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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#590062 | #6837. AC Automaton | cyj888 | TL | 3ms | 36816kb | C++11 | 5.0kb | 2024-09-25 21:21:09 | 2024-09-25 21:21:11 |
Judging History
answer
#include <bits/stdc++.h>
#define pb push_back
#define ott(i,l,r) for (int i = l; i <= r; i ++)
#define tto(i,l,r) for (int i = r; i >= l; i --)
using namespace std;
using ll = long long;
inline int read () {
int x = 0; bool f = 0; char c = getchar ();
while (!isdigit (c)) f |= (c == '-'), c = getchar ();
while (isdigit (c)) x = (x << 3) + (x << 1) + (c ^ 48), c = getchar ();
if (f) x = -x; return x;
}
const int N = 3e5 + 110;
int n, m, q, idx, B;
ll res;
vector <int> e[N], E[N];
int up[N], dn[N];
int dfn[N], dep[N], fa[N];
int lg[N << 1], f[N << 1][20];
char ch[N];
inline void dfs0 (int u) {
f[dfn[u] = ++ idx][0] = u, dep[u] = dep[fa[u]] + 1;
for (int v : e[u]) {
dfs0 (v);
f[++ idx][0] = u;
}
return ;
}
inline int lca (int x, int y) {
x = dfn[x], y = dfn[y];
if (x > y) swap (x, y);
int z = lg[y - x + 1], f1 = f[x][z], f2 = f[y - (1 << z) + 1][z];
return dep[f1] < dep[f2] ? f1 : f2;
}
struct OPT {
int x; char c;
} a[N];
struct BLOCK {
int ac, now, sum;//ac = 'A'count
int s[1201];
inline void ins (int v) {
if (v >= now) ++ sum;
if (-m <= v && v <= m) ++ s[v + m];
return ;
}
inline void upd (int i) {
if (ch[i] == 'A') ++ ac;
if (ch[i] == '?') ins (dn[i] - up[i]);
return ;
}
inline void add (int v) {
if (v == 1) {
sum -= s[(now ++) + m];
res -= 1ll * sum;
}
if (v == -1) {
res += 1ll * sum;
sum += s[(-- now) + m];
}
return ;
}
void clear () {
ac = now = sum = 0;
ott (i, 0, m + m) s[i] = 0;
return ;
}
} b[N];
int id[N], val[N], FA[N];
inline bool cmp (const int &x, const int &y) {
return dfn[x] < dfn[y];
}
inline void push (int u, int z) {
b[z].upd (u);
for (int v : e[u]) push (v, z);
return ;
}
int Z, OTH;
inline void find (int x) {
if (id[fa[x]]) {
val[Z = id[x] = ++ idx] = x;
return ;
}
find (fa[x]);
b[Z].upd (fa[x]);
for (int v : e[fa[x]]) {
if (v == x) continue;
if (!OTH) val[OTH = id[v] = ++ idx] = v;
push (v, OTH);
}
return ;
}
inline void red (int u) {
dn[u] = 0;
for (int v : e[u]) {
up[v] = up[u] + (ch[u] != 'C');
red (v);
dn[u] += dn[v] + (ch[v] != 'A');
}
if (ch[u] == 'A') res += 1ll * dn[u];
if (ch[u] == '?') res += 1ll * max (0, dn[u] - up[u]);
return ;
}
inline void cup (int u, int V) {
for (int v : E[u]) {
if (val[v] < 0) {
int tv = -val[v];
if (ch[tv] == '?') res -= 1ll * max (0, dn[tv] - up[tv]);
up[tv] += V;
if (ch[tv] == '?') res += 1ll * max (0, dn[tv] - up[tv]);
}
else {
b[v].add (V);
}
cup (v, V);
}
return ;
}
inline void cdn (int u, int V) {
if (!u) return ;
if (val[u] < 0) {
int tu = -val[u];
if (ch[tu] == '?') res -= 1ll * max (0, dn[tu] - up[tu]);
dn[tu] += V; if (ch[tu] == 'A') res += 1ll * V;
if (ch[tu] == '?') res += 1ll * max (0, dn[tu] - up[tu]);
}
else {
b[u].add (-V), res += 1ll * b[u].ac * V;
}
cdn (FA[u], V);
return ;
}
inline void sol () {
ott (i, 1, m) val[++ idx] = a[i].x;
sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
sort (val + 1, val + 1 + idx, cmp);
ott (i, 2, idx) val[idx + i - 1] = lca (val[i - 1], val[i]); val[idx += idx] = 1;
sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
ott (i, 1, idx) {
id[val[i]] = i;
val[i] = -val[i];//区分会修改的点
}
ott (i, 2, idx) {
if (val[i] > 0) break;
if (!id[fa[-val[i]]]) {
OTH = Z = 0, find (-val[i]);
if (OTH) E[FA[OTH] = i].pb (OTH);
E[FA[Z] = id[fa[val[Z]]]].pb (Z), E[FA[i] = Z].pb (i);
}
else E[FA[i] = id[fa[-val[i]]]].pb (i);
}
ott (i, 1, idx) {
if (val[i] > 0) break;
OTH = 0; for (int v : e[-val[i]]) {
if (id[v]) continue;
if (!OTH) {
val[OTH = id[v] = ++ idx] = v;
E[FA[OTH] = i].pb (OTH);
}
push (v, OTH);
}
}
ott (i, 1, m) {
int x = a[i].x; char c = a[i].c;
if (ch[x] != 'C') cup (id[x], -1); if (ch[x] != 'A') cdn (FA[id[x]], -1);
if (ch[x] == 'A') res -= 1ll * dn[x];
if (ch[x] == '?') res -= 1ll * max (0, dn[x] - up[x]);
ch[x] = c;
if (ch[x] == 'A') res += 1ll * dn[x];
if (ch[x] == '?') res += 1ll * max (0, dn[x] - up[x]);
if (ch[x] != 'C') cup (id[x], 1); if (ch[x] != 'A') cdn (FA[id[x]], 1);
printf ("%lld\n", res);
}
ott (i, 1, idx) {
E[i].clear (), FA[i] = 0;
if (val[i] < 0) val[i] = -val[i];
else b[i].clear ();
id[val[i]] = 0, val[i] = 0;
}
m = idx = 0, res = 0; red (1);
return ;
}
int main () {
//freopen ("data.in", "r", stdin); freopen ("res.out", "w", stdout);
n = read (), q = read (), scanf ("%s", ch + 1); ott (i, 2, n) e[fa[i] = read ()].pb (i);
B = 600; dfs0 (1);
ott (j, 1, 19) {
ott (i, 1, idx - (1 << j) + 1) {
int f1 = f[i][j - 1], f2 = f[i + (1 << j - 1)][j - 1];
f[i][j] = dep[f1] < dep[f2] ? f1 : f2;
}
}
lg[0] = -1; ott (i, 1, idx) lg[i] = lg[i >> 1] + 1;
idx = 0, red (1); ott (i, 1, q) {
int x = read (); char c = getchar ();
a[++ m] = {x, c};
if (i % B == 0 || i == q) sol ();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 33344kb
input:
5 3 AC??C 1 2 2 1 1 ? 4 A 2 ?
output:
4 3 3
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 3ms
memory: 36816kb
input:
1000 1000 AC?ACCCCC?CCA??CCCCC?A?AC?C??C?ACCCACC?C?CCC?CACACA???????C?????CC?C?AAAAACCA??AAAACACACA???AACAC?CCC?CAC?AAAACCAC???ACAA??A??A?CA?A?ACACACCAA?ACACA?AC??AC??ACAAACCC??CAA?A???CC?AA??AC???A?CCCC??CACCAACC?AA?C?AAACCCA?AAA??C?CC??CACCACAACCA?AACCC?A?CCC?CC???AA?CACCCAAC??CAA??C?AA??CA???CAAA...
output:
2344 2345 2342 2342 2768 2768 2772 2772 2772 2772 2772 2772 2772 2767 2767 2767 2767 2764 2766 2766 2769 2765 2761 2764 2767 2772 2772 2772 2772 2772 2772 2777 2777 2777 2777 2774 2771 2774 2782 2778 2778 2772 2768 2772 2772 2772 2772 2772 2774 2774 2778 2781 2781 2779 2782 2784 2787 2782 2786 2788 ...
result:
ok 1000 lines
Test #3:
score: -100
Time Limit Exceeded
input:
300000 300000 AAA?CA?AA?AC?A?CCA?AACCAAA???CA?ACCAACCCCAACAAA?CCAAAC?A?C??CC?C?C?CCCA?CAA?ACA??C?C?AC??CA??ACA?AA???CACAAA?CACCCCCCC?A?AAAAAC?AACCA????CCC?C?AAACCCAA?C???CCCC?AAACAAA???A?CAAC??A??A??CCCC??AA?C??ACA?AACAAA????CAA???AAAAACC?C?CCA?CCAA?AAC?CC?CA?A??CC??CCAC??C??????AAC?AA?AA?AAC?C??AAC...
output:
14995917235 14995917235 14996064601 14996083631 14995980103 14995925797 14995925797 14995925797 14995967213 14995967213 14995967213 14995876211 14995774037 14995774037 14995774037 14995876791 14995866113 14995756158 14995647554 14995647554 14995560537 14995560537 14995583619 14995583619 14995583619 ...