QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#590078#6837. AC Automatoncyj888RE 4ms21672kbC++116.2kb2024-09-25 21:26:072024-09-25 21:26:16

Judging History

你现在查看的是最新测评结果

  • [2024-09-25 21:26:16]
  • 评测
  • 测评结果:RE
  • 用时:4ms
  • 内存:21672kb
  • [2024-09-25 21:26:07]
  • 提交

answer

#include <bits/stdc++.h>
#define ott(i,l,r) for (register int i = l; i <= r; ++ i)
#define read(x) {x = 0; char c; while ((c = getchar ()) < 48); do x = (x << 3) + (x << 1) + (c ^ 48); while ((c = getchar ()) > 47);}
#define print() {long long x = res; len = 0; if (!x) putchar (48); while (x) pc[++ len] = x % 10, x /= 10; while (len) putchar (pc[len --] + 48); putchar ('\n');}
#define cdn1(ttu) {int tu, u = ttu; while (u) {if (u <= LIM) {tu = val[u]; if (!(ch[tu] ^ '?')) res -= Max (dn[tu] - up[tu]); ++ dn[tu]; if (ch[tu] == 'A') ++ res; if (!(ch[tu] ^ '?')) res += Max (dn[tu] - up[tu]);} else b[u - LIM].add2 (), res += b[u - LIM].ac; u = FA[u];}}
#define cdn2(ttu) {int tu, u = ttu; while (u) {if (u <= LIM) {tu = val[u]; if (!(ch[tu] ^ '?')) res -= Max (dn[tu] - up[tu]); -- dn[tu]; if (ch[tu] == 'A') -- res; if (!(ch[tu] ^ '?')) res += Max (dn[tu] - up[tu]);} else b[u - LIM].add1 (), res -= b[u - LIM].ac; u = FA[u];}}
using namespace std;
const int N = 3e5 + 110, B = 800, inf = 0x3f3f3f3f;
int n, m, q, idx, len, Z, OTH, LIM;
long long res; char pc[65];
vector <int> e[N], E[B << 2];
int up[N], dn[N], dfn[N], dep[N], fa[N], lg[N << 1], f[N << 1][21];
char ch[N];
void dfs0 (int u) {
	f[dfn[u] = ++ idx][0] = u, dep[u] = dep[fa[u]] + 1;
	for (int v : e[u]) {
		dfs0 (v);
		f[++ idx][0] = u;
	}
	return ;
}
inline int lca (int x, int y) {
	x = dfn[x], y = dfn[y]; if (x > y) swap (x, y);
	Z = lg[y - x + 1], x = f[x][Z], y = f[y - (1 << Z) + 1][Z];
	return dep[x] < dep[y] ? x : y;
}
struct OPT {
	int x; char c;
} a[B + 1];
struct BLOCK {
	int ac, now, val, sum;//ac = 'A'count
	vector <int> s; vector <pair <int, int> > t;
	inline void upd (int i) {
		if (!(ch[i] ^ 'A')) ++ ac;
		if (!(ch[i] ^ '?')) {
			i = dn[i] - up[i];
			if (i >= 0) ++ sum;
			if (-m <= i && i <= m) s.emplace_back (i);
		}
		return ;
	}
	inline void init () {
		t.emplace_back (-inf, 0);
		if (s.size ()) {
			sort (s.begin (), s.end ());
			ott (i, 0, s.size () - 1) {
	        	int cnt = 1; while (i + 1 < s.size () && !(s[i] ^ s[i + 1])) ++ i, ++ cnt;
	        	t.emplace_back (s[i], cnt);
			}
		}
		t.emplace_back (inf, 0);
		int l = 0, r = t.size () - 1, mid;
		while (l <= r) {
			mid = l + r >> 1;
			if (t[mid].first >= 0) now = mid, r = mid - 1;
			else l = mid + 1;
		}
		return ;
	}
	inline void add1 () {
		if (!(t[now].first ^ val ++)) sum -= t[now ++].second; res -= 1ll * sum;
		return ;
	}
	inline void add2 () {
		res += 1ll * sum; if (!(t[now - 1].first ^ -- val)) sum += t[-- now].second;
		return ;
	}
	inline void clear () {
		ac = now = val = sum = 0, vector <int> ().swap (s), vector <pair <int, int> > ().swap (t);
		return ;
	}
} b[B << 1 | 1];
int id[N], val[B << 2], FA[B << 2];
inline int Max (const int &x) {
	return x > 0 ? x : 0;
}
inline bool cmp (const int &x, const int &y) {
	return dfn[x] < dfn[y];
}
inline void push (int u) {
	b[OTH].upd (u); for (int v : e[u]) push (v); 
	return ;
}
inline void find (int x) {
	if (id[fa[x]]) {
		val[Z = id[x] = ++ idx] = x, Z -= LIM;
		return ;
	}
	find (fa[x]), b[Z].upd (fa[x]);
	for (int v : e[fa[x]]) {
		if (!(v ^ x)) continue;
		if (!OTH) val[OTH = id[v] = ++ idx] = v, OTH -= LIM;
		push (v);
	}
	return ;
} 
inline void red (int u) {
	dn[u] = 0;
	for (int v : e[u]) {
		up[v] = up[u]; if (ch[u] ^ 'C') ++ up[v];
		red (v);
		dn[u] += dn[v]; if (ch[v] ^ 'A') ++ dn[u];
	}
	if (!(ch[u] ^ 'A')) res += 1ll * dn[u];
	if (!(ch[u] ^ '?')) res += 1ll * Max (dn[u] - up[u]);
	return ;
}
inline void cup1 (int u) {
	for (int v : E[u]) {
		if (v <= LIM) {
			int tv = val[v];
			if (!(ch[tv] ^ '?')) res -= 1ll * Max (dn[tv] - up[tv]);
			++ up[tv];
			if (!(ch[tv] ^ '?')) res += 1ll * Max (dn[tv] - up[tv]);
		}
		else b[v - LIM].add1 ();
		cup1 (v);
	}
	return ;
}
inline void cup2 (int u) {
	for (int v : E[u]) {
		if (v <= LIM) {
			int tv = val[v];
			if (!(ch[tv] ^ '?')) res -= 1ll * Max (dn[tv] - up[tv]);
			-- up[tv];
			if (!(ch[tv] ^ '?')) res += 1ll * Max (dn[tv] - up[tv]);
		}
		else b[v - LIM].add2 ();
		cup2 (v);
	}
	return ;
}
inline void sol () {
    ott (i, 1, m) val[i] = a[i].x; 
	idx = m, sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1, sort (val + 1, val + 1 + idx, cmp);
    ott (i, 2, idx) val[idx + i - 1] = lca (val[i - 1], val[i]); 
	val[idx += idx] = 1, sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
    ott (i, 1, idx) id[val[i]] = i; LIM = idx;
    ott (i, 2, LIM) {
    	if (!id[fa[val[i]]]) {
    		OTH = 0, find (val[i]);
    		if (OTH) OTH += LIM, E[FA[OTH] = i].emplace_back (OTH);
    		Z += LIM, E[FA[Z] = id[fa[val[Z]]]].emplace_back (Z), E[FA[i] = Z].emplace_back (i);
		}
		else E[FA[i] = id[fa[val[i]]]].emplace_back (i);
	}
	ott (i, 1, LIM) {
		OTH = 0; for (int v : e[val[i]]) {
			if (id[v]) continue;
			if (!OTH) {
				val[OTH = id[v] = ++ idx] = v;
				E[FA[OTH] = i].emplace_back (OTH), OTH -= LIM;
			}
			push (v);
		}
	}
	Z = idx - LIM; ott (i, 1, Z) b[i].init ();
	ott (i, 1, m) {
		int x = a[i].x; char c = a[i].c;
		if (ch[x] ^ 'C') cup2 (id[x]); if (ch[x] ^ 'A') cdn2 (FA[id[x]]);
		if (!(ch[x] ^ 'A')) res -= 1ll * dn[x];
		if (!(ch[x] ^ '?')) res -= 1ll * Max (dn[x] - up[x]);
		ch[x] = c;
		if (!(ch[x] ^ 'A')) res += 1ll * dn[x];
		if (!(ch[x] ^ '?')) res += 1ll * Max (dn[x] - up[x]);
		if (ch[x] ^ 'C') cup1 (id[x]); if (ch[x] ^ 'A') cdn1 (FA[id[x]]);
		print ();
	}
	ott (i, 1, idx) E[i].clear (), FA[i] = 0, id[val[i]] = 0, val[i] = 0;
	Z = idx - LIM, m = idx = 0, res = 0, red (1); ott (i, 1, Z) b[i].clear ();
	return ;
}
int main () {
	//freopen ("data.in", "r", stdin); freopen ("res.out", "w", stdout);
	read (n); read (q); scanf ("%s", ch + 1); ott (i, 2, n) {
		read (fa[i]); e[fa[i]].emplace_back (i);
	}
	dfs0 (1), red (1);
	ott (j, 1, 20) {
		ott (i, 1, idx - (1 << j) + 1) {
			OTH = f[i][j - 1], LIM = f[i + (1 << j - 1)][j - 1];
			f[i][j] = dep[OTH] < dep[LIM] ? OTH : LIM;
		}
	}
	assert (idx <= 1024 * 1024 / 2);
	lg[0] = -1;	ott (i, 1, idx) lg[i] = lg[i >> 1] + 1; idx = 0;
	int x; char c;
	ott (i, 1, q) {
		read (x); c = getchar ();
		a[++ m] = {x, c};
		if (!(i % B) || !(i ^ q)) sol ();
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 21672kb

input:

5 3
AC??C
1 2 2 1
1 ?
4 A
2 ?

output:

4
3
3

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 4ms
memory: 19088kb

input:

1000 1000
AC?ACCCCC?CCA??CCCCC?A?AC?C??C?ACCCACC?C?CCC?CACACA???????C?????CC?C?AAAAACCA??AAAACACACA???AACAC?CCC?CAC?AAAACCAC???ACAA??A??A?CA?A?ACACACCAA?ACACA?AC??AC??ACAAACCC??CAA?A???CC?AA??AC???A?CCCC??CACCAACC?AA?C?AAACCCA?AAA??C?CC??CACCACAACCA?AACCC?A?CCC?CC???AA?CACCCAAC??CAA??C?AA??CA???CAAA...

output:

2344
2345
2342
2342
2768
2768
2772
2772
2772
2772
2772
2772
2772
2767
2767
2767
2767
2764
2766
2766
2769
2765
2761
2764
2767
2772
2772
2772
2772
2772
2772
2777
2777
2777
2777
2774
2771
2774
2782
2778
2778
2772
2768
2772
2772
2772
2772
2772
2774
2774
2778
2781
2781
2779
2782
2784
2787
2782
2786
2788
...

result:

ok 1000 lines

Test #3:

score: -100
Runtime Error

input:

300000 300000
AAA?CA?AA?AC?A?CCA?AACCAAA???CA?ACCAACCCCAACAAA?CCAAAC?A?C??CC?C?C?CCCA?CAA?ACA??C?C?AC??CA??ACA?AA???CACAAA?CACCCCCCC?A?AAAAAC?AACCA????CCC?C?AAACCCAA?C???CCCC?AAACAAA???A?CAAC??A??A??CCCC??AA?C??ACA?AACAAA????CAA???AAAAACC?C?CCA?CCAA?AAC?CC?CA?A??CC??CCAC??C??????AAC?AA?AA?AAC?C??AAC...

output:


result: