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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#603125 | #8716. 树 | Komorebie# | WA | 1ms | 3676kb | C++17 | 2.7kb | 2024-10-01 14:51:00 | 2024-10-01 14:51:14 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
#define ll long long
#define PII pair<int, int>
#define pi acos(-1.0)
struct LCA {
vector<vector<int>> G;
vector<vector<int>> fa;
vector<int> dep;
LCA(int n)
{
G.resize(n + 1);
fa.resize(n + 1, vector<int>(31, 0));
dep.resize(n + 1, 0);
}
void dfs(int u, int f)
{
fa[u][0] = f;
dep[u] = dep[f] + 1;
for (int i = 1; i < 31; i++) {
fa[u][i] = fa[fa[u][i - 1]][i - 1];
}
for (int v : G[u]) {
if (v != f) {
dfs(v, u);
}
}
}
int lca(int x, int y)
{
if (dep[x] < dep[y]) {
swap(x, y);
}
int d = dep[x] - dep[y];
for (int i = 0; (1 << i) <= d; i++) {
if ((d >> i) & 1) x = fa[x][i];
}
if (x == y) return x;
for (int i = log2(dep[y]); i >= 0; i--) {
if (fa[x][i] != fa[y][i]) {
x = fa[x][i];
y = fa[y][i];
}
}
return fa[x][0];
}
bool isfa(int x, int y) { return lca(x, y) == x; }
int dist(int x, int y) { return dep[x] + dep[y] - 2 * dep[lca(x, y)]; }
};
int main()
{
ios::sync_with_stdio(false), cin.tie(nullptr);
int n, m, q;
cin >> n >> m >> q;
LCA T(n);
vector<int> b(m + 1);
for (int i = 1; i < n; i++) {
int u, v;
cin >> u >> v;
T.G[u].push_back(v), T.G[v].push_back(u);
}
for (int i = 1; i <= m; i++) cin >> b[i];
T.dfs(1, 0);
vector<bool> son(m + 1, false);
son[1] = 1;
auto calc = [&](int i) {
if (i > 2 && T.lca(b[i - 2], b[i]) != b[i - 1] && T.isfa(b[i - 1], b[i - 2]) && T.isfa(b[i - 1], b[i])) return false;
return T.isfa(b[i - 1], b[i]);
};
for (int i = 2; i <= m; i++) {
son[i] = calc(i);
}
int ans = m;
for (int i = 3; i <= m; i++) {
if (son[i] == 1) ans--;
}
// cout << ans << endl;
while (q--) {
int p, w;
cin >> p >> w;
unordered_map<int, bool> tmp;
int last = b[p];
for (int i = max(2, p - 2); i <= min(m, p + 2); i++) tmp[i] = son[i];
b[p] = w;
for (int i = max(2, p - 2); i <= min(m, p + 2); i++) {
son[i] = calc(i);
}
for (int i = max(3, p - 2); i <= min(m, p + 2); i++) {
ans -= son[i] - tmp[i];
}
for (int i = max(2, p - 2); i <= min(m, p + 2); i++) {
son[i] = tmp[i];
}
b[p] = last;
cout << ans << endl;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3676kb
input:
5 5 3 2 1 3 2 1 4 5 1 1 5 4 2 3 1 3 5 3 3 3
output:
4 4 5
result:
ok 3 number(s): "4 4 5"
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3604kb
input:
30 200 200 10 24 10 13 10 26 13 29 27 26 17 24 27 21 17 15 13 5 13 30 27 3 18 21 9 21 2 24 10 4 11 5 2 8 10 23 1 18 21 25 4 20 12 23 22 27 28 27 18 7 13 6 14 30 10 19 16 21 14 29 25 30 1 17 22 21 11 19 21 30 13 1 22 10 14 7 29 7 15 21 25 29 25 7 29 7 1 23 3 17 2 7 4 27 18 26 3 6 5 3 16 26 20 19 16 2...
output:
184 185 185 185 185 186 186 186 185 185 185 185 186 186 186 186 185 185 185 185 185 184 184 184 184 184 184 183 183 183 183 183 183 183 183 183 183 183 183 183 183 183 183 182 182 182 181 181 182 182 183 183 183 184 184 184 184 185 185 185 185 186 186 187 187 187 187 187 187 189 189 189 189 189 188 ...
result:
wrong answer 1st numbers differ - expected: '174', found: '184'