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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#60562#2544. Flatland CurrencyenhWA 255ms17080kbC++142.9kb2022-11-05 15:42:352022-11-05 15:42:37

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-11-05 15:42:37]
  • 评测
  • 测评结果:WA
  • 用时:255ms
  • 内存:17080kb
  • [2022-11-05 15:42:35]
  • 提交

answer

#include <iostream>
#include <vector>
using namespace std ;

#define int long long
const int N = 4000005 , INF = 0x3f3f3f3f3f3f3f3f ;
int n , m , a[N] , b[N] ;

void ckin ( int &x , int y ) { x = min ( x , y ) ; }

vector < int > merge ( vector < int > a , vector < int > b ) {
	int n = a .size ( ) , m = b .size ( ) ;
	vector < int > c ( n + m - 1 ) ;
	for ( int &i : c ) i = INF ;
	static int x[N] , y[N] , z[N] ;
	for ( int i = 0 ; i < 12 ; ++ i ) {
		if ( i >= n ) break ;
		for ( int j = 0 ; j < 12 ; ++ j ) {
			if ( j >= m ) break ;
			int t1 = 0 , t2 = 0 , t3 = 0 ;
			for ( int k = i ; k < n ; k += 12 ) x [ t1 ++ ] = a [ k ] ;
			for ( int k = j ; k < m ; k += 12 ) y [ t2 ++ ] = b [ k ] ;
			for ( int k = t1 - 1 ; k ; -- k ) x [ k ] -= x [ k - 1 ] ;
			for ( int k = t2 - 1 ; k ; -- k ) y [ k ] -= y [ k - 1 ] ;
			int k1 = 1 , k2 = 1 ;
			while ( k1 < t1 && k2 < t2 ) {
				if ( x [ k1 ] < y [ k1 ] ) z [ ++ t3 ] = x [ k1 ++ ] ;
				else z [ ++ t3 ] = y [ k2 ++ ] ;
			}
			while ( k1 < t1 ) z [ ++ t3 ] = x [ k1 ++ ] ;
			while ( k2 < t2 ) z [ ++ t3 ] = y [ k2 ++ ] ;
			z [ 0 ] = x [ 0 ] + y [ 0 ] ;
			for ( int k = 1 ; k <= t3 ; ++ k ) z [ k ] += z [ k - 1 ] ;
			for ( int k = 0 ; k <= t3 ; ++ k ) ckin ( c [ k * 12 + i + j ] , z [ k ] ) ;
		}
	}
	return c ;
}

vector < int > solve ( int l , int r ) {
	if ( l == r ) {
		vector < int > f ( 5 ) ;
		for ( int i = 1 ; i < 5 ; ++ i ) f [ i ] = INF ;
		f [ 0 ] = 0 , f [ a [ l ] ] = b [ l ] ;
		return f ;
	}
	int mid = ( l + r ) >> 1 ;
	
//	vector < int > res = merge ( solve ( l , mid ) , solve ( mid + 1 , r ) ) ;
//	cout << " solve : " << l << " - " << r << " : " << mid << "\n" ;
//	int siz = res .size ( ) ;
//	cout << " siz : " << siz << "\n" ;
//	for ( int u : res ) cout << u << " " ;
//	puts ( "\n\n" ) ;
//	return res ;
	
	return merge ( solve ( l , mid ) , solve ( mid + 1 , r ) ) ;
}

int read ( ) {
	char ch = getchar ( ) ;
	int x = 0 ;
	while ( ch < '0' || ch > '9' )
		ch = getchar ( ) ;
	while ( ch >= '0' && ch <= '9' )
		x = x * 10 + ch - 48 , ch = getchar ( ) ;
	return x ;
}

signed main ( ) {
//	freopen ( "data.in" , "r" , stdin ) ;
//	freopen ( "data.out" , "w" , stdout ) ;
	cin >> n >> m ;
	int nn = 0 ;
	for ( int i = 1 ; i <= n ; ++ i ) {
		int x = read ( ) ;
		if ( x % 5 == 0 ) continue ;
		b [ ++ nn ] = ( x + 4 ) / 5 * 5 ;
		a [ nn ] = b [ nn ] - x ;
	}
	n = nn ;
	if ( ! n ) {
		cout << m % 5 << "\n" ;
		return 0 ;
	}
	
//	cout << " a : " ;
//	for ( int i = 1 ; i <= n ; ++ i ) printf ( "%3d" , a [ i ] ) ;
//	puts ( "" ) ;
//	cout << " b : " ;
//	for ( int i = 1 ; i <= n ; ++ i ) printf ( "%3d" , b [ i ] ) ;
//	puts ( "" ) ;
	
	vector < int > ans = solve ( 1 , n ) ;
	int siz = ans .size ( ) , res = 0 ;
	for ( int i = 0 ; i < siz ; ++ i )
		if ( ans [ i ] <= m ) res = i ;
	cout << res + m % 5 << "\n" ;
	return 0 ;
}

Details

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Test #1:

score: 100
Accepted
time: 4ms
memory: 11600kb

input:

5 57
9 14 31 18 27

output:

8

result:

ok answer is '8'

Test #2:

score: 0
Accepted
time: 1ms
memory: 11608kb

input:

4 50
11 11 11 11

output:

12

result:

ok answer is '12'

Test #3:

score: -100
Wrong Answer
time: 255ms
memory: 17080kb

input:

100000 89648823509660
921733427 402270498 51157221 585477094 435728758 913951087 580580944 557082810 585086423 837912728 799129405 867009344 751591136 714946046 464999915 256043168 416678301 183246216 569365122 479031618 435168577 31068363 903791719 497652990 960987871 223120213 395437892 112869678 ...

output:

1130

result:

wrong answer expected '200414', found '1130'