QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#597939 | #9425. Generated String | ucup-team1004# | RE | 0ms | 55196kb | C++14 | 4.2kb | 2024-09-28 19:31:47 | 2024-09-28 19:31:54 |
Judging History
answer
#include<bits/stdc++.h>
#define Gc() getchar()
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define eb emplace_back
#define all(x) x.begin(),x.end()
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;
const int N=2e5+5,M=1e7+5,K=1000+5,mod=998244353,Mod=mod-1;const db eps=1e-9;const int INF=1e9+7;mt19937 rnd(263082);
#define Tp template<typename T>
#define Ts template<typename T,typename... Ar>
namespace Debug{
Tp void _debug(char* f,T t){cerr<<f<<'='<<t<<endl;}
Ts void _debug(char* f,T x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
#ifdef LOCAL
#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
#else
#define gdb(...) void()
#endif
}using namespace Debug;
int n,q,X[N],op[N];
const int P=1e9+7;
const int bas=137;
ll pw[N],sum[N];
ll qryHa(int l,int r){
return (sum[r]+(P-sum[l-1])*pw[r-l+1])%P;
}
struct str{
vector<int> L,R;
ll len;
vector<ll> siz,sum;
void init(){
siz.resize(L.size());
sum.resize(R.size());
for(int i=0;i<L.size();i++){
siz[i]=(i?siz[i-1]:0)+R[i]-L[i]+1;
sum[i]=((i?sum[i-1]:0)*pw[R[i]-L[i]+1]+qryHa(L[i],R[i]))%P;
}
len=siz.back();
}
ll qry(ll x){
if(!x) return 0;
int i=LB(all(siz),x)-siz.begin();
x-=(i?siz[i-1]:0);
return ((i?sum[i-1]:0)*pw[x]+qryHa(L[i],L[i]+x-1))%P;
}
ll qryS(ll x){
return (qry(x)+(P-qry(x-1))*bas)%P;
}
}A[N],B[N];
char s[N];
void readstr(str &A){
int k;scanf("%d",&k);
A.L.resize(k);A.R.resize(k);
for(int i=0;i<k;i++) scanf("%d%d",&A.L[i],&A.R[i]);
}
void rev(str &A){
swap(A.L,A.R);
for(int &j:A.L) j=2*n+1-j;
for(int &j:A.R) j=2*n+1-j;
reverse(all(A.L));
reverse(all(A.R));
}
ll LCP(str &A,str &B){
ll l=0,r=min(A.len,B.len)+1,mid;
while(l+1<r) mid=l+r>>1,(A.qry(mid)==B.qry(mid)?l:r)=mid;
return l;
}
int b1[N],e1[N],b2[N],e2[N];
void Sort(str *A,int *bg,int *en){
static int id[N],ih;
ih=0;
for(int i=1;i<=n;i++) if(!A[i].L.empty()) id[++ih]=i;
sort(id+1,id+ih+1,[&](int x,int y){
ll len=LCP(A[x],A[y]);
if(len==min(A[x].len,A[y].len)) return A[x].len<A[y].len;
return A[x].qryS(len+1)<A[y].qryS(len+1);
});
for(int i=1;i<=ih;i++){
bg[id[i]]=i;
int l=i,r=ih+1,mid;
while(l+1<r) mid=l+r>>1,(LCP(A[id[i]],A[id[mid]])==A[id[i]].len?l:r)=mid;
en[id[i]]=l;
}
}
struct ques{int x,l,r,id,w;}Q[N];int qh,ans[N];
namespace bit{
int f[N];
void add(int x,int w){while(x<=q) f[x]+=w,x+=x&-x;}
int qry(int x){int ans=0;while(x) ans+=f[x],x-=x&-x;return ans;}
}
void calc(int l=1,int r=qh){
if(l==r) return;
int m=l+r>>1;calc(l,m);calc(m+1,r);
int R=l;
for(int i=m+1;i<=r;i++){
while(R<=m&&Q[R].x<=Q[i].x){
if(Q[R].id==-1) bit::add(Q[R].l,Q[R].w);
R++;
}
if(~Q[i].id) ans[Q[i].id]+=Q[i].w*(bit::qry(Q[i].r)-bit::qry(Q[i].l-1));
}
while(R>l){
R--;
if(Q[R].id==-1) bit::add(Q[R].l,-Q[R].w);
}
inplace_merge(Q+l,Q+m+1,Q+r+1,[](ques x,ques y){return x.x<y.x;});
}
void Solve(){
scanf("%d%d",&n,&q);
scanf("%s",s+1);
for(int i=1;i<=n;i++) s[2*n-i+1]=s[i];
for(int i=pw[0]=1;i<=2*n;i++) pw[i]=pw[i-1]*bas%P;
for(int i=1;i<=2*n;i++) sum[i]=(sum[i-1]*bas+s[i])%P;
for(int i=1;i<=q;i++){
char c=Gc();
while(c^'+'&&c^'-'&&c^'?') c=Gc();
if(c=='+'){
op[i]=1;
readstr(A[i]);
B[i]=A[i];
rev(B[i]);
A[i].init();
B[i].init();
}else if(c=='-'){
op[i]=2;
scanf("%d",&X[i]);
}else{
op[i]=3;
readstr(A[i]);
readstr(B[i]);
rev(B[i]);
A[i].init();
B[i].init();
}
}
// gdb(LCP(A[1],A[2]));
// return;
Sort(A,b1,e1);Sort(B,b2,e2);
for(int i=1;i<=q;i++){
if(op[i]==1){
Q[++qh]=(ques){b1[i],b2[i],b2[i],-1,1};
}else if(op[i]==2){
Q[++qh]=(ques){b1[X[i]],b2[X[i]],b2[X[i]],-1,-1};
}else{
Q[++qh]=(ques){b1[i]-1,b2[i],e2[i],i,-1};
Q[++qh]=(ques){e1[i],b2[i],e2[i],i,1};
}
}
calc();
for(int i=1;i<=q;i++) if(op[i]==3) printf("%d\n",ans[i]);
}
int main(){
int t=1;
// scanf("%d",&t);
while(t--) Solve();
cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 55196kb
input:
8 7 abcaabbc + 3 1 3 2 4 3 8 + 2 1 4 1 8 + 1 2 4 ? 1 5 6 1 7 8 - 3 + 1 2 5 ? 1 2 3 1 5 5
output:
2 1
result:
ok 2 lines
Test #2:
score: -100
Runtime Error
input:
5 2000 bbaab + 1 3 5 + 2 5 5 3 5 - 2 ? 1 1 3 3 3 3 4 5 2 5 - 1 ? 3 1 1 2 4 1 5 1 3 4 ? 1 1 2 2 2 4 4 4 ? 1 1 5 1 5 5 + 3 1 2 1 5 1 4 ? 2 1 5 1 3 2 1 2 5 5 ? 1 3 4 1 4 5 - 9 ? 1 1 4 1 2 3 + 2 1 5 1 2 + 1 1 4 - 15 - 14 ? 2 2 5 2 5 1 3 4 + 1 2 3 - 19 + 3 1 4 1 5 4 5 - 21 + 1 2 5 ? 3 1 5 5 5 1 5 1 3 5 ?...