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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#604839 | #8761. 另一个计数问题 | Kanate# | AC ✓ | 1772ms | 113456kb | C++14 | 7.1kb | 2024-10-02 14:11:58 | 2024-10-02 14:11:59 |
Judging History
answer
#include<bits/stdc++.h>
#define int long long
#define mod 998244353
#define rep(i,j,k) for(int i=(j);i<=(k);i++)
#define per(i,j,k) for(int i=(j);i>=(k);i--)
using namespace std;
template<class T>void chkmax(T &a,T b){a=max(a,b);}
template<class T>void chkmin(T &a,T b){a=min(a,b);}
template<class T>T read(T &x)
{
x=0;T f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9'){x=x*10+(c^'0');c=getchar();}
return x*=f;
}
template<class T,class ...L>void read(T &x,L &...l){read(x),read(l...);}
template<class T>void write(T x)
{
if(x<0){putchar('-');x=-x;}
if(x>9){write(x/10);}putchar(x%10+'0');
}
template<class T>void write(T x,char c){write(x),putchar(c);}
int qpow(int a,int b)
{
int ans=1;
while(b)
{
if(b&1)ans=ans*a%mod;
b>>=1;a=a*a%mod;
}
return ans;
}
int inv(int x){return qpow(x,mod-2);}
int N,n;
int A,B,C,D,E,F,G;
int isprime(int x)
{
for(int i=2;i*i<=x;i++)
if(x%i==0)
return 0;
return 1;
}
int fa[10005];
int find(int n){return fa[n]==n?n:fa[n]=find(fa[n]);}
void bruteforce(int N)
{
rep(i,2,N)fa[i]=i;
rep(i,2,N)for(int j=2*i;j<=N;j+=i)
fa[find(i)]=fa[find(j)];
int ans=0;
rep(i,2,N-1)rep(j,i+1,N)if(find(i)==find(j))
ans=(i*j%mod+ans)%mod;
write(ans,'\n');
}
#define LL long long
#define V 1000005
const int pw6=inv(6);
const int pw2=inv(2);
namespace Min254 {
int prime[V], id1[V], id2[V], flag[V], ncnt, m;
LL g[V], sum[V], a[V], T, n;
inline int ID(LL x) {
return x <= T ? id1[x] : id2[n / x];
}
inline LL calc(LL x) {
x%=mod;
return (x * (x + 1) %mod * (2*x+1)%mod *pw6%mod - 1 +mod)%mod;
}
inline LL f(LL x) {
return x * x %mod;
}
inline void init() {
T = sqrt(n + 0.5);
for (int i = 2; i <= T; i++) {
if (!flag[i]) prime[++ncnt] = i, sum[ncnt] = (sum[ncnt - 1] + i * i %mod )%mod;
for (int j = 1; j <= ncnt && i * prime[j] <= T; j++) {
flag[i * prime[j]] = 1;
if (i % prime[j] == 0) break;
}
}
for (LL l = 1; l <= n; l = n / (n / l) + 1) {
a[++m] = n / l;
if (a[m] <= T) id1[a[m]] = m; else id2[n / a[m]] = m;
g[m] = calc(a[m]);
}
for (int i = 1; i <= ncnt; i++)
for (int j = 1; j <= m && (LL)prime[i] * prime[i] <= a[j]; j++) {
g[j] = g[j] - (LL)prime[i]*prime[i]%mod* ((g[ID(a[j] / prime[i])] - sum[i - 1]+mod)%mod) %mod;
g[j] = (g[j] %mod + mod) %mod;
}
}
inline LL solve(LL x) {
if (x <= 1) return x;
return n = x, init(), g[ID(n)];
}
}
namespace Min252 {
int prime[V], id1[V], id2[V], flag[V], ncnt, m;
LL g[V], sum[V], a[V], T, n;
inline int ID(LL x) {
return x <= T ? id1[x] : id2[n / x];
}
inline LL calc(LL x) {
x%=mod;
return (x * (x + 1) %mod * (2*x+1)%mod *pw6%mod - 1 +mod)%mod;
}
inline LL f(LL x) {
return x * x %mod;
}
inline void init() {
T = sqrt(n + 0.5);
for (int i = 2; i <= T; i++) {
if (!flag[i]) prime[++ncnt] = i, sum[ncnt] = (sum[ncnt - 1] + i * i %mod )%mod;
for (int j = 1; j <= ncnt && i * prime[j] <= T; j++) {
flag[i * prime[j]] = 1;
if (i % prime[j] == 0) break;
}
}
for (LL l = 1; l <= n; l = n / (n / l) + 1) {
a[++m] = n / l;
if (a[m] <= T) id1[a[m]] = m; else id2[n / a[m]] = m;
g[m] = calc(a[m]);
}
for (int i = 1; i <= ncnt; i++)
for (int j = 1; j <= m && (LL)prime[i] * prime[i] <= a[j]; j++) {
g[j] = g[j] - (LL)prime[i]*prime[i]%mod* ((g[ID(a[j] / prime[i])] - sum[i - 1]+mod)%mod) %mod;
g[j] = (g[j] %mod + mod) %mod;
}
}
inline LL solve(LL x) {
if (x <= 1) return x;
return n = x, init(), g[ID(n)];
}
}
namespace Min251 {
int prime[V], id1[V], id2[V], flag[V], ncnt, m;
LL g[V], sum[V], a[V], T, n;
inline int ID(LL x) {
return x <= T ? id1[x] : id2[n / x];
}
inline LL calc(LL x) {
x%=mod;
return (x * (x + 1)%mod * pw2 %mod - 1 +mod)%mod;
}
inline LL f(LL x) {
return x;
}
inline void init() {
T = sqrt(n + 0.5);
for (int i = 2; i <= T; i++) {
if (!flag[i]) prime[++ncnt] = i, sum[ncnt] = (sum[ncnt - 1] + i ) %mod;
for (int j = 1; j <= ncnt && i * prime[j] <= T; j++) {
flag[i * prime[j]] = 1;
if (i % prime[j] == 0) break;
}
}
for (LL l = 1; l <= n; l = n / (n / l) + 1) {
a[++m] = n / l;
if (a[m] <= T) id1[a[m]] = m; else id2[n / a[m]] = m;
g[m] = calc(a[m]);
}
for (int i = 1; i <= ncnt; i++)
for (int j = 1; j <= m && (LL)prime[i] * prime[i] <= a[j]; j++) {
g[j] = g[j] - (LL)prime[i] * ((g[ID(a[j] / prime[i])] - sum[i - 1] + mod)%mod) %mod;
g[j] = (g[j] %mod + mod) %mod;
}
}
inline LL solve(LL x) {
if (x <= 1) return x;
return n = x, init(), g[ID(n)];
}
}
namespace Min253 {
int prime[V], id1[V], id2[V], flag[V], ncnt, m;
LL g[V], sum[V], a[V], T, n;
inline int ID(LL x) {
return x <= T ? id1[x] : id2[n / x];
}
inline LL calc(LL x) {
x%=mod;
return (x * (x + 1)%mod * pw2 %mod - 1 +mod)%mod;
}
inline LL f(LL x) {
return x;
}
inline void init() {
T = sqrt(n + 0.5);
for (int i = 2; i <= T; i++) {
if (!flag[i]) prime[++ncnt] = i, sum[ncnt] = (sum[ncnt - 1] + i ) %mod;
for (int j = 1; j <= ncnt && i * prime[j] <= T; j++) {
flag[i * prime[j]] = 1;
if (i % prime[j] == 0) break;
}
}
for (LL l = 1; l <= n; l = n / (n / l) + 1) {
a[++m] = n / l;
if (a[m] <= T) id1[a[m]] = m; else id2[n / a[m]] = m;
g[m] = calc(a[m]);
}
for (int i = 1; i <= ncnt; i++)
for (int j = 1; j <= m && (LL)prime[i] * prime[i] <= a[j]; j++) {
g[j] = g[j] - (LL)prime[i] * ((g[ID(a[j] / prime[i])] - sum[i - 1] + mod)%mod) %mod;
g[j] = (g[j] %mod + mod) %mod;
}
}
inline LL solve(LL x) {
if (x <= 1) return x;
return n = x, init(), g[ID(n)];
}
}
signed main()
{
read(N);
// rep(i,1,200)
// write(i,' '),bruteforce(i);
n=N%mod;
C=(n*(n+1)%mod*inv(2)%mod+mod-1)%mod;
D=(n*(n+1)%mod*((2*n+1)%mod)%mod*inv(6)%mod+mod-1)%mod;
B=C*C%mod;
// write(C,' ');write(D,' ');
// rep(i,(N+1)/2,N)if(isprime(i))
// E=(E+i)%mod,F=(i*i%mod+F)%mod;
E=((Min251::solve(N)-Min253::solve(N/2))%mod+mod)%mod;
F=((Min252::solve(N)-Min254::solve(N/2))%mod+mod)%mod;
// write(E,' ');write(F,' ');
int ans=((B+E*E%mod-(2*C*E%mod)+F-D)%mod+mod)%mod*inv(2)%mod;
write(ans);
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 38516kb
input:
4
output:
8
result:
ok 1 number(s): "8"
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score: 0
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memory: 38512kb
input:
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output:
8
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ok 1 number(s): "8"
Test #3:
score: 0
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time: 0ms
memory: 38364kb
input:
6
output:
80
result:
ok 1 number(s): "80"
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score: 0
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time: 0ms
memory: 38416kb
input:
7
output:
80
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ok 1 number(s): "80"
Test #5:
score: 0
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time: 0ms
memory: 42616kb
input:
8
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200
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ok 1 number(s): "200"
Test #6:
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9
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407
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ok 1 number(s): "539142456"
Test #29:
score: 0
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time: 72ms
memory: 47920kb
input:
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ok 1 number(s): "730264865"
Test #30:
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time: 68ms
memory: 47972kb
input:
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ok 1 number(s): "326703895"
Test #31:
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memory: 49964kb
input:
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Test #32:
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Accepted
time: 63ms
memory: 45856kb
input:
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memory: 78480kb
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score: 0
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Accepted
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memory: 107212kb
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Accepted
time: 1772ms
memory: 110376kb
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ok 1 number(s): "627965619"