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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#588111#6613. Bitwise Exclusive-OR SequencezzyNorthPoleTL 34ms8396kbC++142.0kb2024-09-25 01:26:342024-09-25 01:26:34

Judging History

你现在查看的是最新测评结果

  • [2024-09-25 01:26:34]
  • 评测
  • 测评结果:TL
  • 用时:34ms
  • 内存:8396kb
  • [2024-09-25 01:26:34]
  • 提交

answer

#include <cstdio>
#include <vector>
#include <iostream>
using namespace std;
const int N = 1e5 + 5;
struct DSU {
	int pa[N], h[N], diff[N], com[N], dist[N], vis[N], sz;

	DSU(int size) {
		for (int i = 1; i <= size; ++i) pa[i] = i, h[i] = 0, dist[i] = 0, com[i] = 1, diff[i] = 0, vis[i] = 0;
		sz = size;
	}
	~DSU() {}

	void init() {
		for (int i = 1; i <= sz; ++i) pa[i] = i, h[i] = 0, dist[i] = 0, com[i] = 1, diff[i] = 0, vis[i] = 0;
	}

	int qry(int x) {
		int cnt = 0, x_ = x;
		while (pa[x] != x) cnt += dist[x], x = pa[x];
		dist[x_] = cnt, pa[x_] = x;
		return x;
	}

	bool merge(int x, int y, int op) {
		int rtx = qry(x), rty = qry(y);
		if (rtx == rty) {
			if ((dist[x] + dist[y]) % 2 == op) return true;
			// cerr << x << ' ' << dist[x] << ' ' << y << ' ' << dist[y] << ' ' << op << '\n';
			return false;
		}
		if (h[rtx] > h[rty]) swap(rtx, rty);
		pa[rtx] = rty;
		h[rtx] = max(h[rtx], h[rty] + 1);
		if ((dist[x] + dist[y]) % 2 == op) dist[rtx] = 0, com[rty] += com[rtx], diff[rty] += diff[rtx];
		else dist[rtx] = 1, diff[rty] += com[rtx], com[rty] += diff[rtx];
		return true;
	}
};
const int M = 2e5 + 5;
struct Data {
	int u, v, w;
} a[M];
typedef long long LL;
LL solve(DSU &dsu, int step, int m) {
	dsu.init();
	for (int i = 1; i <= m; ++i) {
		int u = a[i].u, v = a[i].v, w = a[i].w;
		int flag = 1;
		if (w & (1 << step)) flag = 1;
		else flag = 0;
		if (!dsu.merge(u, v, flag)) {
			// cerr << step << '\n';
			return -1;
		}
	}
	LL ans = 0;
	for (int i = 1; i < dsu.sz; ++i) {
		int rti = dsu.qry(i);
		if (dsu.vis[rti]) continue;
		else dsu.vis[rti] = 1, ans += min(dsu.com[rti], dsu.diff[rti]);
	}
	return (ans << step);
}
int main() {
	int n, m;
	scanf("%d%d", &n, &m);
	DSU dsu(n);
	for (int i = 1; i <= m; ++i) {
		scanf("%d%d%d", &a[i].u, &a[i].v, &a[i].w);
	}

	LL ans = 0;
	for (int i = 0; i < 30; ++i) {
		LL res = solve(dsu, i, m);
		if (res == -1) {
			printf("-1\n");
			return 0;
		}
		ans += res;
	}

	printf("%lld\n", ans);
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 6100kb

input:

3 2
1 2 1
2 3 1

output:

1

result:

ok 1 number(s): "1"

Test #2:

score: 0
Accepted
time: 0ms
memory: 6100kb

input:

3 3
1 2 1
2 3 1
1 3 1

output:

-1

result:

ok 1 number(s): "-1"

Test #3:

score: 0
Accepted
time: 1ms
memory: 6276kb

input:

5 5
3 4 12
3 1 20
2 5 16
1 4 24
4 5 19

output:

58

result:

ok 1 number(s): "58"

Test #4:

score: 0
Accepted
time: 33ms
memory: 8396kb

input:

500 124750
1 2 31473
1 3 11597
1 4 6686
1 5 1214
1 6 14442
1 7 1042
1 8 19057
1 9 22648
1 10 24461
1 11 25714
1 12 3976
1 13 31954
1 14 7384
1 15 13988
1 16 28651
1 17 31599
1 18 8786
1 19 27068
1 20 9645
1 21 28281
1 22 11681
1 23 28897
1 24 31916
1 25 10462
1 26 23973
1 27 4615
1 28 5124
1 29 2026...

output:

8041745

result:

ok 1 number(s): "8041745"

Test #5:

score: 0
Accepted
time: 34ms
memory: 8356kb

input:

500 124750
1 2 3902
1 3 9006
1 4 2914
1 5 8753
1 6 2395
1 7 21406
1 8 14552
1 9 25834
1 10 28282
1 11 9684
1 12 11347
1 13 20545
1 14 16324
1 15 16951
1 16 11594
1 17 5035
1 18 17726
1 19 831
1 20 23194
1 21 7693
1 22 6147
1 23 315
1 24 32755
1 25 17078
1 26 11348
1 27 9587
1 28 21015
1 29 881
1 30 ...

output:

7803950

result:

ok 1 number(s): "7803950"

Test #6:

score: -100
Time Limit Exceeded

input:

100000 200000
82262 26109 1005476194
43106 86715 475153289
59086 60577 507254441
71498 80384 186530379
99676 3003 289537598
30772 72897 345346447
12686 87447 896623879
12520 27709 26442442
82734 20830 967590473
13380 76164 927495776
25723 55377 89078582
7173 86993 669894679
37790 94846 331905713
365...

output:


result: