#include <bits/stdc++.h>
using namespace std;
const int N = 2e6 + 10;
void solve()
{
    int n, ans = 0;
    cin >> n;
    int a[2 * n + 1];
    for (int i = 1; i <= n * 2; i++)
    {
        int x;
        cin >> x;
        if (++a[x] == 1)
        {
            ans++;
        }
    }
    if (ans > n)
    {
        cout << "Kevin\n";
    }
    else
    {
        cout << "Qingyu\n";
    }
}
signed main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int T;
    cin >> T;
    while (T--)
    {
        solve();
    }
    return 0;
}