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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#588111 | #6613. Bitwise Exclusive-OR Sequence | zzyNorthPole | TL | 34ms | 8396kb | C++14 | 2.0kb | 2024-09-25 01:26:34 | 2024-09-25 01:26:34 |
Judging History
answer
#include <cstdio>
#include <vector>
#include <iostream>
using namespace std;
const int N = 1e5 + 5;
struct DSU {
int pa[N], h[N], diff[N], com[N], dist[N], vis[N], sz;
DSU(int size) {
for (int i = 1; i <= size; ++i) pa[i] = i, h[i] = 0, dist[i] = 0, com[i] = 1, diff[i] = 0, vis[i] = 0;
sz = size;
}
~DSU() {}
void init() {
for (int i = 1; i <= sz; ++i) pa[i] = i, h[i] = 0, dist[i] = 0, com[i] = 1, diff[i] = 0, vis[i] = 0;
}
int qry(int x) {
int cnt = 0, x_ = x;
while (pa[x] != x) cnt += dist[x], x = pa[x];
dist[x_] = cnt, pa[x_] = x;
return x;
}
bool merge(int x, int y, int op) {
int rtx = qry(x), rty = qry(y);
if (rtx == rty) {
if ((dist[x] + dist[y]) % 2 == op) return true;
// cerr << x << ' ' << dist[x] << ' ' << y << ' ' << dist[y] << ' ' << op << '\n';
return false;
}
if (h[rtx] > h[rty]) swap(rtx, rty);
pa[rtx] = rty;
h[rtx] = max(h[rtx], h[rty] + 1);
if ((dist[x] + dist[y]) % 2 == op) dist[rtx] = 0, com[rty] += com[rtx], diff[rty] += diff[rtx];
else dist[rtx] = 1, diff[rty] += com[rtx], com[rty] += diff[rtx];
return true;
}
};
const int M = 2e5 + 5;
struct Data {
int u, v, w;
} a[M];
typedef long long LL;
LL solve(DSU &dsu, int step, int m) {
dsu.init();
for (int i = 1; i <= m; ++i) {
int u = a[i].u, v = a[i].v, w = a[i].w;
int flag = 1;
if (w & (1 << step)) flag = 1;
else flag = 0;
if (!dsu.merge(u, v, flag)) {
// cerr << step << '\n';
return -1;
}
}
LL ans = 0;
for (int i = 1; i < dsu.sz; ++i) {
int rti = dsu.qry(i);
if (dsu.vis[rti]) continue;
else dsu.vis[rti] = 1, ans += min(dsu.com[rti], dsu.diff[rti]);
}
return (ans << step);
}
int main() {
int n, m;
scanf("%d%d", &n, &m);
DSU dsu(n);
for (int i = 1; i <= m; ++i) {
scanf("%d%d%d", &a[i].u, &a[i].v, &a[i].w);
}
LL ans = 0;
for (int i = 0; i < 30; ++i) {
LL res = solve(dsu, i, m);
if (res == -1) {
printf("-1\n");
return 0;
}
ans += res;
}
printf("%lld\n", ans);
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 6100kb
input:
3 2 1 2 1 2 3 1
output:
1
result:
ok 1 number(s): "1"
Test #2:
score: 0
Accepted
time: 0ms
memory: 6100kb
input:
3 3 1 2 1 2 3 1 1 3 1
output:
-1
result:
ok 1 number(s): "-1"
Test #3:
score: 0
Accepted
time: 1ms
memory: 6276kb
input:
5 5 3 4 12 3 1 20 2 5 16 1 4 24 4 5 19
output:
58
result:
ok 1 number(s): "58"
Test #4:
score: 0
Accepted
time: 33ms
memory: 8396kb
input:
500 124750 1 2 31473 1 3 11597 1 4 6686 1 5 1214 1 6 14442 1 7 1042 1 8 19057 1 9 22648 1 10 24461 1 11 25714 1 12 3976 1 13 31954 1 14 7384 1 15 13988 1 16 28651 1 17 31599 1 18 8786 1 19 27068 1 20 9645 1 21 28281 1 22 11681 1 23 28897 1 24 31916 1 25 10462 1 26 23973 1 27 4615 1 28 5124 1 29 2026...
output:
8041745
result:
ok 1 number(s): "8041745"
Test #5:
score: 0
Accepted
time: 34ms
memory: 8356kb
input:
500 124750 1 2 3902 1 3 9006 1 4 2914 1 5 8753 1 6 2395 1 7 21406 1 8 14552 1 9 25834 1 10 28282 1 11 9684 1 12 11347 1 13 20545 1 14 16324 1 15 16951 1 16 11594 1 17 5035 1 18 17726 1 19 831 1 20 23194 1 21 7693 1 22 6147 1 23 315 1 24 32755 1 25 17078 1 26 11348 1 27 9587 1 28 21015 1 29 881 1 30 ...
output:
7803950
result:
ok 1 number(s): "7803950"
Test #6:
score: -100
Time Limit Exceeded
input:
100000 200000 82262 26109 1005476194 43106 86715 475153289 59086 60577 507254441 71498 80384 186530379 99676 3003 289537598 30772 72897 345346447 12686 87447 896623879 12520 27709 26442442 82734 20830 967590473 13380 76164 927495776 25723 55377 89078582 7173 86993 669894679 37790 94846 331905713 365...