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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#603140 | #8718. 保区间最小值一次回归问题 | UESTC_DECAYALI# | WA | 485ms | 35756kb | C++20 | 3.0kb | 2024-10-01 14:53:51 | 2024-10-01 14:53:52 |
Judging History
answer
#include<cstdio>
#include<iostream>
#include<vector>
#include<algorithm>
#define int long long
#define RI register int
#define CI const int&
using namespace std;
const int N=500005,INF=1e18;
struct ifo
{
int l,r,v;
friend inline bool operator < (const ifo& A,const ifo& B)
{
return A.v>B.v;
}
}O[N]; int t,n,m,tl,tr,a[N],fa[N],mxp[N];
inline int getfa(CI x)
{
return fa[x]!=x?fa[x]=getfa(fa[x]):x;
}
class Segment_Tree
{
private:
int mn[N<<2];
public:
#define TN CI now=1,CI l=tl,CI r=tr
#define LS now<<1,l,mid
#define RS now<<1|1,mid+1,r
inline void build(TN)
{
if (l==r) return (void)(mn[now]=INF);
int mid=(l+r)/2; build(LS); build(RS);
}
inline int query(CI beg,CI end,TN)
{
if (beg>end) return INF;
if (beg<=l&&r<=end) return mn[now]; int mid=(l+r)/2,ret=INF;
if (beg<=mid) ret=min(ret,query(beg,end,LS));
if (end>mid) ret=min(ret,query(beg,end,RS));
return ret;
}
inline void update(CI pos,CI mv,TN)
{
if (l==r) return (void)(mn[now]=mv); int mid=(l+r)/2;
if (pos<=mid) update(pos,mv,LS); else update(pos,mv,RS);
mn[now]=min(mn[now<<1],mn[now<<1|1]);
}
#undef TN
#undef LS
#undef RS
}SEG;
inline int solve(CI l,CI r,CI v)
{
vector <int> vec;
for (RI i=l;i<=r;++i)
{
int x=getfa(O[i].l);
while (x<=O[i].r)
{
vec.push_back(x);
fa[x]=x+1; x=getfa(x);
}
}
sort(vec.begin(),vec.end());
for (RI i=0;i<vec.size();++i) mxp[i]=0;
for (RI i=l;i<=r;++i)
{
int L=lower_bound(vec.begin(),vec.end(),O[i].l)-vec.begin();
int R=lower_bound(vec.begin(),vec.end(),O[i].r)-vec.begin()+1;
if (L>R) return -1; else mxp[R]=max(mxp[R],L);
}
if (vec.empty()) return 0;
tl=0; tr=vec.size(); SEG.build(); SEG.update(0,0);
int lst=-1;
for (RI i=0;i<vec.size();++i)
{
if (i-1>=0) lst=max(lst,mxp[i-1]);
int tmp=SEG.query(lst+1,i)+abs(a[vec[i]]-v);
SEG.update(i+1,tmp);
if (a[vec[i]]<=v) lst=i;
}
lst=max(lst,mxp[vec.size()-1]);
return SEG.query(lst+1,vec.size());
}
signed main()
{
//freopen("F.in","r",stdin);
for (scanf("%lld",&t);t;--t)
{
scanf("%lld%lld",&n,&m);
for (RI i=1;i<=n;++i) scanf("%lld",&a[i]);
for (RI i=1;i<=n+1;++i) fa[i]=i;
for (RI i=1;i<=m;++i) scanf("%lld%lld%lld",&O[i].l,&O[i].r,&O[i].v);
sort(O+1,O+m+1); bool flag=1; int ans=0;
for (RI i=1;i<=m;)
{
int j=i;
while (j+1<=m&&O[j+1].v==O[i].v) ++j;
int tmp=solve(i,j,O[i].v);
if (tmp==-1) { flag=0; break; }
ans+=tmp; i=j+1;
}
if (!flag) puts("-1"); else printf("%lld\n",ans);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 12068kb
input:
1 3 2 2023 40 41 1 1 2022 2 3 39
output:
2
result:
ok 1 number(s): "2"
Test #2:
score: -100
Wrong Answer
time: 485ms
memory: 35756kb
input:
1000 100 100 1 35141686 84105222 84105220 7273527 178494861 178494861 112519027 77833654 77833656 261586535 278472336 278472336 261586536 416361017 416361017 426649080 323519513 278472337 420127821 420127823 420127823 482516531 434108818 420127821 631535744 615930922 546346921 546346920 546346920 70...
output:
51 46 37 39 44 43 45 46 46 48 40 56 777 50 43 54 44 61 53 45 45 52 38 51 49 56 51 43 40 43 41 52 53 43 57 42 43 40 38 48 41 46 45 48 738 776 43 49 47 52 46 40 50 48 39 46 52 53 49 45 38 46 40 38 52 42 47 42 33 51 47 49 45 45 42 38 36 42 35 45 43 31 43 47 49 47 46 46 38 38 42 38 46 50 46 42 43 42 42 ...
result:
wrong answer 1st numbers differ - expected: '49', found: '51'