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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#586554#9376. GameMiniLongCompile Error//C++172.9kb2024-09-24 14:02:202024-09-24 14:02:20

Judging History

你现在查看的是最新测评结果

  • [2024-09-24 14:02:20]
  • 评测
  • [2024-09-24 14:02:20]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
ll a, b, p0, p1, t;
ll solve(ll x, ll y){
    if(x <= 0) return 0;
    if(y <= 0) return 1;
    if(x < y){
        ll t = (y - x) / x + ((y - x) % x != 0);
        return solve(x, y - t * x) * ksm(p0, t) % mod;
    }
    if(x == y) return p0;
    ll k = (x - y) / y + ((x - y) % y != 0);
    return (solve(x - k * y, y) * ksm(p1, k) % mod + (ksm(p1, k) - 1 + mod) % mod * ksm(p1 + mod - 1, mod - 2) % mod * p0 % mod) % mod;
}
int main(){
    multitest(){
        read(a, b, p0, p1, t);
        mul(p0, ksm(t, mod - 2)), mul(p1, ksm(t, mod - 2));
        t = ksm(p0 + p1, mod - 2);
        mul(p0, t), mul(p1, t);
        writeln(solve(a, b) % mod);
    }
    return 0;
}

詳細信息

answer.code: In function ‘ll solve(ll, ll)’:
answer.code:78:39: error: reference to ‘p1’ is ambiguous
   78 |     return (solve(x - k * y, y) * ksm(p1, k) % mod + (ksm(p1, k) - 1 + mod) % mod * ksm(p1 + mod - 1, mod - 2) % mod * p0 % mod) % mod;
      |                                       ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~
answer.code:78:59: error: reference to ‘p1’ is ambiguous
   78 |     return (solve(x - k * y, y) * ksm(p1, k) % mod + (ksm(p1, k) - 1 + mod) % mod * ksm(p1 + mod - 1, mod - 2) % mod * p0 % mod) % mod;
      |                                                           ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~
answer.code:78:89: error: reference to ‘p1’ is ambiguous
   78 |     return (solve(x - k * y, y) * ksm(p1, k) % mod + (ksm(p1, k) - 1 + mod) % mod * ksm(p1 + mod - 1, mod - 2) % mod * p0 % mod) % mod;
      |                                                                                         ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~
answer.code: In function ‘int main()’:
answer.code:82:24: error: reference to ‘p1’ is ambiguous
   82 |         read(a, b, p0, p1, t);
      |                        ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~
answer.code:83:39: error: reference to ‘p1’ is ambiguous
   83 |         mul(p0, ksm(t, mod - 2)), mul(p1, ksm(t, mod - 2));
      |                                       ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~
answer.code:84:22: error: reference to ‘p1’ is ambiguous
   84 |         t = ksm(p0 + p1, mod - 2);
      |                      ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~
answer.code:85:25: error: reference to ‘p1’ is ambiguous
   85 |         mul(p0, t), mul(p1, t);
      |                         ^~
answer.code:19:25: note: candidates are: ‘char* fastio::p1’
   19 |     char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
      |                         ^~
answer.code:68:14: note:                 ‘ll p1’
   68 | ll a, b, p0, p1, t;
      |              ^~