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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#602596 | #8720. BFS 序 0 | Kanate# | RE | 0ms | 22056kb | C++14 | 2.4kb | 2024-10-01 11:05:12 | 2024-10-01 11:05:12 |
Judging History
answer
#include<bits/stdc++.h>
#define int long long
//#define mod 1000000007
#define rep(i,j,k) for(int i=(j);i<=(k);i++)
#define per(i,j,k) for(int i=(j);i>=(k);i--)
using namespace std;
template<class T>void chkmax(T &a,T b){a=max(a,b);}
template<class T>void chkmin(T &a,T b){a=min(a,b);}
template<class T>T read(T &x)
{
x=0;T f=1;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0'&&c<='9'){x=x*10+(c^'0');c=getchar();}
return x*=f;
}
template<class T,class ...L>void read(T &x,L &...l){read(x),read(l...);}
template<class T>void write(T x)
{
if(x<0){putchar('-');x=-x;}
if(x>9){write(x/10);}putchar(x%10+'0');
}
template<class T>void write(T x,char c){write(x),putchar(c);}
int dfnn;
int n,dfn[300005],dep[300005],siz[300005];
int q,m,a[300005];
vector <int> g[300005];
void dfs(int u)
{
dfn[u]=++dfnn;
siz[u]=1;
for(int v:g[u])
{
dep[v]=dep[u]+1;
dfs(v);
siz[u]+=siz[v];
}
}
#define mid (l+r)/2
#define ls (o*2)
#define rs (o*2+1)
int seg1[300005<<2],seg2[300005<<2],tag[300005<<2];
void pushup(int o)
{
seg1[o]=max(seg1[ls],seg1[rs]);
seg2[o]=min(seg2[ls],seg2[rs]);
}
void pushdown(int o)
{
if(!tag[o])return;
tag[ls]=tag[rs]=tag[o];
seg1[ls]=seg2[ls]=seg1[rs]=seg2[rs]=tag[o]-1;
tag[o]=0;
pushup(o);
}
void assign(int lx,int rx,int k,int o=1,int l=1,int r=n)
{
pushdown(o);
if(lx<=l&&r<=rx)
{
tag[o]=k;
seg1[o]=k-1;
seg2[o]=k-1;
return;
}
if(lx<=mid)assign(lx,rx,k,ls,l,mid);
if(rx>mid)assign(lx,rx,k,rs,mid+1,r);
pushup(o);
}
int query1(int lx,int rx,int o=1,int l=1,int r=n)
{
pushdown(o);
if(lx<=l&&r<=rx)return seg1[o];
int ans=0;
if(lx<=mid)chkmax(ans,query1(lx,rx,ls,l,mid));
if(rx>mid)chkmax(ans,query1(lx,rx,rs,mid+1,r));
return ans;
}
int query2(int lx,int rx,int o=1,int l=1,int r=n)
{
pushdown(o);
if(lx<=l&&r<=rx)return seg2[o];
int ans=1;
if(lx<=mid)chkmin(ans,query2(lx,rx,ls,l,mid));
if(rx>mid)chkmin(ans,query2(lx,rx,rs,mid+1,r));
return ans;
}
void solve()
{
assign(1,n,1);
read(m);
rep(i,1,m)read(a[i]);
rep(i,1,m-1)
if(dep[a[i]]>dep[a[i+1]])
{puts("No");return;}
rep(i,1,m)
{
int l=dfn[a[i]];
int r=dfn[a[i]]+siz[a[i]]-1;
int q1=query1(l,r);
int q2=query2(l,r);
if(q1!=q2){puts("No");return;}
assign(l,r,2);
}
puts("Yes");
}
signed main()
{
read(n);
rep(i,2,n)
{
int fa;read(fa);
g[fa].push_back(i);
}
dfs(1);
read(q);
rep(i,1,q)solve();
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 22056kb
input:
6 1 1 3 2 4 10 4 3 6 2 5 1 4 3 2 4 5 5 2 5 4 6 3 3 1 4 2 3 5 6 3 5 4 5 2 6 1 4 4 3 2 5 4 4 6 2 3 3 3 2 6
output:
No Yes Yes No No No No No No Yes
result:
ok 10 token(s): yes count is 3, no count is 7
Test #2:
score: -100
Runtime Error
input:
300000 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1...