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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#603108 | #8716. 树 | frs# | WA | 0ms | 12540kb | C++14 | 3.2kb | 2024-10-01 14:43:11 | 2024-10-01 14:43:11 |
Judging History
answer
#include<iostream>
#include<cstdio>
#include<cstring>
#include<queue>
#include<vector>
using namespace std;
const int N = 2e5 + 5;
int n, m, qr, p, g, b[N], ans;
int fa[N][22], dep[N];
bool f[N];
vector<int> ve[N];
void dfs(int x, int last, int d){
dep[x] = d;
fa[x][0] = last;
for (auto i:ve[x]){
if (i == last) continue;
dfs(i, x, d+1);
}
}
int lca(int x, int y){
if (dep[x] > dep[y]) swap(x, y);
int z = dep[y]-dep[x], c = 0;
while (z){
if (z & 1) y = fa[y][c];
z >>= 1;
c++;
}
if (x == y) return x;
for (int i = 20; i >= 0; --i) {
if (fa[x][i] == fa[y][i]) continue;
x = fa[x][i];
y = fa[y][i];
}
return fa[x][0];
}
void check(int i){
int l = 0, r = 0, z = 0, ret;
ret = lca(b[i - 1], b[i + 1]);
if(ret == b[i - 1]) l++;
else if(ret == b[i + 1]) r++;
ret = lca(b[i - 1], b[i]);
if(ret == b[i - 1]) l++;
else if(ret == b[i]) z++;
ret = lca(b[i], b[i + 1]);
if(ret == b[i]) z++;
else if(ret == b[i + 1]) r++;
if(f[i] == 1){
if(l == 2 && z == 1) f[i] = 0;
else if(r == 2 && z == 1) f[i] = 0;
else if(l == 0 && r == 0 && (z == 1 || (z == 2 && lca(b[i - 1], b[i + 1]) == b[i]) || (z == 2 && lca(lca(b[i - 1], b[i + 1]), b[i]) != b[i]))){
f[i] = 0;
}
if(f[i] == 0) ans--;
}
else{
if(l == 2 && z == 1) f[i] = 0;
else if(r == 2 && z == 1) f[i] = 0;
else if(l == 0 && r == 0 && (z == 1 || (z == 2 && lca(b[i - 1], b[i + 1]) == b[i]) || (z == 2 && lca(lca(b[i - 1], b[i + 1]), b[i]) != b[i]))){
f[i] = 0;
}
else{
f[i] = 1;
ans++;
}
}
}
int main(){
scanf("%d%d%d", &n, &m, &qr);
int u, v;
for(int i = 1; i < n; i++){
scanf("%d%d", &u, &v);
ve[u].push_back(v);
ve[v].push_back(u);
}
for(int i = 1; i <= m; i++){
scanf("%d", &b[i]);
}
dfs(1, 0, 1);
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= 20; ++j) {
fa[i][j] = fa[fa[i][j-1]][j-1];
}
}
f[1] = 1;
f[m] = 1;
for(int i = 2; i < m; i++){
int l = 0, r = 0, z = 0, ret;
ret = lca(b[i - 1], b[i + 1]);
if(ret == b[i - 1]) l++;
else if(ret == b[i + 1]) r++;
ret = lca(b[i - 1], b[i]);
if(ret == b[i - 1]) l++;
else if(ret == b[i]) z++;
ret = lca(b[i], b[i + 1]);
if(ret == b[i]) z++;
else if(ret == b[i + 1]) r++;
f[i] = 1;
if(l == 2 && z == 1) f[i] = 0;
else if(r == 2 && z == 1) f[i] = 0;
else if(l == 0 && r == 0 && (z == 1 || (z == 2 && lca(b[i - 1], b[i + 1]) == b[i]) || (z == 2 && lca(lca(b[i - 1], b[i + 1]), b[i]) != b[i]))){
f[i] = 0;
}
}
ans = 0;
for(int i = 1; i <= m; i++){
if(f[i]) ans++;
}
while(qr--){
scanf("%d%d", &p, &g);
b[p] = g;
if(p > 1 && p < m) check(p);
if(p - 1 > 1 && p - 1 < m) check(p - 1);
if(p + 1 > 1 && p + 1 < m) check(p + 1);
printf("%d\n", ans);
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 12540kb
input:
5 5 3 2 1 3 2 1 4 5 1 1 5 4 2 3 1 3 5 3 3 3
output:
4 4 5
result:
ok 3 number(s): "4 4 5"
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 9596kb
input:
30 200 200 10 24 10 13 10 26 13 29 27 26 17 24 27 21 17 15 13 5 13 30 27 3 18 21 9 21 2 24 10 4 11 5 2 8 10 23 1 18 21 25 4 20 12 23 22 27 28 27 18 7 13 6 14 30 10 19 16 21 14 29 25 30 1 17 22 21 11 19 21 30 13 1 22 10 14 7 29 7 15 21 25 29 25 7 29 7 1 23 3 17 2 7 4 27 18 26 3 6 5 3 16 26 20 19 16 2...
output:
171 172 172 172 172 172 173 173 173 173 174 174 174 174 173 173 172 172 172 172 171 170 169 169 169 169 169 169 169 169 169 168 168 169 169 169 169 169 169 169 170 170 169 169 169 169 170 171 172 171 172 172 172 172 172 172 172 172 172 172 173 174 173 173 173 173 173 174 174 174 174 174 174 174 174 ...
result:
wrong answer 1st numbers differ - expected: '174', found: '171'