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#601325#9429. Subarrayucup-team4474WA 268ms46664kbC++205.7kb2024-09-29 22:21:212024-09-29 22:21:22

Judging History

你现在查看的是最新测评结果

  • [2024-09-29 22:21:22]
  • 评测
  • 测评结果:WA
  • 用时:268ms
  • 内存:46664kb
  • [2024-09-29 22:21:21]
  • 提交

answer

#include <bits/stdc++.h>
using i64 = long long;
using namespace std;

const int P = 998244353;
using Poly = vector<int>;
#define MUL(a, b) (i64(a) * (b) % P)
#define ADD(a, b) (((a) += (b)) >= P ? (a) -= P : 0)
#define SUB(a, b) (((a) -= (b)) < 0 ? (a) += P : 0)
Poly getInv(int L)
{
    Poly inv(L);
    inv[1] = 1;
    for (int i = 2; i < L; i++)
        inv[i] = MUL((P - P / i), inv[P % i]);
    return inv;
}
int POW(i64 a, int b = P - 2, i64 x = 1)
{
    for (; b; b >>= 1, a = a * a % P)
        if (b & 1)
            x = x * a % P;
    return x;
}
namespace NTT
{
    const int g = 3;
    Poly Omega(int L)
    {
        int wn = POW(g, P / L);
        Poly w(L);
        w[L >> 1] = 1;
        for (int i = L / 2 + 1; i < L; i++)
            w[i] = MUL(w[i - 1], wn);
        for (int i = L / 2 - 1; i >= 1; i--)
            w[i] = w[i << 1];
        return w;
    }
    auto W = Omega(1 << 20);
    void DIF(int *a, int n)
    {
        for (int k = n >> 1; k; k >>= 1)
            for (int i = 0, y; i < n; i += k << 1)
                for (int j = 0; j < k; j++)
                    y = a[i + j + k], a[i + j + k] = MUL(a[i + j] - y + P, W[k + j]), ADD(a[i + j], y);
    }
    void IDFT(int *a, int n)
    {
        for (int k = 1; k < n; k <<= 1)
            for (int i = 0, x, y; i < n; i += k << 1)
                for (int j = 0; j < k; j++)
                    x = a[i + j], y = MUL(a[i + j + k], W[k + j]),
                    a[i + j + k] = x - y < 0 ? x - y + P : x - y, ADD(a[i + j], y);
        int Inv = P - (P - 1) / n;
        for (int i = 0; i < n; i++)
            a[i] = MUL(a[i], Inv);
        reverse(a + 1, a + n);
    }
}
namespace Polynomial
{
    int norm(int n) { return 1 << (__lg(n - 1) + 1); }
    void norm(Poly &a)
    {
        if (!a.empty())
            a.resize(norm(a.size()), 0);
        else
            a = {0};
    }
    void DFT(Poly &a) { NTT::DIF(a.data(), a.size()); }
    void IDFT(Poly &a) { NTT::IDFT(a.data(), a.size()); }
    Poly &dot(Poly &a, Poly &b)
    {
        for (int i = 0; i < a.size(); i++)
            a[i] = MUL(a[i], b[i]);
        return a;
    }
    Poly operator*(Poly a, Poly b)
    {
        int n = a.size() + b.size() - 1, L = norm(n);
        if (a.size() <= 8 || b.size() <= 8)
        {
            Poly c(n);
            for (int i = 0; i < a.size(); i++)
                for (int j = 0; j < b.size(); j++)
                    c[i + j] = (c[i + j] + (i64)a[i] * b[j] % P);
            return c;
        }
        a.resize(L), b.resize(L);
        DFT(a), DFT(b), dot(a, b), IDFT(a);
        return a.resize(n), a;
    }
}
using namespace Polynomial;

void solve()
{
    int n;
    cin >> n;
    vector<int> a(n + 1);
    for (int i = 1; i <= n; i++)
        cin >> a[i];
    vector<array<int, 19>> b(n + 1);
    map<int, vector<int>> pos;
    vector<int> logn(n + 1, -1);
    for (int i = 1; i <= n; i++)
    {
        logn[i] = logn[i >> 1] + 1;
        pos[a[i]].push_back(i);
        b[i][0] = a[i];
    }
    for (int j = 1; j <= 18; j++)
        for (int i = 1; i + (1 << j) - 1 <= n; i++)
            b[i][j] = max(b[i][j - 1], b[i + (1 << (j - 1))][j - 1]);
    auto ask = [&](int l, int r) -> int
    {
        int s = logn[r - l + 1];
        return max(b[l][s], b[r - (1 << s) + 1][s]);
    };

    Poly ans(n + 1);
    auto solve = [&](auto &solve, int cur, int l, int r) -> void
    {
        if (l < cur)
        {
            int val = ask(l, cur - 1);
            auto &t = pos[val];
            vector<int> tmp{l - 1};
            for (auto it = lower_bound(t.begin(), t.end(), l); it != t.end() and *it < cur; it++)
                tmp.push_back(*it);
            tmp.push_back(cur);

            Poly f(tmp.size() - 1);
            for (int j = 1; j < tmp.size(); j++)
                f[j - 1] = tmp[j] - tmp[j - 1];
            auto g = f;
            reverse(g.begin(), g.end());
            auto h = f * g;
            int p = f.size();
            for (int j = p - 1; j < p * 2 - 1; j++)
                ADD(ans[j - p + 1], h[j]);

            for (int j = 1; j + 1 < tmp.size(); j++)
            {
                if (j == 1)
                    solve(solve, tmp[j], tmp[j - 1] + 1, tmp[j + 1] - 1);
                else
                    solve(solve, tmp[j], tmp[j], tmp[j + 1] - 1);
            }
        }
        if (cur < r)
        {
            int val = ask(cur + 1, r);
            auto &t = pos[val];
            vector<int> tmp{cur};
            for (auto it = lower_bound(t.begin(), t.end(), cur); it != t.end() and *it <= r; it++)
                tmp.push_back(*it);
            tmp.push_back(r + 1);

            Poly f(tmp.size() - 1);
            for (int j = 1; j < tmp.size(); j++)
                f[j - 1] = tmp[j] - tmp[j - 1];
            auto g = f;
            reverse(g.begin(), g.end());
            auto h = f * g;
            int p = f.size();
            for (int j = p - 1; j < p * 2 - 1; j++)
                ADD(ans[j - p + 1], h[j]);

            for (int j = 1; j + 1 < tmp.size(); j++)
            {
                if (j == 1)
                    solve(solve, tmp[j], tmp[j - 1] + 1, tmp[j + 1] - 1);
                else
                    solve(solve, tmp[j], tmp[j], tmp[j + 1] - 1);
            }
        }
    };

    solve(solve, 0, 1, n);
    int res = 0;
    for (int i = 1; i <= n; i++)
        res = (res + 1ll * i * ans[i] % P * ans[i] % P) % P;
    cout << res << '\n';
}
/*
 3
 11
 1 1 2 1 2 2 3 3 2 3 1
 3
 2024 5 26
 3
 1000000000 1000000000 1000000000
*/

signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int t = 1;
    cin >> t;
    while (t--)
        solve();
}

詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 7008kb

input:

3
11
1 1 2 1 2 2 3 3 2 3 1
3
2024 5 26
3
1000000000 1000000000 1000000000

output:

2564
36
20

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 107ms
memory: 19156kb

input:

2522
12
642802746 634074578 642802746 634074578 642802746 634074578 634074578 642802746 740396295 634074578 740396295 634074578
16
305950462 400920468 400920468 305950462 400920468 305950462 400920468 400920468 400920468 400920468 305950462 305950462 400920468 305950462 305950462 305950462
2
4405082...

output:

3610
7545
9
1
50
1006
16170
5972
3117
540
540
4417
12885
336
3185
83
9272
27
1794
2776
1793
196
27
1377
8783
19723
5385
1864
3478
7101
1
431
825
4534
9900
162
21644
6
36
14088
306
9
57
1719
72
9
4637
68
16583
17701
19390
16282
5440
1
6
1716
19541
3823
2033
24
825
429
1911
11787
11388
12255
12175
126...

result:

ok 2522 lines

Test #3:

score: 0
Accepted
time: 148ms
memory: 44836kb

input:

1
400000
860350786 641009859 939887597 54748096 641009859 860350786 710156469 985188306 476927808 641009859 985188306 322595515 322595515 973764525 54748096 939887597 54748096 476927808 588586447 669240390 54748096 476927808 669240390 804928248 669240390 75475634 804928248 669240390 985188306 754756...

output:

300998364

result:

ok single line: '300998364'

Test #4:

score: 0
Accepted
time: 166ms
memory: 43760kb

input:

1
400000
860422965 880311831 389867323 711027909 603801945 977217669 127611088 468302420 100563882 896362064 321065270 937796491 106388135 679974087 799365054 508500258 155801089 72992050 568198964 469117950 605828088 147285088 931759705 335154243 123769214 717250374 123769214 588271814 193910044 58...

output:

642490751

result:

ok single line: '642490751'

Test #5:

score: -100
Wrong Answer
time: 268ms
memory: 46664kb

input:

1
400000
489576972 624268112 792793292 261080167 299965397 570683924 43370033 865049228 160224484 597021302 799302320 154578623 616009875 817736437 422498140 177450324 576706528 701882608 322199948 469659816 265384591 886524303 331787804 922381773 642896492 36870304 922875786 328785523 506357505 778...

output:

545691233

result:

wrong answer 1st lines differ - expected: '728396411', found: '545691233'