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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#594352#9302. Caesar Cipherzqx#WA 11ms15188kbC++233.7kb2024-09-27 22:02:332024-09-27 22:02:34

Judging History

你现在查看的是最新测评结果

  • [2024-11-04 17:10:09]
  • hack成功,自动添加数据
  • (/hack/1110)
  • [2024-10-21 09:47:48]
  • hack成功,自动添加数据
  • (/hack/1022)
  • [2024-10-21 09:39:50]
  • hack成功,自动添加数据
  • (/hack/1021)
  • [2024-10-21 09:31:34]
  • hack成功,自动添加数据
  • (/hack/1020)
  • [2024-10-03 10:14:59]
  • hack成功,自动添加数据
  • (/hack/928)
  • [2024-09-28 07:51:27]
  • hack成功,自动添加数据
  • (/hack/922)
  • [2024-09-28 07:42:39]
  • hack成功,自动添加数据
  • (/hack/921)
  • [2024-09-27 22:02:34]
  • 评测
  • 测评结果:WA
  • 用时:11ms
  • 内存:15188kb
  • [2024-09-27 22:02:33]
  • 提交

answer

#include <bits/stdc++.h>

#define int long long

using namespace std;

const int N = 5e5 + 10;
const int lim = 65536;
const int base = 13331;
const int mod1 = 1e9 + 7;
const int mod2 = 998244353;

int n;
int a[N];
int pw[N], ppw[N];

struct Segment_Tree 
{
    static const int N = 5e5 + 10;

    int mod;
    void Init(int x)
    {
        mod = x;
        pw[0] = 1;
        for (int i = 1; i < N; i++)
        {
            pw[i] = pw[i - 1] * base % mod;
            (ppw[i] = ppw[i - 1] + pw[i]) %= mod;
        }
    }

    struct node {
        int l, r;
        int hash, mx;
        int lazy;
    }t[N << 2];

    #define ls(x) (x << 1)
    #define rs(x) (x << 1 | 1)

    void Pushup(int p)
    {
        t[p].mx = max(t[ls(p)].mx, t[rs(p)].mx);
        t[p].hash = (t[ls(p)].hash * pw[t[rs(p)].r - t[rs(p)].l + 1] % mod + t[rs(p)].hash) % mod;
    }

    void Build(int p, int l, int r)
    {
        t[p].l = l, t[p].r = r;
        if (l == r) {
            t[p].hash = a[l] + 1;
            return ;
        }
        int mid = (l + r) >> 1;
        Build(ls(p), l, mid);
        Build(rs(p), mid + 1, r);
        Pushup(p);
    }

    void Pushdown(int p)
    {
        int lz = t[p].lazy;
        if (lz == 0)
           return ;
        t[ls(p)].lazy += lz;
        t[rs(p)].lazy += lz;
        (t[ls(p)].hash += lz * ppw[t[ls(p)].r - t[ls(p)].l] % mod) %= mod;
        (t[rs(p)].hash += lz * ppw[t[rs(p)].r - t[rs(p)].l] % mod) %= mod;
        t[p].lazy = 0;
    }

    void Update(int p, int l, int r, int v)
    {
        if (t[p].l == t[p].r)
        {
            (t[p].hash += v) %= lim;
            (t[p].mx += v) %= lim;
            return ;
        }

        if (l <= t[p].l && r >= t[p].r)
        {
            if (t[p].mx < lim - 1)
            {
                t[p].lazy += v;
                (t[p].hash += v * ppw[t[p].r - t[p].l] % mod) %= mod;
                return ;
            }
        }
        Pushdown(p);
        int mid = (t[p].l + t[p].r) >> 1;
        if (l <= mid)
            Update(ls(p), l, r, v);
        if (r > mid)
            Update(rs(p), l, r, v);
        Pushup(p);
    }

    int Query(int p, int l, int r)
    {
        if (l <= t[p].l && r >= t[p].r) 
        {
            return t[p].hash;
        }
        Pushdown(p);
        int mid = (t[p].l + t[p].r) >> 1;
        int res = 0;
        if (l > mid)
            res = Query(rs(p), l, r);
        else if(r <= mid)
            res = Query(ls(p), l, r);
        else 
            res = (Query(ls(p), l, mid) * pw[r - mid] % mod + Query(rs(p), mid + 1, r)) % mod;
        return res;
    }
}sgt1, sgt2;

void Solve()
{
    int q;
    cin >> n >> q;
    for (int i = 1; i <= n; i++)
        cin >> a[i];
    sgt1.Build(1, 1, n);
    sgt2.Build(1, 1, n);
    while (q--)
    {
        int opt;
        cin >> opt;
        if (opt == 1)
        {
            int l, r;
            cin >> l >> r;
            sgt1.Update(1, l, r, 1);
            sgt2.Update(1, l, r, 1);
        }
        else 
        {
            int l1, r1, l2, r2, len;
            cin >> l1 >> l2 >> len;
            r1 = l1 + len - 1; r2 = l2 + len - 1;
            bool ok1 = (sgt1.Query(1, l1, r1) == sgt1.Query(1, l2, r2));
            bool ok2 = (sgt2.Query(1, l1, r1) == sgt2.Query(1, l2, r2));
            cout << ((ok1 && ok2) ? "yes\n" : "no\n");
        }
    }
    return ;
}

signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    int T = 1;
    // cin >> T;
    sgt1.Init(mod1);
    sgt2.Init(mod2);
    while(T--)
    {
        Solve();
    }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 11ms
memory: 13904kb

input:

5 6
1 2 1 2 1
2 1 2 2
2 1 3 3
1 1 1
1 3 5
2 1 2 4
2 1 2 2

output:

no
yes
no
yes

result:

ok 4 token(s): yes count is 2, no count is 2

Test #2:

score: 0
Accepted
time: 11ms
memory: 15188kb

input:

3 3
0 65535 65535
2 1 2 2
1 2 3
2 1 2 2

output:

no
yes

result:

ok 2 token(s): yes count is 1, no count is 1

Test #3:

score: -100
Wrong Answer
time: 7ms
memory: 14508kb

input:

1000 1000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

output:

no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
yes
no
no
no
no
no
no
no
no
no
no
no
no
yes
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
yes
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
yes
no
no
yes
no
no
no
yes
no
no
no
no
no
...

result:

wrong answer expected YES, found NO [1st token]