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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#591734 | #7079. Array | Afterlife# | TL | 1ms | 7660kb | C++20 | 2.7kb | 2024-09-26 17:28:52 | 2024-09-26 17:28:52 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
int n ;
int a[1000005];
typedef long long ll;
typedef pair<int,int> pii;
ll S(int x) {
return 1LL * x * (x + 1) / 2;
}
struct bit {
ll c[1000005];
int n;
void init(int _n) {
n = _n;
for(int i = 1;i <= n;i++) c[i] = 1e18;
}
void upd(int x,ll y) {
while(x <= n) {
c[x] = min(c[x] , y);
x += (x & -x);
}
}
ll qry(int x) {
ll ans = 1e18;
while(x) {
ans = min(ans , c[x]) ;
x -= (x & -x);
}
return ans;
}
}b[2];
void solv() {
cin >> n;
for(int i = 1;i <= n;i++) cin >> a[i];
ll ans = 0;
set<int> st;
for(int i = 1;i <= n;i++) {
st.insert(a[i]) ;
ans += 1LL * i * st.size() ;
}
map<int,vector<int> > mp;
vector<int> v;
for(int i = 1 ; i <= n;i++) mp[a[i]].push_back(i) , v.push_back(a[i]);
sort(v.begin() , v.end()) ;
v.erase(unique(v.begin() , v.end()) , v.end()) ;
vector<pii> p;
for(auto &[x,y] : mp) p.push_back({y[0] , x}) ;
sort(p.begin() , p.end()) ;
st.clear() ;
ll sol = 0;
auto qmin = [&](int x) ->ll {
if(st.size() == 0) return 1e18;
auto it = st.lower_bound(x) ;
ll ans = 1e18;
if(it != st.end()) ans = min(ans , (ll)abs(x - (*it))) ;
if(it != st.begin()) {
it-- ;
ans = min(ans , (ll)abs(x - (*it))) ;
}
return ans;
};
for(int i = 0;i < p.size();i++) {
auto &v = mp[p[i].second] ;
int b2;
if(v.size() == 1) b2 = n + 1;
else b2 = v[1];
ll dec = S(b2 - 1) - S(v[0] - 1) ;
ll cur = qmin(p[i].second) - dec ;
sol = min(sol , cur) ;
st.insert(p[i].second) ;
}
b[0].init(v.size()) ;
b[1].init(v.size()) ;
for(int i = p.size() - 1 ; i >= 0;i--) {
auto &v = mp[p[i].second] ;
int b2 , b1 = p[i].first;
if(v.size() == 1) b2 = n + 1;
else b2 = v[1];
int bpos = lower_bound(v.begin() , v.end() , p[i].second) - v.begin() + 1;
/// if a > b , a - b - S(b2-1) + S(a1)
sol = min(sol , -S(b2 - 1) - p[i].second + b[0].qry(v.size() - bpos + 1)) ;
b[0].upd(v.size() - bpos + 1 , p[i].second + S(b1)) ;
/// if a < b , b - a - S(b2-1) + S(a1)
sol = min(sol , p[i].second - S(b2 - 1) + b[1].qry(bpos)) ;
b[1].upd(bpos , -p[i].second + S(b1)) ;
}
cout << ans + sol << '\n' ;
return ;
}
int main() {
ios::sync_with_stdio(false) ; cin.tie(0) ;
int t;cin >> t;
while(t--) solv() ;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 7660kb
input:
1 4 1 2 3 4
output:
22
result:
ok "22"
Test #2:
score: -100
Time Limit Exceeded
input:
100000 10 873324878 873324878 873324878 873324878 891656676 891656676 615245360 873324878 873324878 873324878 10 560723194 560723194 797429144 797429144 560723194 797429144 819647695 560723194 797429144 560723194 10 750627649 746781323 756277046 756277046 750627649 750627649 756277046 750627649 9142...