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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#598898#9417. Palindromic Polygonucup-team3584#WA 1ms3652kbC++234.6kb2024-09-28 23:57:252024-09-28 23:57:25

Judging History

你现在查看的是最新测评结果

  • [2024-09-28 23:57:25]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3652kb
  • [2024-09-28 23:57:25]
  • 提交

answer

#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
typedef unsigned long long int ull;

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll myRand(ll B) { return (ull)rng() % B; }

// 整数幾何
typedef ll Integer;
const Integer eps = 0;
inline constexpr int arg_type(Integer x, Integer y) { return y < 0 ? 2 : x < 0 ? 1 : 0; }
struct Point {
    Integer x, y;
    constexpr explicit Point(Integer x = 0, Integer y = 0) : x(x), y(y) {}
    constexpr Point operator+() const noexcept { return *this; }
    constexpr Point operator-() const noexcept { return Point(-x, -y); }
    constexpr Point operator+(const Point &p) const { return Point(x + p.x, y + p.y); }
    constexpr Point operator-(const Point &p) const { return Point(x - p.x, y - p.y); }
    constexpr Point &operator+=(const Point &p) { return x += p.x, y += p.y, *this; }
    constexpr Point &operator-=(const Point &p) { return x -= p.x, y -= p.y, *this; }
    constexpr Point &operator*=(const Integer &k) { return x *= k, y *= k, *this; }
    constexpr Point operator*(const Integer &k) const { return Point(x * k, y * k); }
    constexpr bool operator==(const Point &r) const noexcept { return r.x == x and r.y == y; }
    constexpr Integer dot(const Point &r) const { return x * r.x + y * r.y; }
    constexpr Integer cross(const Point &r) const { return x * r.y - y * r.x; }
    constexpr Integer norm2() const { return x * x + y * y; }
};

int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    int q;
    cin >> q;
    auto area = [&](Point a, Point b, Point c) -> ll {
        b -= a, c -= a;
        ll bx = b.x, by = b.y, cx = c.x, cy = c.y;
        return abs(bx * cy - cx * by);
    };
    while (q--) {
        int n, m;
        cin >> n;
        vector<int> v(n);
        for (int i = 0; i < n; ++i) {
            cin >> v[i];
        }
        vector<Point> p(n);
        for (int i = 0; i < n; ++i) {
            cin >> p[i].x >> p[i].y;
        }
        vector<vector<int>> nxt_r(n), nxt_l(n);
        {
            auto z = v;
            sort(z.begin(), z.end());
            z.erase(unique(z.begin(), z.end()), z.end());
            m = z.size();
            for (int i = 0; i < n; ++i) {
                nxt_l[i].resize(m), nxt_r[i].resize(m);
                v[i] = lower_bound(z.begin(), z.end(), v[i]) - z.begin();
            }
            for (int i = 0; i < n; ++i) {
                nxt_l[i][v[i]] = nxt_r[i][v[i]] = i;
                for (int j = 0, k = i; j < n; ++j) {
                    k -= 1;
                    if (k == -1) k = n - 1;
                    if (v[k] == v[i]) break;
                    nxt_r[k][v[i]] = i;
                }
                for (int j = 0, k = i; j < n; ++j) {
                    k += 1;
                    if (k == n) k = 0;
                    if (v[k] == v[i]) break;
                    nxt_l[k][v[i]] = i;
                }
            }
        }

        ll res = 0;
        vector<vector<ll>> dp(n, vector<ll>(n, -1));
        for (int i = 0; i < n; ++i) {
            dp[i][i] = 0;
        }
        auto valid = [&](int l, int r, int x) -> bool {
            if (l <= r) {
                if (l <= x and x < r) return false;
                else return true;
            } else {
                if (r <= x and x < l) return true;
                else return false;
            }
        };
        auto calc = [&](auto calc, int l, int r) -> ll {
            if (dp[l][r] != -1) return dp[l][r];
            dp[l][r] = 0;
            for (int i = 0, j = l; i < n; ++i) {
                if (j == r) break;
                int k = nxt_r[r][v[j]];
                if (valid(j, r, k)) {
                    dp[l][r] = max(dp[l][r], calc(calc, j, k) + area(p[l], p[r], p[j]) + area(p[j], p[k], p[r]));
                }
                j -= 1;
                if (j == -1) j = n - 1;
            }
            return dp[l][r];
        };
        for (int i = 0; i < n; ++i) {
            for (int j = 0, k = i; j < n; ++j) {
                k += 1;
                if (k == n) k = 0;
                if (v[i] == v[k] and dp[i][k] == -1) {
                    calc(calc, i, k);
                }
                res = max(res, dp[i][k]);
                for (int l = 0, kk = i; l < j; ++l) {
                    kk += 1;
                    if (kk == n) kk = 0;
                    res = max(res, dp[i][k] + area(p[i], p[kk], p[k]));
                }
            }
        }
        cout << res << "\n";
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3652kb

input:

3
8
2 4 2 4 3 4 5 3
2 3
0 6
-3 3
-3 0
-2 -3
1 -5
3 -3
4 0
3
1 2 3
0 0
1 0
0 1
3
1 1 1
0 0
1 0
0 1

output:

84
0
1

result:

ok 3 number(s): "84 0 1"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3580kb

input:

1
4
1000000000 1000000000 1000000000 1000000000
-1000000000 -1000000000
1000000000 -1000000000
1000000000 1000000000
-1000000000 1000000000

output:

8000000000000000000

result:

ok 1 number(s): "8000000000000000000"

Test #3:

score: -100
Wrong Answer
time: 1ms
memory: 3628kb

input:

129
10
604040473 604040473 287094217 682965575 70435786 287094217 604040473 287094217 682965575 92620053
-193 -184
-200 -200
-125 -169
-120 -157
-120 -145
-124 -139
-137 -136
-155 -149
-172 -163
-187 -177
5
346787871 346787871 113397429 113397429 346787871
-173 -181
-186 -166
-200 -195
-194 -200
-17...

output:

3938
1068
1239
516
2668
3559
1165
3637
560
925
3502
708
3824
1746
2970
1987
1011
2221
1245
4762
1900
1646
564
273
3203
6572
1070
3378
1024
799
142
3104
1883
9445
2128
395
1741
2657
1276
480
2107
5119
5458
2446
4031
2249
4378
5192
2226
1473
3152
1770
2160
1655
3367
2298
1459
2663
2617
2447
4239
232
5...

result:

wrong answer 1st numbers differ - expected: '3857', found: '3938'