QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#596086#7736. Red Black TreezhangbojuTL 0ms10436kbC++141.9kb2024-09-28 15:06:172024-09-28 15:06:20

Judging History

你现在查看的是最新测评结果

  • [2024-09-28 15:06:20]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:10436kb
  • [2024-09-28 15:06:17]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const int MAXN=100010;
const int INF=1e9;
int n;
char ch[MAXN];
int col[MAXN];
int cnt[MAXN];
int ans[MAXN];
vector<int> T[MAXN];
priority_queue<int> pq[MAXN];
int mdep[MAXN];
void dfs(int u){
    if(!T[u].size()){
        if(col[u])pq[u].push(1);
        else pq[u].push(-1);
        return;
    }
    bool flag=false;
    for(auto v: T[u]){
        dfs(v);
        cnt[u]+=cnt[v];
        if(!flag){
            swap(pq[u],pq[v]);
            mdep[u]=mdep[v];
            flag=true;
            continue;
        }
        static int tmp[MAXN];
        int len=min(mdep[u],mdep[v]);
        mdep[u]=len+1;
        int sum=0;
        for(int i=0;i<=len;++i){
            tmp[i]=pq[u].top()+pq[v].top();
            pq[u].pop(),pq[v].pop();
        }
        while(!pq[u].empty())pq[u].pop();
        for(int i=0;i<=len;++i){
            pq[u].push(tmp[i]);
            if(tmp[i]>0)sum+=tmp[i];
            tmp[i]=0;
        }
        if(v==T[u].back())ans[u]=cnt[u]-sum;
    }
    if(col[u])pq[u].push(1),ans[u]-=(T[u].size()>1);
    else pq[u].push(-1);
    // priority_queue<int> tmp;
    // tmp=pq[u];
    // cout<<u<<endl;
    // while(!tmp.empty())cout<<tmp.top()<<' ',tmp.pop();
    // cout<<endl;
}
int main(){
    int testcase;
    scanf("%d",&testcase);
    while(testcase--){
        scanf("%d",&n);
        scanf("%s",ch+1);
        for(int i=1;i<=n;++i){
            col[i]=ch[i]-'0';
            cnt[i]=col[i];
        }
        for(int i=2;i<=n;++i){
            int p;
            scanf("%d",&p);
            T[p].push_back(i);
        }
        dfs(1);
        for(int i=1;i<=n;++i){
            printf("%d",ans[i]);
            if(i<n)putchar(' ');
        }
        putchar('\n');
        for(int i=1;i<=n;++i){
            T[i].clear();
            cnt[i]=col[i]=ans[i]=0;
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 10436kb

input:

2
9
101011110
1 1 3 3 3 6 2 2
4
1011
1 1 3

output:

4 1 2 0 0 0 0 0 0
2 0 0 0

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

6107
12
000000001000
1 2 3 2 5 4 4 7 3 8 11
19
1100111101111011110
1 2 1 1 4 5 2 4 3 2 2 7 10 2 11 3 15 5
7
0111110
1 1 2 2 1 5
3
000
1 1
7
1000011
1 2 3 3 5 4
7
0001001
1 1 1 3 5 3
8
00111000
1 1 3 2 5 2 7
11
11111110111
1 1 1 4 5 4 5 2 5 1
15
110101101000010
1 2 3 2 1 5 2 5 6 5 8 7 9 14
10
0101000...

output:


result: