QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#595529#9434. Italian Cuisineucup-team4474#WA 1ms5508kbC++178.3kb2024-09-28 13:54:532024-09-28 13:54:53

Judging History

你现在查看的是最新测评结果

  • [2024-09-28 13:54:53]
  • 评测
  • 测评结果：WA
  • 用时：1ms
  • 内存：5508kb
查看
  • [2024-09-28 13:54:53]
  • 提交

answer

#include <bits/stdc++.h>
#define pb push_back
#define mp make_pair
#define pii pair<int,int>
#define pll pair<long long,long long>
#define FF fflush(stdout)
#define inf 0x3f3f3f3f
#define endl "\n"
#define fi first
#define se second
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
//char buf[1<<20],*p1,*p2;
//#define getchar() (p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<20,stdin),p1==p2)?EOF:*p1++)
inline int read()
{
    int s=0,f=1;
    char x=getchar();
    while(!isdigit(x))f=(x=='-'?-1:1),x=getchar();
    while(isdigit(x))s=s*10+x-'0',x=getchar();
    return s*f;
}
#define reaD read
using i64 = long long;
template<class T>
struct Point {
    T x;
    T y;
    Point(const T &x_ = 0, const T &y_ = 0) : x(x_), y(y_) {}
    
    template<class U>
    operator Point<U>() {
        return Point<U>(U(x), U(y));
    }
    Point &operator+=(const Point &p) & {
        x += p.x;
        y += p.y;
        return *this;
    }
    Point &operator-=(const Point &p) & {
        x -= p.x;
        y -= p.y;
        return *this;
    }
    Point &operator*=(const T &v) & {
        x *= v;
        y *= v;
        return *this;
    }
    Point &operator/=(const T &v) & {
        x /= v;
        y /= v;
        return *this;
    }
    Point operator-() const {
        return Point(-x, -y);
    }
    friend Point operator+(Point a, const Point &b) {
        return a += b;
    }
    friend Point operator-(Point a, const Point &b) {
        return a -= b;
    }
    friend Point operator*(Point a, const T &b) {
        return a *= b;
    }
    friend Point operator/(Point a, const T &b) {
        return a /= b;
    }
    friend Point operator*(const T &a, Point b) {
        return b *= a;
    }
    friend bool operator==(const Point &a, const Point &b) {
        return a.x == b.x && a.y == b.y;
    }
    friend std::istream &operator>>(std::istream &is, Point &p) {
        return is >> p.x >> p.y;
    }
    friend std::ostream &operator<<(std::ostream &os, const Point &p) {
        return os << "(" << p.x << ", " << p.y << ")";
    }
};

template<class T>
struct Line {
    Point<T> a;
    Point<T> b;
    Line(const Point<T> &a_ = Point<T>(), const Point<T> &b_ = Point<T>()) : a(a_), b(b_) {}
};

template<class T>
T dot(const Point<T> &a, const Point<T> &b) {
    return a.x * b.x + a.y * b.y;
}

template<class T>
T cross(const Point<T> &a, const Point<T> &b) {
    return a.x * b.y - a.y * b.x;
}

template<class T>
T square(const Point<T> &p) {
    return dot(p, p);
}

template<class T>
double length(const Point<T> &p) {
    return std::sqrt(square(p));
}

template<class T>
double length(const Line<T> &l) {
    return length(l.a - l.b);
}

template<class T>
Point<T> normalize(const Point<T> &p) {
    return p / length(p);
}

template<class T>
bool parallel(const Line<T> &l1, const Line<T> &l2) {
    return cross(l1.b - l1.a, l2.b - l2.a) == 0;
}

template<class T>
double distance(const Point<T> &a, const Point<T> &b) {
    return length(a - b);
}

template<class T>
double distancePL(const Point<T> &p, const Line<T> &l) {
    return std::abs(cross(l.a - l.b, l.a - p)) / length(l);
}

template<class T>
double distancePS(const Point<T> &p, const Line<T> &l) {
    if (dot(p - l.a, l.b - l.a) < 0) {
        return distance(p, l.a);
    }
    if (dot(p - l.b, l.a - l.b) < 0) {
        return distance(p, l.b);
    }
    return distancePL(p, l);
}

template<class T>
Point<T> rotate(const Point<T> &a) {
    return Point(-a.y, a.x);
}

template<class T>
int sgn(const Point<T> &a) {
    return a.y > 0 || (a.y == 0 && a.x > 0) ? 1 : -1;
}

template<class T>
bool pointOnLineLeft(const Point<T> &p, const Line<T> &l) {
    return cross(l.b - l.a, p - l.a) > 0;
}

template<class T>
Point<T> lineIntersection(const Line<T> &l1, const Line<T> &l2) {
    return l1.a + (l1.b - l1.a) * (cross(l2.b - l2.a, l1.a - l2.a) / cross(l2.b - l2.a, l1.a - l1.b));
}

template<class T>
bool pointOnSegment(const Point<T> &p, const Line<T> &l) {
    return cross(p - l.a, l.b - l.a) == 0 && std::min(l.a.x, l.b.x) <= p.x && p.x <= std::max(l.a.x, l.b.x)
        && std::min(l.a.y, l.b.y) <= p.y && p.y <= std::max(l.a.y, l.b.y);
}

template<class T>
bool pointInPolygon(const Point<T> &a, const std::vector<Point<T>> &p) {
    int n = p.size();
    for (int i = 0; i < n; i++) {
        if (pointOnSegment(a, Line(p[i], p[(i + 1) % n]))) {
            return true;
        }
    }
    
    int t = 0;
    for (int i = 0; i < n; i++) {
        auto u = p[i];
        auto v = p[(i + 1) % n];
        if (u.x < a.x && v.x >= a.x && pointOnLineLeft(a, Line(v, u))) {
            t ^= 1;
        }
        if (u.x >= a.x && v.x < a.x && pointOnLineLeft(a, Line(u, v))) {
            t ^= 1;
        }
    }
    
    return t == 1;
}

// 0 : not intersect
// 1 : strictly intersect
// 2 : overlap
// 3 : intersect at endpoint
template<class T>
std::tuple<int, Point<T>, Point<T>> segmentIntersection(const Line<T> &l1, const Line<T> &l2) {
    if (std::max(l1.a.x, l1.b.x) < std::min(l2.a.x, l2.b.x)) {
        return {0, Point<T>(), Point<T>()};
    }
    if (std::min(l1.a.x, l1.b.x) > std::max(l2.a.x, l2.b.x)) {
        return {0, Point<T>(), Point<T>()};
    }
    if (std::max(l1.a.y, l1.b.y) < std::min(l2.a.y, l2.b.y)) {
        return {0, Point<T>(), Point<T>()};
    }
    if (std::min(l1.a.y, l1.b.y) > std::max(l2.a.y, l2.b.y)) {
        return {0, Point<T>(), Point<T>()};
    }
    if (cross(l1.b - l1.a, l2.b - l2.a) == 0) {
        if (cross(l1.b - l1.a, l2.a - l1.a) != 0) {
            return {0, Point<T>(), Point<T>()};
        } else {
            auto maxx1 = std::max(l1.a.x, l1.b.x);
            auto minx1 = std::min(l1.a.x, l1.b.x);
            auto maxy1 = std::max(l1.a.y, l1.b.y);
            auto miny1 = std::min(l1.a.y, l1.b.y);
            auto maxx2 = std::max(l2.a.x, l2.b.x);
            auto minx2 = std::min(l2.a.x, l2.b.x);
            auto maxy2 = std::max(l2.a.y, l2.b.y);
            auto miny2 = std::min(l2.a.y, l2.b.y);
            Point<T> p1(std::max(minx1, minx2), std::max(miny1, miny2));
            Point<T> p2(std::min(maxx1, maxx2), std::min(maxy1, maxy2));
            if (!pointOnSegment(p1, l1)) {
                std::swap(p1.y, p2.y);
            }
            if (p1 == p2) {
                return {3, p1, p2};
            } else {
                return {2, p1, p2};
            }
        }
    }
    auto cp1 = cross(l2.a - l1.a, l2.b - l1.a);
    auto cp2 = cross(l2.a - l1.b, l2.b - l1.b);
    auto cp3 = cross(l1.a - l2.a, l1.b - l2.a);
    auto cp4 = cross(l1.a - l2.b, l1.b - l2.b);
    
    if ((cp1 > 0 && cp2 > 0) || (cp1 < 0 && cp2 < 0) || (cp3 > 0 && cp4 > 0) || (cp3 < 0 && cp4 < 0)) {
        return {0, Point<T>(), Point<T>()};
    }
    
    Point p = lineIntersection(l1, l2);
    if (cp1 != 0 && cp2 != 0 && cp3 != 0 && cp4 != 0) {
        return {1, p, p};
    } else {
        return {3, p, p};
    }
}

template<class T>
double distanceSS(const Line<T> &l1, const Line<T> &l2) {
    if (std::get<0>(segmentIntersection(l1, l2)) != 0) {
        return 0.0;
    }
    return std::min({distancePS(l1.a, l2), distancePS(l1.b, l2), distancePS(l2.a, l1), distancePS(l2.b, l1)});
}



using P = Point<i64>;



P a[100005];
i64 cal(int x,int y,int z)
{
	return abs(cross(a[y]-a[x],a[z]-a[x]));
}
int main()
{
	int T=reaD();
	while(T--)
	{
		int n=reaD();
		int rx=read(),ry=reaD(),rd=reaD();
		P cir=P(rx,ry);
		for(int i=1;i<=n;i++)
		{
			int x=reaD(),y=reaD();
			a[i]=P(x,y);
		}
		ll ans=0;
		ll ansl=0,ansr=0;
		int l=2;
		while(l<=n&&distancePL(cir,Line(a[1],a[l]))>=rd)ansl+=cal(1,l,l-1),l++;
		assert(l<n);
		int r=l;
		while(r<=n&&distancePL(cir,Line(a[1],a[r]))<rd)r++;
		for(int i=r;i<n;i++)
		ansr+=cal(1,i,i+1);
		ans=max(ans,max(ansl,ansr));
		
		for(int i=2;i<=n;i++)
		{
		    ansr+=cal(i,i-1,r);
		    ansl-=cal(i,i-1,l==1?n:l-1);
			while(pointOnLineLeft(cir,Line(a[i],a[l]))&&distancePL(cir,Line(a[i],a[l]))>=rd)ansl+=cal(i,l,l==1?n:l-1),l=l%n+1;
			while(pointOnLineLeft(cir,Line(a[i],a[r]))||distancePL(cir,Line(a[i],a[r]))<rd)ansr-=cal(i,r,r%n+1),r=r%n+1;
			ans=max(ans,max(ansl,ansr));//cout<<i<<" "<<l<<" "<<r-1<<" "<<ansl<<" "<<ansr<<endl;
		}
		printf("%lld\n",ans);
	}
}
源文件, 语言: C++17

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 5456kb

input:

3
5
1 1 1
0 0
1 0
5 0
3 3
0 5
6
2 4 1
2 0
4 0
6 3
4 6
2 6
0 3
4
3 3 1
3 0
6 3
3 6
0 3

output:

5
24
0

result:

ok 3 number(s): "5 24 0"

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 5508kb

input:

1
6
0 0 499999993
197878055 -535013568
696616963 -535013568
696616963 40162440
696616963 499999993
-499999993 499999993
-499999993 -535013568

output:

286862654137719264

result:

wrong answer 1st numbers differ - expected: '0', found: '286862654137719264'
English 繁體中文 简体中文

伺服器時間: 2025-01-22 19:09:27 | 開源專案