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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#590132 | #8237. Sugar Sweet II | ucup-team3294 | WA | 172ms | 21972kb | C++20 | 2.8kb | 2024-09-25 21:50:38 | 2024-09-25 21:50:38 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
const int N=5e5+10;
const int mod=1e9+7;
#define ll long long
struct node
{
int to;
};
vector<node> h[N];
int dis[N];
int n;
int a[N],b[N],w[N];
int d[N];
ll fact[N],infact[N];
int ans=0;
int color[N];
int kk[N];
ll qmi(ll a,ll b,ll p)
{
ll cnt=1;
while(b)
{
if(b&1) cnt=(cnt*a)%mod;
b>>=1;
a=(a*a)%mod;
}
return cnt;
}
void add(int a,int b)
{
h[a].push_back({b});
d[b]++;
}
void bfs(int pos)
{
queue<int> q;
q.push(pos);
dis[pos]=1;
while(q.size())
{
auto t=q.front();
q.pop();
for(int i=0;i<h[t].size();i++)
{
int j=h[t][i].to;
if(dis[j]!=0) continue;
dis[j]=dis[t]+1;
d[j]--;
kk[j]=infact[dis[j]]*(a[j]+w[j])%mod+(1-infact[dis[j]]+mod)%mod*a[j]%mod;
// ans=(ans+infact[dis[j]]*w[j]%mod)%mod;
q.push(j);
}
}
}
void solve()
{
for(int i=1;i<=n;i++)
{
h[i].clear();
d[i]=0;
dis[i]=0;
color[i]=0;
}
ans=0;
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a[i];
}
for(int i=1;i<=n;i++)
{
cin>>b[i];
}
for(int i=1;i<=n;i++)
{
cin>>w[i];
}
for(int i=1;i<=n;i++)
{
if(a[b[i]]<=a[i]&&a[b[i]]+w[b[i]]>a[i]) //可能加
{
color[i]=3;
}
else if(a[b[i]]<=a[i]&&a[b[i]]+w[b[i]]<=a[i]) //不加
{
color[i]=2;
}
else color[i]=1; //加
}
for(int i=1;i<=n;i++)
{
//cout<<color[i]<<"aa";
if(color[i]==2) kk[i]=a[i];
else if(color[i]==1) kk[i]=(w[i]+a[i])%mod;
else
{
if(color[b[i]]==1||color[b[i]]==3)
{
add(b[i],i);
// cout<<b[i]<<"aa"<<i<<endl;
}
else
{
kk[i]=a[i];
}
}
}
// cout<<endl;
for(int i=1;i<=n;i++)
{
if(dis[i]==0&&d[i]==0&&color[i]==1)
{
bfs(i);
//cout<<i<<"aa"<<endl;
}
}
for(int i=1;i<=n;i++)
{
if(d[i]!=0)
{
kk[i]=a[i];
}
}
for(int i=1;i<=n;i++)
{
cout<<kk[i]<<' ';
}
cout<<endl;
}
signed main()
{
//cout<<qmi(2,mod-2,mod)<<endl;
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int T;
cin>>T;
fact[0]=infact[0]=1;
for(ll i=1;i<N;i++) //此处不能取到N,否则数组越界
{
fact[i]=(fact[i-1]*i)%mod;
infact[i]=(infact[i-1]*qmi(i,mod-2,mod))%mod;
}
while(T--)
{
solve();
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 53ms
memory: 21972kb
input:
4 4 2 5 5 2 4 2 1 3 3 2 1 4 3 5 4 3 1 1 1 6 6 6 3 5 4 3 2 3 1 1 2 3 5 2 1 3 2 1 5 1 1 3 4 1 3 4 2 4
output:
500000007 5 5 6 5 10 9 166666673 5 6 500000006 4 3 4 5
result:
ok 15 numbers
Test #2:
score: -100
Wrong Answer
time: 172ms
memory: 21928kb
input:
50000 5 508432375 168140163 892620793 578579275 251380640 3 4 4 1 3 346232959 736203130 186940774 655629320 607743104 1 863886789 1 364158084 18 864679185 463975750 558804051 604216585 694033700 499417132 375390750 337590759 467353355 111206671 983760005 984444619 322277587 138763925 205122047 97736...
output:
854665334 904343293 590444253 906393935 859123744 863886789 871186919 814243920 968784984 206455474 1017527057 449261413 196759729 901433117 519383814 907574792 983760005 984444619 489899014 435736558 113628626 977360756 482247153 963066959 665922935 577926775 1132646730 421298438 601054667 99438...
result:
wrong answer 11th numbers differ - expected: '17527050', found: '1017527057'