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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#595064#8037. Gambler's RuinYu_mxWA 1ms6004kbC++141.3kb2024-09-28 12:21:532024-09-28 12:21:54

Judging History

你现在查看的是最新测评结果

  • [2024-09-28 12:21:54]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:6004kb
  • [2024-09-28 12:21:53]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define ios ios::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#define endl '\n'

const int N = 1e6+5;

struct gambler{
	double p;
	ll c;
	bool operator < (gambler &x) const{
		return p>x.p||(p==x.p&&c>x.c);
	} 
}a[N];

ll pre[N];
ll n;
double ans = 0.0;

double calc(int i,int j){
//	if(j<=0||j>n) return -1e15;
	if(a[i].p+1.0-a[j].p<=1.0) return -1e20;
	double x = 1.0/a[i].p;
	double sx = 1.0*pre[i];
	double y = 1.0/(1.0-a[j].p);
	double sy = 1.0*(pre[n]-pre[j-1]);
	double t = (sx+sy-1.0*max(sx*x,sy*y));
	ans = max(ans,t);
	return t;
}

void solve(){
	cin>>n;
	for(int i=1;i<=n;i++) cin>>a[i].p>>a[i].c;
	sort(a+1,a+1+n);
	pre[0] = 0;
	for(int i=1;i<=n;i++) pre[i] = pre[i-1]+a[i].c;
	//double ans = 0.0;
	for(int i=1;i<=n-1;i++){
		ll l = 1, r = n;
		double anst = max(calc(i,l),calc(i,r));
		while(l<=r){
			int lmid = l+(r-l)/3;
			int rmid = r-(r-l)/3;
			//cout<<lmid<<' '<<calc(i,lmid)<<endl;
			//cout<<rmid<<' '<<calc(i,rmid)<<endl;
			if(calc(i,lmid) <= calc(i,rmid)) l = lmid+1;
			else r = rmid-1;
		}
		anst = max(calc(i,l),calc(i,r));
		ans = max(ans,anst);
		//cout<<anst<<endl;
	}
	//cout<<calc(1,3)<<endl;
	cout<<fixed<<setprecision(10)<<ans<<endl;
} 

int main(){
	ios;
	//ll T;cin>>T;while(T--)
	solve();
	return 0;
} 

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 5908kb

input:

2
1 15
0 10

output:

10.0000000000

result:

ok found '10.0000000', expected '10.0000000', error '0.0000000'

Test #2:

score: 0
Accepted
time: 1ms
memory: 5912kb

input:

3
0.4 100
0.5 100
0.6 100

output:

33.3333333333

result:

ok found '33.3333333', expected '33.3333333', error '0.0000000'

Test #3:

score: 0
Accepted
time: 1ms
memory: 6004kb

input:

1
0 1

output:

0.0000000000

result:

ok found '0.0000000', expected '0.0000000', error '-0.0000000'

Test #4:

score: 0
Accepted
time: 1ms
memory: 5900kb

input:

2
1 0
1 100

output:

0.0000000000

result:

ok found '0.0000000', expected '0.0000000', error '-0.0000000'

Test #5:

score: 0
Accepted
time: 1ms
memory: 5960kb

input:

1
0.5 100

output:

0.0000000000

result:

ok found '0.0000000', expected '0.0000000', error '-0.0000000'

Test #6:

score: -100
Wrong Answer
time: 1ms
memory: 5908kb

input:

3
0.4 100
0.6 100
0.6 100

output:

33.3333333333

result:

wrong answer 1st numbers differ - expected: '0.0000000', found: '33.3333333', error = '33.3333333'