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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#589092 | #9310. Permutation Counting 4 | svmh | RE | 0ms | 0kb | Python3 | 685b | 2024-09-25 16:10:04 | 2024-09-25 16:10:06 |
answer
import heapq
t = int(input())
for _ in range(t):
n = int(input())
# print(t, n)
arr = []
for i in range(n):
a1, a2 = map(int, input().split())
arr.append([a1, a2])
arr.sort()
flag = True
for i in range(n):
if not arr[i][0] <= i + 1 <= arr[i][1]:
flag = False
dic = {}
if flag:
while arr:
a1, a2 = heapq.heappop(arr)
if a1 in dic:
if a2 == dic[a2]:
flag = False
break
heapq.heappush(arr, [dic[a1] + 1, a2])
else:
dic[a1] = a2
print(1 if flag else 0)
Details
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Test #1:
score: 0
Dangerous Syscalls
input:
4 5 1 2 1 5 1 2 1 2 2 2 5 1 1 2 4 2 3 5 5 3 4 5 3 5 1 2 3 4 3 5 3 3 5 1 5 1 4 4 5 5 5 1 2
output:
0