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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#589092#9310. Permutation Counting 4svmhRE 0ms0kbPython3685b2024-09-25 16:10:042024-09-25 16:10:06

Judging History

你现在查看的是最新测评结果

  • [2024-09-25 16:10:06]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-09-25 16:10:04]
  • 提交

answer

import heapq

t = int(input())
for _ in range(t):
    n = int(input())
    # print(t, n)
    arr = []
    for i in range(n):
        a1, a2 = map(int, input().split())
        arr.append([a1, a2])
    arr.sort()
    flag = True
    for i in range(n):
        if not arr[i][0] <= i + 1 <= arr[i][1]:
            flag = False
    dic = {}
    if flag:
        while arr:
            a1, a2 = heapq.heappop(arr)
            if a1 in dic:
                if a2 == dic[a2]:
                    flag = False
                    break
                heapq.heappush(arr, [dic[a1] + 1, a2])
            else:
                dic[a1] = a2
    print(1 if flag else 0)

Details

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Test #1:

score: 0
Dangerous Syscalls

input:

4
5
1 2
1 5
1 2
1 2
2 2
5
1 1
2 4
2 3
5 5
3 4
5
3 5
1 2
3 4
3 5
3 3
5
1 5
1 4
4 5
5 5
1 2

output:

0

result: