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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#587784#7778. Turning PermutationTMM233WA 232ms255868kbC++2013.6kb2024-09-24 21:39:552024-09-24 21:40:02

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你现在查看的是最新测评结果

  • [2024-09-24 21:40:02]
  • 评测
  • 测评结果:WA
  • 用时:232ms
  • 内存:255868kb
  • [2024-09-24 21:39:55]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define int long long
using namespace std;
const int maxn =1e6+5;
const int N=53;
ll dp[N][N][N][N][2];// [pos,kaitou,duan,i,left or right]    
ll sum_dp[N][N][N][2][2];//[len,kaitou,duan,kaitou state,jiewei state]
ll sum_sum[N][N][2][2];//[len,duan,kaitou state,jiewei state]
ll pre1[N][N][N];//[ct_merge,ct_x,ct_v]
ll pre2[N][N][N][N];//[kon,fan,tie,jiao]
ll pre3[N][N][N][N];//[kon,fan,tie,jiao]
ll C[N][N];
ll dp1[N][N];//[kaitou,duan]
ll sum1[N];//[duan]
ll DP1[N][N];//[kaitou,duan]
void init0()
{
    C[0][0]=1;
    for(int i=1;i<N;i++)
    {
        C[i][0]=1;
        for(int j=1;j<=i;j++)
        C[i][j]=C[i-1][j]+C[i-1][j-1];
    }
}
void init2()
{
    pre2[0][0][0][0]=1;
    for(int i=0;i<N-1;i++)
    {
        for(int j=0;j<N;j++)
        {
            for(int k=0;k<=j;k++)
            {
                for(int jiao=0;jiao<=i&&jiao+k<=j;jiao++)
                {
                    if(j+1<N)
                    pre2[i+1][j+1][k][jiao+1]+=pre2[i][j][k][jiao];
                    for(int w=0;w+j<N;w++)
                    {
                        // for(int kk=0;kk<=2&&kk<=w;kk++)
                        if(1<=w)
                        pre2[i+1][w+j][k+1][jiao]+=pre2[i][j][k][jiao]*2;
                        if(2<=w)
                        pre2[i+1][w+j][k+2][jiao]+=pre2[i][j][k][jiao];
                        pre2[i+1][w+j][k+0][jiao]+=pre2[i][j][k][jiao];
                    }
                }
                
            }
        }
    }
    // chu li zui hou yi ge mei you right
    for(int i=0;i<N-1;i++)
    {
        for(int j=0;j<N;j++)
        {
            for(int k=0;k<=j;k++)
            {
                for(int jiao=0;jiao<=i&&jiao+k<=j;jiao++)
                for(int w=0;w+j<N;w++)
                {
                    for(int kk=0;kk<=1&&kk<=w;kk++)
                    pre3[i][w+j][k+kk][jiao]+=pre2[i][j][k][jiao];
                }
            }
        }
    }
}
void init1()
{
    for(int i=1;i<N;i++)
    {
        for(int j=1;j<N;j++)
        {
            for(int k=0;k<=j&&k<=i-1;k++)
            {
                for(int w=0;k+w<=j&&w<=(i-k)*2-1;w++)
                {
                    pre1[i+(j-k-w)-k][i][j]+=pre3[i-1][j][w][k];
                }
            }
        }
    }
}
// ll dp[N][N][N][N][2]; [pos,kaitou,duan,i,left or right]
// ll sum_dp[N][N][N];//[len,kaitou,duan]
void init3()
{
    dp[2][1][1][1][0]=1;
    dp[2][2][1][1][1]=1;
    dp[2][2][2][1][1]=1;
    dp[2][1][2][2][0]=1;
    for(int i=2;i<N-1;i++)
    {
        for(int j=1;j<=i;j++)
        {
            for(int k=1;k<=i;k++)
            {
                for(int w=1;w<=k;w++)
                {
                    // add
                    for(int z=1;z<=k+1;z++)
                    {
                        if(z<=w)
                        {
                            if(z==1)
                            dp[i+1][i+1][k+1][z][1]+=dp[i][j][k][w][0];
                            else
                            dp[i+1][j][k+1][z][1]+=dp[i][j][k][w][0];
                        }
                        else
                        {
                            if(z==1)
                            dp[i+1][i+1][k+1][z][0]+=dp[i][j][k][w][1];
                            else
                            dp[i+1][j][k+1][z][0]+=dp[i][j][k][w][1];
                        }
                    }
                    // tie
                    for(int z=1;z<=k;z++)
                    {
                        if(z<w)
                        {
                            if(z==1)
                            {
                                dp[i+1][i+1][k][z][1]+=dp[i][j][k][w][0];// tie left
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];// tie right
                            }
                            else
                            {
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];
                            }
                        }
                        else if(z==w)
                        {
                            if(z==1)
                            {
                                dp[i+1][i+1][k][z][1]+=dp[i][j][k][w][0];// tie left
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];// tie right
                            }
                            else
                            {
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];
                            }
                        }
                        else if(z>w)
                        {
                            if(z==1)
                            {
                                dp[i+1][i+1][k][z][0]+=dp[i][j][k][w][1];// tie left
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];// tie right
                            }
                            else
                            {
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];
                            }
                        }
                    }
                    // jiao
                    for(int z=1;z<=k-1;z++)
                    {
                        if(z<w)
                        {
                            dp[i+1][j][k-1][z][1]+=dp[i][j][k][w][0];
                        }
                        else 
                        {
                            dp[i+1][j][k-1][z][0]+=dp[i][j][k][w][1];
                        }
                    }
                }
            }
        }
    }
    sum_dp[1][1][1][0][0]=1;
    sum_dp[1][1][1][0][1]=1;
    for(int i=2;i<N;i++)
    {
        for(int j=1;j<=i;j++)
        {
            for(int k=1;k<=i;k++)
            {
                for(int w=1;w<=k;w++)
                {
                    for(int z=0;z<=1;z++)
                    sum_dp[i][j][k][0][0]+=dp[i][j][k][w][z];
                    sum_dp[i][j][k][0][1]+=dp[i][j][k][w][0];
                }
            }
            
        }
    }
    memset(dp,0,sizeof(dp));
    dp[2][2][1][1][1]=1;
    dp[2][2][2][1][1]=1;
    for(int i=2;i<N-1;i++)
    {
        for(int j=1;j<=i;j++)
        {
            for(int k=1;k<=i;k++)
            {
                for(int w=1;w<=k;w++)
                {
                    // add
                    for(int z=1;z<=k+1;z++)
                    {
                        if(z<=w)
                        {
                            if(z==1)
                            dp[i+1][i+1][k+1][z][1]+=dp[i][j][k][w][0];
                            else
                            dp[i+1][j][k+1][z][1]+=dp[i][j][k][w][0];
                        }
                        else
                        {
                            if(z==1)
                            dp[i+1][i+1][k+1][z][0]+=dp[i][j][k][w][1];
                            else
                            dp[i+1][j][k+1][z][0]+=dp[i][j][k][w][1];
                        }
                    }
                    // tie
                    for(int z=1;z<=k;z++)
                    {
                        if(z<w)
                        {
                            if(z==1)
                            {
                                dp[i+1][i+1][k][z][1]+=dp[i][j][k][w][0];// tie left
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];// tie right
                            }
                            else
                            {
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];
                            }
                        }
                        else if(z==w)
                        {
                            if(z==1)
                            {
                                dp[i+1][i+1][k][z][1]+=dp[i][j][k][w][0];// tie left
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];// tie right
                            }
                            else
                            {
                                dp[i+1][j][k][z][1]+=dp[i][j][k][w][0];
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];
                            }
                        }
                        else if(z>w)
                        {
                            if(z==1)
                            {
                                dp[i+1][i+1][k][z][0]+=dp[i][j][k][w][1];// tie left
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];// tie right
                            }
                            else
                            {
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];
                                dp[i+1][j][k][z][0]+=dp[i][j][k][w][1];
                            }
                        }
                    }
                    // jiao
                    for(int z=1;z<=k-1;z++)
                    {
                        if(z<w)
                        {
                            dp[i+1][j][k-1][z][1]+=dp[i][j][k][w][0];
                        }
                        else 
                        {
                            dp[i+1][j][k-1][z][0]+=dp[i][j][k][w][1];
                        }
                    }
                }
            }
        }
    }
    sum_dp[1][1][1][1][0]=1;
    sum_dp[1][1][1][1][1]=1;
    for(int i=2;i<N;i++)
    {
        for(int j=1;j<=i;j++)
        {
            for(int k=1;k<=i;k++)
            {
                for(int w=1;w<=k;w++)
                {
                    for(int z=0;z<=1;z++)
                    sum_dp[i][j][k][1][0]+=dp[i][j][k][w][z];
                    sum_dp[i][j][k][1][1]+=dp[i][j][k][w][0];
                }
            }
            
        }
    }
    sum_sum[1][1][0][0]=1;
    sum_sum[1][1][0][1]=1;
    sum_sum[1][1][1][0]=1;
    sum_sum[1][1][1][1]=1;
    for(int i=2;i<N;i++)
    {
        for(int j=1;j<=i;j++)
        {
            for(int k=1;k<=i;k++)
            for(int z1=0;z1<2;z1++)
            for(int z2=0;z2<2;z2++)
            sum_sum[i][k][z1][z2]+=sum_dp[i][j][k][z1][z2];
        }
    }
}
void solve()
{
    ll n,k;cin>>n>>k;
    k--;
    init0();
    init2();
    init1();
    init3();
    vector<int> ans;
    set<int> st;
    st.insert(0);
    st.insert(n+1);
    for(int i=1;i<=n;i++)
    {
        ll lt=-1;
        memset(dp1,0,sizeof(dp1));
        memset(dp1,0,sizeof(DP1));
        bool fg=0;
        for(auto v:st)
        {
            if(v-lt-1==0)
            {
                lt=v;
                continue;
            }
            if(!fg)
            {
                fg=1;
                for(int j=lt+1,jj=1;j<=v-1;j++,jj++)
                {
                    for(int k=1;k<=v-lt-1;k++)
                    {
                        dp1[j][k]=sum_dp[v-lt-1][jj][k][(lt!=0)][(v!=n+1)];
                    }
                }
                memset(sum1,0,sizeof(sum1));
                for(int k=1;k<=v-lt-1;k++)
                {
                    for(int j=lt+1;j<=v-1;j++)
                    sum1[k]+=dp1[j][k];
                }
                lt=v;
                continue;
            } 
            for(int w=1;w<=v-1;w++)
            {
                if(w<lt)
                {
                    for(int ct_merge=1;ct_merge<=v-1;ct_merge++)
                    {
                        for(int ct_x=1;ct_x<=lt-1;ct_x++)
                        {
                            for(int ct_v=1;ct_v<=v-lt-1;ct_v++)
                            {
                                DP1[w][ct_merge]+=pre1[ct_merge][ct_x][ct_v]*dp1[w][ct_x]*sum_sum[v-lt-1][ct_v][(lt!=0)][(v!=n+1)];
                            }
                        }
                    }
                }
                else if(w>lt)
                {
                    for(int ct_merge=1;ct_merge<=v-1;ct_merge++)
                    {
                        for(int ct_x=1;ct_x<=lt-1;ct_x++)
                        {
                            for(int ct_v=1;ct_v<=v-lt-1;ct_v++)
                            {
                                DP1[w][ct_merge]+=pre1[ct_merge][ct_v][ct_x]*sum1[ct_x]*sum_dp[v-lt-1][w-lt][ct_v][(lt!=0)][(v!=n+1)];
                            }
                        }
                    }
                }
            }
            for(int j=1;j<=v-1;j++)
            {
                for(int k=1;k<=v-1;k++)
                {
                    dp1[j][k]=DP1[j][k];
                    DP1[j][k]=0;
                }
            }
            memset(sum1,0,sizeof(sum1));
            for(int k=1;k<=n;k++)
            {
                for(int j=1;j<=n;j++)
                sum1[k]+=dp1[j][k];
            }
            lt=v;
        }
        bool mk=0;
        for(int j=1;j<=n;j++)
        {
            if(k>=dp1[j][1])
            {
                k-=dp1[j][1];
            }
            else if(dp1[j][1]!=0)
            {
                ans.push_back(j);
                st.insert(j);
                mk=1;
                break;
            }
        }
        if(!mk)
        {
            cout<<-1<<'\n';
            return ;
        }
    }
    for(auto v:ans)
    cout<<v<<' ';
}
signed main()
{
    ios::sync_with_stdio(0), cin.tie(0) ;
    int t= 1;
    // cin>>t;
    while(t--)solve();
}

详细

Test #1:

score: 100
Accepted
time: 191ms
memory: 249948kb

input:

3 2

output:

2 1 3 

result:

ok 3 number(s): "2 1 3"

Test #2:

score: 0
Accepted
time: 232ms
memory: 251836kb

input:

3 5

output:

-1

result:

ok 1 number(s): "-1"

Test #3:

score: 0
Accepted
time: 194ms
memory: 254696kb

input:

4 6

output:

3 1 2 4 

result:

ok 4 number(s): "3 1 2 4"

Test #4:

score: 0
Accepted
time: 206ms
memory: 254968kb

input:

4 11

output:

-1

result:

ok 1 number(s): "-1"

Test #5:

score: 0
Accepted
time: 186ms
memory: 254816kb

input:

3 1

output:

1 3 2 

result:

ok 3 number(s): "1 3 2"

Test #6:

score: 0
Accepted
time: 196ms
memory: 254732kb

input:

3 10

output:

-1

result:

ok 1 number(s): "-1"

Test #7:

score: 0
Accepted
time: 187ms
memory: 255800kb

input:

3 52

output:

-1

result:

ok 1 number(s): "-1"

Test #8:

score: 0
Accepted
time: 192ms
memory: 255024kb

input:

3 756

output:

-1

result:

ok 1 number(s): "-1"

Test #9:

score: 0
Accepted
time: 192ms
memory: 254812kb

input:

3 7721

output:

-1

result:

ok 1 number(s): "-1"

Test #10:

score: 0
Accepted
time: 178ms
memory: 255600kb

input:

5 1

output:

1 3 2 5 4 

result:

ok 5 number(s): "1 3 2 5 4"

Test #11:

score: 0
Accepted
time: 193ms
memory: 255640kb

input:

5 8

output:

2 4 1 3 5 

result:

ok 5 number(s): "2 4 1 3 5"

Test #12:

score: 0
Accepted
time: 187ms
memory: 254540kb

input:

5 85

output:

-1

result:

ok 1 number(s): "-1"

Test #13:

score: 0
Accepted
time: 187ms
memory: 255560kb

input:

5 846

output:

-1

result:

ok 1 number(s): "-1"

Test #14:

score: 0
Accepted
time: 193ms
memory: 255800kb

input:

5 6957

output:

-1

result:

ok 1 number(s): "-1"

Test #15:

score: 0
Accepted
time: 192ms
memory: 254960kb

input:

8 1

output:

1 3 2 5 4 7 6 8 

result:

ok 8 numbers

Test #16:

score: 0
Accepted
time: 203ms
memory: 254796kb

input:

8 7

output:

1 3 2 5 7 8 4 6 

result:

ok 8 numbers

Test #17:

score: 0
Accepted
time: 188ms
memory: 255492kb

input:

8 71

output:

1 3 7 5 4 2 6 8 

result:

ok 8 numbers

Test #18:

score: 0
Accepted
time: 208ms
memory: 255012kb

input:

8 863

output:

3 5 7 1 4 2 8 6 

result:

ok 8 numbers

Test #19:

score: 0
Accepted
time: 183ms
memory: 254720kb

input:

8 7099

output:

-1

result:

ok 1 number(s): "-1"

Test #20:

score: 0
Accepted
time: 191ms
memory: 255608kb

input:

10 100000

output:

10 8 4 6 9 2 7 3 5 1 

result:

ok 10 numbers

Test #21:

score: 0
Accepted
time: 218ms
memory: 254528kb

input:

10 62278

output:

7 1 9 8 5 10 3 6 2 4 

result:

ok 10 numbers

Test #22:

score: 0
Accepted
time: 206ms
memory: 255796kb

input:

10 1000000

output:

-1

result:

ok 1 number(s): "-1"

Test #23:

score: 0
Accepted
time: 206ms
memory: 254716kb

input:

10 572106

output:

-1

result:

ok 1 number(s): "-1"

Test #24:

score: 0
Accepted
time: 187ms
memory: 255512kb

input:

10 10000000

output:

-1

result:

ok 1 number(s): "-1"

Test #25:

score: 0
Accepted
time: 192ms
memory: 255504kb

input:

10 9715489

output:

-1

result:

ok 1 number(s): "-1"

Test #26:

score: 0
Accepted
time: 195ms
memory: 254720kb

input:

10 100000000

output:

-1

result:

ok 1 number(s): "-1"

Test #27:

score: 0
Accepted
time: 187ms
memory: 255436kb

input:

10 85089137

output:

-1

result:

ok 1 number(s): "-1"

Test #28:

score: 0
Accepted
time: 201ms
memory: 255868kb

input:

10 1000000000

output:

-1

result:

ok 1 number(s): "-1"

Test #29:

score: 0
Accepted
time: 199ms
memory: 254788kb

input:

10 906109922

output:

-1

result:

ok 1 number(s): "-1"

Test #30:

score: 0
Accepted
time: 172ms
memory: 254744kb

input:

15 100000

output:

1 3 2 5 7 9 13 15 11 6 4 14 10 8 12 

result:

ok 15 numbers

Test #31:

score: 0
Accepted
time: 180ms
memory: 254852kb

input:

15 99389

output:

1 3 2 5 7 9 13 15 6 4 11 8 10 14 12 

result:

ok 15 numbers

Test #32:

score: 0
Accepted
time: 192ms
memory: 255596kb

input:

15 1000000

output:

1 3 2 7 15 13 5 11 6 9 8 14 4 10 12 

result:

ok 15 numbers

Test #33:

score: 0
Accepted
time: 196ms
memory: 254672kb

input:

15 691130

output:

1 3 2 7 9 5 11 4 13 6 15 12 10 8 14 

result:

ok 15 numbers

Test #34:

score: -100
Wrong Answer
time: 190ms
memory: 255632kb

input:

15 10000000

output:

-1

result:

wrong answer 1st numbers differ - expected: '1', found: '-1'