QOJ.ac
QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #59650 | #1373. Rating Problems | abdelrahman001# | AC ✓ | 2ms | 3856kb | C++20 | 607b | 2022-10-31 17:54:14 | 2022-10-31 17:54:15 |
Judging History
answer
#pragma GCC optimize ("O3")
#pragma GCC optimize ("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#include <bits/stdc++.h>
typedef long long ll;
typedef long double ld;
using namespace std;
const int N = 1e5 + 5;
int n, k;
int main() {
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> k;
int sum = 0;
for(int i = 0;i < k;i++) {
int x;
cin >> x;
sum += x;
}
ld mn = (sum + (n - k) * -3) / (ld)n;
ld mx = (sum + (n - k) * 3) / (ld)n;
cout << fixed << setprecision(9) << mn << " " << mx;
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3664kb
input:
10 0
output:
-3.000000000 3.000000000
result:
ok 2 numbers
Test #2:
score: 0
Accepted
time: 2ms
memory: 3856kb
input:
10 10 3 2 1 0 -1 -2 -3 -2 -1 0
output:
-0.300000000 -0.300000000
result:
ok 2 numbers
Test #3:
score: 0
Accepted
time: 2ms
memory: 3760kb
input:
10 10 0 0 0 0 0 0 0 0 0 0
output:
0.000000000 0.000000000
result:
ok 2 numbers
Test #4:
score: 0
Accepted
time: 2ms
memory: 3648kb
input:
10 10 3 3 3 3 3 3 3 3 3 3
output:
3.000000000 3.000000000
result:
ok 2 numbers
Test #5:
score: 0
Accepted
time: 2ms
memory: 3756kb
input:
10 10 -3 -3 -3 -3 -3 -3 -3 -3 -3 -3
output:
-3.000000000 -3.000000000
result:
ok 2 numbers
Test #6:
score: 0
Accepted
time: 2ms
memory: 3764kb
input:
1 0
output:
-3.000000000 3.000000000
result:
ok 2 numbers
Test #7:
score: 0
Accepted
time: 0ms
memory: 3608kb
input:
1 1 2
output:
2.000000000 2.000000000
result:
ok 2 numbers
Test #8:
score: 0
Accepted
time: 2ms
memory: 3632kb
input:
9 7 1 3 2 2 1 1 2
output:
0.666666667 2.000000000
result:
ok 2 numbers
Test #9:
score: 0
Accepted
time: 2ms
memory: 3852kb
input:
6 4 -2 -1 -2 0
output:
-1.833333333 0.166666667
result:
ok 2 numbers