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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#586530 | #6837. AC Automaton | cyj888 | WA | 3ms | 49372kb | C++17 | 5.4kb | 2024-09-24 13:51:02 | 2024-09-24 13:51:02 |
Judging History
answer
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define ott(i,l,r) for (int i = l; i <= r; i ++)
#define tto(i,l,r) for (int i = r; i >= l; i --)
using namespace std;
using ll = long long;
int read () {
int x = 0; bool f = 0; char c = getchar ();
while (!isdigit (c)) f |= (c == '-'), c = getchar ();
while (isdigit (c)) x = (x << 3) + (x << 1) + (c ^ 48), c = getchar ();
if (f) x = -x; return x;
}
const int N = 3e5 + 110, inf = 0x3f3f3f3f;
int n, m, q, idx, B;
ll res;
vector <int> e[N], E[N];
int up[N], dn[N];
int dfn[N], dep[N], fa[N];
int lg[N << 1], f[N << 1][20];
char ch[N];
void dfs0 (int u) {
f[dfn[u] = ++ idx][0] = u, dep[u] = dep[fa[u]] + 1;
for (int v : e[u]) {
dfs0 (v);
f[++ idx][0] = u;
}
return ;
}
int lca (int x, int y) {
x = dfn[x], y = dfn[y];
if (x > y) swap (x, y);
int z = lg[y - x + 1], f1 = f[x][z], f2 = f[y - (1 << z) + 1][z];
return dep[f1] < dep[f2] ? f1 : f2;
}
struct OPT {
int x; char c;
} a[N];
struct BLOCK {
int ac, now, val, sum, len;//ac = 'A'count
vector <int> p; pair <int, int> *a;
void ins (int v) {
if (v >= 0) ++ sum;
if (-m <= v && v <= m) p.pb (v);
return ;
}
void init () {
sort (p.begin (), p.end ()); a = new pair <int, int>[p.size () + 4];
a[0] = {-inf, 0};
for (int v : p) {
if (v != a[len].fi) a[++ len] = {v, 1};
else ++ a[len].se;
if (len && v >= 0) now = len;
}
a[++ len] = {inf, 0};
return ;
}
void upd (int i) {
if (ch[i] == 'A') ++ ac;
if (ch[i] == '?') ins (dn[i] - up[i]);
return ;
}
void add (int v) {
if (v == 1) {
if (a[now].fi == val ++) sum -= a[now ++].se;
res -= 1ll * sum;
}
if (v == -1) {
res += 1ll * sum;
if (a[now - 1].fi == -- val) sum -= a[-- now].se;
}
return ;
}
void clear () {
ac = now = val = sum = len = 0;
vector <int> ().swap (p); free (a);
return ;
}
} b[N];
int id[N], val[N], FA[N];
bool cmp (int x, int y) {
return dfn[x] < dfn[y];
}
void push (int u, int z) {
b[z].upd (u);
for (int v : e[u]) push (v, z);
return ;
}
int Z, OTH;
void find (int x) {
if (id[fa[x]]) {
val[Z = id[x] = ++ idx] = x;
return ;
}
find (fa[x]);
b[Z].upd (fa[x]);
for (int v : e[fa[x]]) {
if (v == x) continue;
if (!OTH) val[OTH = id[v] = ++ idx] = v;
push (v, OTH);
}
return ;
}
void red (int u) {
dn[u] = 0;
for (int v : e[u]) {
up[v] = up[u] + (ch[u] != 'C');
red (v);
dn[u] += dn[v] + (ch[v] != 'A');
}
if (ch[u] == 'A') res += 1ll * dn[u];
if (ch[u] == '?') res += 1ll * max (0, dn[u] - up[u]);
return ;
}
void cup (int u, int V) {
for (int v : E[u]) {
if (val[v] < 0) {
int tv = -val[v];
if (ch[tv] == '?') res -= 1ll * max (0, dn[tv] - up[tv]);
up[tv] += V;
if (ch[tv] == '?') res += 1ll * max (0, dn[tv] - up[tv]);
}
else {
b[v].add (V);
}
cup (v, V);
}
return ;
}
void cdn (int u, int V) {
if (!u) return ;
if (val[u] < 0) {
int tu = -val[u];
if (ch[tu] == '?') res -= 1ll * max (0, dn[tu] - up[tu]);
dn[tu] += V; if (ch[tu] == 'A') res += 1ll * V;
if (ch[tu] == '?') res += 1ll * max (0, dn[tu] - up[tu]);
}
else {
b[u].add (-V), res += 1ll * b[u].ac * V;
}
cdn (FA[u], V);
return ;
}
void sol () {
ott (i, 1, m) val[++ idx] = a[i].x;
sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
sort (val + 1, val + 1 + idx, cmp);
ott (i, 2, idx) val[idx + i - 1] = lca (val[i - 1], val[i]); val[idx += idx] = 1;
sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
ott (i, 1, idx) {
id[val[i]] = i;
val[i] = -val[i];//区分会修改的点
}
ott (i, 2, idx) {
if (val[i] > 0) break;
if (!id[fa[-val[i]]]) {
OTH = Z = 0, find (-val[i]);
if (OTH) E[FA[OTH] = i].pb (OTH);
E[FA[Z] = id[fa[val[Z]]]].pb (Z), E[FA[i] = Z].pb (i);
}
else E[FA[i] = id[fa[-val[i]]]].pb (i);
}
ott (i, 1, idx) {
if (val[i] > 0) break;
OTH = 0; for (int v : e[-val[i]]) {
if (id[v]) continue;
if (!OTH) {
val[OTH = id[v] = ++ idx] = v;
E[FA[OTH] = i].pb (OTH);
}
push (v, OTH);
}
}
ott (i, 1, idx) if (val[i] > 0) b[i].init ();
ott (i, 1, m) {
int x = a[i].x; char c = a[i].c;
if (ch[x] != 'C') cup (id[x], -1); if (ch[x] != 'A') cdn (FA[id[x]], -1);
if (ch[x] == 'A') res -= 1ll * dn[x];
if (ch[x] == '?') res -= 1ll * max (0, dn[x] - up[x]);
ch[x] = c;
if (ch[x] == 'A') res += 1ll * dn[x];
if (ch[x] == '?') res += 1ll * max (0, dn[x] - up[x]);
if (ch[x] != 'C') cup (id[x], 1); if (ch[x] != 'A') cdn (FA[id[x]], 1);
printf ("%lld\n", res);
}
ott (i, 1, idx) {
E[i].clear (), FA[i] = 0;
if (val[i] < 0) val[i] = -val[i];
else b[i].clear ();
id[val[i]] = 0, val[i] = 0;
}
m = idx = 0, res = 0; red (1);
return ;
}
int main () {
//freopen ("data.in", "r", stdin);
//freopen ("res.out", "w", stdout);
n = read (), q = read (), scanf ("%s", ch + 1); ott (i, 2, n) e[fa[i] = read ()].pb (i);
B = 1000; dfs0 (1);
ott (j, 1, 19) {
ott (i, 1, idx - (1 << j) + 1) {
int f1 = f[i][j - 1], f2 = f[i + (1 << j - 1)][j - 1];
f[i][j] = dep[f1] < dep[f2] ? f1 : f2;
}
}
lg[0] = -1; ott (i, 1, idx) lg[i] = lg[i >> 1] + 1;
idx = 0, red (1); ott (i, 1, q) {
int x = read (); char c = getchar ();
a[++ m] = {x, c};
if (i % B == 0 || i == q) sol ();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 49372kb
input:
5 3 AC??C 1 2 2 1 1 ? 4 A 2 ?
output:
4 3 3
result:
ok 3 lines
Test #2:
score: -100
Wrong Answer
time: 3ms
memory: 48032kb
input:
1000 1000 AC?ACCCCC?CCA??CCCCC?A?AC?C??C?ACCCACC?C?CCC?CACACA???????C?????CC?C?AAAAACCA??AAAACACACA???AACAC?CCC?CAC?AAAACCAC???ACAA??A??A?CA?A?ACACACCAA?ACACA?AC??AC??ACAAACCC??CAA?A???CC?AA??AC???A?CCCC??CACCAACC?AA?C?AAACCCA?AAA??C?CC??CACCACAACCA?AACCC?A?CCC?CC???AA?CACCCAAC??CAA??C?AA??CA???CAAA...
output:
2344 2345 2342 2342 2768 2768 2772 2772 2772 2772 2772 2772 2772 2767 2767 2767 2767 2764 2766 2766 2769 2765 2761 2764 2767 2772 2772 2772 2772 2772 2772 2777 2777 2777 2777 2774 2771 2774 2782 2778 2778 2772 2768 2772 2772 2772 2772 2772 2774 2774 2778 2781 2781 2779 2782 2784 2787 2782 2786 2788 ...
result:
wrong answer 93rd lines differ - expected: '2792', found: '2796'