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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#597788#7883. Takeout DeliveringAkoasm_XWA 228ms86068kbC++203.0kb2024-09-28 18:48:252024-09-28 18:48:25

Judging History

你现在查看的是最新测评结果

  • [2024-09-28 18:48:25]
  • 评测
  • 测评结果:WA
  • 用时:228ms
  • 内存:86068kb
  • [2024-09-28 18:48:25]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define pii pair<int,int>
#define mp make_pair
#define pb push_back
#define int long long
typedef long long LL;

inline int read(){
	int x = 0 , f = 1 ; char c = getchar() ;
    while( c < '0' || c > '9' ) { if( c == '-' ) f = -1 ; c = getchar() ; } 
    while( c >= '0' && c <= '9' ) { x = x * 10 + c - '0' ; c = getchar() ; } 
    return x * f ;
}

const int maxn = 1e6+20;
int n,m;
int f[maxn];
vector<int> son[maxn],p[maxn];
struct Node{
    int a,b,c;
    bool operator <(const Node X)const{
        return c < X.c;
    }
}A[maxn];
map<pii,int> mm;

int find(int x){
    return x==f[x] ? x : find(f[x]);
}

namespace Seg_tree{
	int s[maxn<<2];
	#define mid ((l+r)>>1)
	#define lson (x<<1),l,mid
	#define rson (x<<1|1),mid+1,r
	void init(int x,int l,int r){
		s[x] = 2e9;
		if(l==r) return ;
		init(lson);init(rson);
	}
	void Modify(int x,int l,int r,int pos,int k){
		s[x] = min(s[x],k);
		if(l==r) return ;
		if(pos<=mid) Modify(lson,pos,k);
		else Modify(rson,pos,k);
	} 
	int Qry(int x,int l,int r,int L,int R){
		if(L<=l&&r<=R){
			return s[x];
		}
		if(R<=mid) return Qry(lson,L,R);
		if(mid<L)  return Qry(rson,L,R);
		return min(Qry(lson,L,R),Qry(rson,L,R));
	}
}
using namespace Seg_tree;

void solve(){
    n = read();m = read();
    for(int i=1;i<=m;i++){
        int a = read(),b = read(),c = read();
        A[i] = (Node){a,b,c};
    }
    sort(A+1,A+1+m);
    if(n==2){
        printf("%d\n",A[1].c);
        return ;
    }
    for(int i=1;i<=n;i++){
        f[i] = i;
        son[i].push_back(i);
    }
    int Ans = 2e9;
    int v = 2e9;
    for(int i=1;i<=m;i++){
        p[A[i].a].push_back(i);
        p[A[i].b].push_back(i+m);
        if(A[i].a==1&&A[i].b==n) Ans = min(Ans,A[i].c);
        if(A[i].a==n&&A[i].b==1) Ans = min(Ans,A[i].c);
    }
    init(1,1,m);
    for(int i=1;i<=m;i++){
        int x = A[i].a;
        int y = A[i].b;
        int fx = find(x);
        int fy = find(y);
        if(fx==fy) continue;
        if((fx==1&&fy==n)||(fx==n&&fy==1)) break;
        if(fx==1 || fx==n || son[fx].size() > son[fy].size()){
            swap(x,y);
            swap(fx,fy);
        }
        f[fx] = fy;
        for(int tmp : son[fx]){
            for(int tt : p[tmp]){
                int id = 0;
                if(tt > m && tt - m > i){
                    A[tt-m].b = fy;
                    id = tt - m;
                }
                else if(tt <= m && tt > i){
                    A[tt].a = fy;
                    id = tt;
                }
                else continue;
                if(A[id].a==1&&A[id].b==n) v = min(v,A[id].c);
        		if(A[id].a==n&&A[id].b==1) v = min(v,A[id].c);
			}
            son[fy].push_back(tmp);
        }
        son[fx].clear();
        Ans = min(Ans,A[i].c + v);
    }
    printf("%d\n",Ans);
}

signed main(){
//	freopen("data.txt","r",stdin);
	int T = 1;
	// T = read();
	while(T--) solve();
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 3ms
memory: 8012kb

input:

4 6
1 2 2
1 3 4
1 4 7
2 3 1
2 4 3
3 4 9

output:

5

result:

ok 1 number(s): "5"

Test #2:

score: -100
Wrong Answer
time: 228ms
memory: 86068kb

input:

300000 299999
80516 80517 597830404
110190 110191 82173886
218008 218009 954561262
250110 250111 942489774
66540 66541 156425292
34947 34948 239499776
273789 273790 453201232
84428 84429 439418398
98599 98600 326095035
55636 55637 355015760
158611 158612 684292473
43331 43332 43265001
171621 171622 ...

output:

2000000000

result:

wrong answer 1st numbers differ - expected: '1999991697', found: '2000000000'