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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#596526#9434. Italian Cuisineucup-team918#WA 19ms3964kbC++142.5kb2024-09-28 15:57:462024-09-28 15:57:48

Judging History

你现在查看的是最新测评结果

  • [2024-09-28 15:57:48]
  • 评测
  • 测评结果:WA
  • 用时:19ms
  • 内存:3964kb
  • [2024-09-28 15:57:46]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

template<typename T> inline void read(T &s) {
	char c = getchar(); int f = 1; s = 0;
	while (!isdigit(c)) { if (c == '-') f = -1; c = getchar(); }
	while (isdigit(c)) s = (s << 3) + (s << 1) + (c ^ 48), c = getchar();
	if (f < 0) s = -s;
}

const int N = 1e5 + 5;
const double eps = 1e-9;

bool equal(double x, double y) { return fabs(x - y) < eps; }

int n;
struct point {
	double x, y;
} p[N];
struct cir {
	point o;
	double r;
} c;
struct line {
	double k, b;
	double gety(double x) {
		return k * x + b;
	}
};

double area(point u, point v, point w) {
	double X1 = v.x - u.x, Y1 = v.y - u.y;
	double X2 = w.x - u.x, Y2 = w.y - u.y;
	double S = fabs(X1 * Y2 - Y1 * X2);
	return S;
}
double dist(point u, point v) {
	return sqrt((u.x - v.x) * (u.x - v.x) + (u.y - v.y) * (u.y - v.y));
}
point intersect(line u, line v) {
	point w;
	w.x = (v.b - u.b) / (u.k - v.k);
	w.y = u.gety(w.x);
	return w;
}
line vertical(line l, point u) {
	line v;
	v.k = -(double)1.0 / l.k;
	v.b = u.y - u.x * v.k;
	return v;
}
line getline(point u, point v) {
	line l;
	l.k = (v.y - u.y) / (v.x - u.x);
	l.b = u.y - l.k * u.x;
	return l;
}
bool intri(point u, point v, point w, point o) {
	double S = area(u, v, w);
	double S1 = area(u, v, o);
	double S2 = area(u, w, o);
	double S3 = area(v, w, o);
	return equal(S, S1 + S2 + S3);
}

ll ans;

void init() {
	ans = 0;
}
int nxt(int id) {
	++id;
	if (id > n) id -= n;
	return id;
}
void solve() {
	init();
	scanf("%d", &n);
	scanf("%lf%lf%lf", &c.o.x, &c.o.y, &c.r);
	for (int i = 1; i <= n; ++i) scanf("%lf%lf", &p[i].x, &p[i].y);
	if (n == 3) { puts("0"); return ; }
	int L = 1, R = 1;
	double now = 0;
	for (L = 1; L <= n; ++L) {
		if (L == R) R = nxt(R);
		while (true) {
			int G = nxt(R);
			if (nxt(G) == L) break;
			if (intri(p[L], p[R], p[G], c.o)) break;
			line l1 = getline(p[L], p[G]);
			line l2 = vertical(l1, c.o);
			point o = intersect(l1, l2);
			if (c.r - dist(c.o, o) > eps) break;
			now += area(p[L], p[R], p[G]);
			// printf("add (%d, %d, %d)\n", L, R, G);
			// printf("area(%d, %d, %d) = %.0lf\n", L, R, G, area(p[L], p[R], p[G]));
			ans = max(ans, (ll)(now + 0.5));
			R = G;
			// printf("L = %d, R = %d, now = %.5lf\n", L, R, now);
		}
		if (R != nxt(L))
			now -= area(p[L], p[nxt(L)], p[R])/*, printf("del (%d, %d, %d)\n", L, nxt(L), R)*/;
	}
	printf("%lld\n", ans);
}

int main() {
	int T; read(T);
	while (T--) solve();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3896kb

input:

3
5
1 1 1
0 0
1 0
5 0
3 3
0 5
6
2 4 1
2 0
4 0
6 3
4 6
2 6
0 3
4
3 3 1
3 0
6 3
3 6
0 3

output:

5
24
0

result:

ok 3 number(s): "5 24 0"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3896kb

input:

1
6
0 0 499999993
197878055 -535013568
696616963 -535013568
696616963 40162440
696616963 499999993
-499999993 499999993
-499999993 -535013568

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: -100
Wrong Answer
time: 19ms
memory: 3964kb

input:

6666
19
-142 -128 26
-172 -74
-188 -86
-199 -157
-200 -172
-199 -186
-195 -200
-175 -197
-161 -188
-144 -177
-127 -162
-107 -144
-90 -126
-87 -116
-86 -104
-89 -97
-108 -86
-125 -80
-142 -74
-162 -72
16
-161 -161 17
-165 -190
-157 -196
-154 -197
-144 -200
-132 -200
-128 -191
-120 -172
-123 -163
-138...

output:

5093
3086
2539
1546
3535
7421
4883
5711
5624
1034
2479
3920
4372
2044
4996
5070
2251
4382
4175
1489
1154
3231
4038
1631
5086
14444
1692
6066
687
1671
4849
5456
2757
8341
8557
8235
1013
5203
10853
6375
6300
4480
2303
3598
1739
2187
3385
4266
6322
909
4334
1518
948
5036
1449
2376
3180
4810
1976
1786
4...

result:

wrong answer 4th numbers differ - expected: '668', found: '1546'