; i++) f[i][0] = inf;
for(int i = 1; i < 5; i++) {
// for(int j = 0; j <= 4 * n; j++) {
// f[j][i] = inf;
// for(int k = 0; k <= j; k++) {
// int lst = (j - k + (i - 1)) / i;
// if(f[k][i-1] + get_val(i, lst) < f[j][i]) {
// f[j][i] = f[k][i-1] + get_val(i, lst);
// }
// }
// }
for(int j = 0; j < i; j++) Lst[j].clear();
for(int j = 0; j <= 4 * n; j++) Lst[j%i].push_back(j);
for(int j = 0; j < i; j++) solve(j, i, 0, (int)Lst[j].size() - 1, 0, (int)Lst[j].size() - 1);
}
int Ans = 0;
for(int i = 0; i <= 4 * n; i++) if(f[i][4] + i <= m) Ans = i;
write(Ans + bas), putchar('\n');
return 0;
}
/*
4 50
11 11 11 11
*/
详细
Test #1:
score: 100
Accepted
time: 3ms
memory: 3348kb
input:
5 57 9 14 31 18 27
output:
8
result:
ok answer is '8'
Test #2:
score: 0
Accepted
time: 2ms
memory: 3348kb
input:
4 50 11 11 11 11
output:
12
result:
ok answer is '12'
Test #3:
score: -100
Runtime Error
input:
100000 89648823509660 921733427 402270498 51157221 585477094 435728758 913951087 580580944 557082810 585086423 837912728 799129405 867009344 751591136 714946046 464999915 256043168 416678301 183246216 569365122 479031618 435168577 31068363 903791719 497652990 960987871 223120213 395437892 112869678 ...