QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#585382 | #9319. Bull Farm | xixixi | WA | 50ms | 3648kb | C++14 | 2.0kb | 2024-09-23 20:34:56 | 2024-09-23 20:34:57 |
Judging History
answer
#include<bits/stdc++.h>
#define PII pair<int,int>
using namespace std;
const int mxn=2e3+8;
int T,n,m1,m2,tot;
int h[mxn],temp[mxn],dp[mxn],vis[mxn];
int pr[mxn],mp[mxn][mxn];
int root(int x){
return pr[x]=(pr[x]==x?x:root(pr[x]));}
struct Star{
int to,w,nx;
}star[mxn*2];
void add(int x,int y,int w){
star[++tot].nx=h[x];
star[tot].to=y;
star[tot].w=w;
h[x]=tot;}
void dijkstra(int x){
memset(mp[x],0x3f,sizeof mp[x]);mp[x][x]=0;
memset(vis,0,sizeof vis);
priority_queue<PII>q;
q.push({0,x});
while(q.size()){
auto dfrom=q.top();q.pop();
int dval=dfrom.first;
int dpoint=dfrom.second;
if(vis[dpoint])continue;
vis[dpoint]=1;
for(int i=h[dpoint];~i;i=star[i].nx){
int dto=star[i].to;
if(vis[dto])continue;
mp[x][dto]=star[i].w;
q.push({star[i].w,dto});
}
}
return ;
}
signed main(){
ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
cin >> T;
while(T--){
cin >> n >> m1 >> m2 ;
for(int i=1;i<=n;i++)pr[i]=i,h[i]=-1;
int from=0,to=0;tot=0;
for(int i=1;i<=m1;i++){
int sum = 0 ;
string s;cin >> s ;
for(int j=0;j<n;j++){
temp[j+1]=(s[j*2]-'0')*50+(s[j*2+1]-'0');
dp[temp[j+1]]+=1;}
for(int j=1;j<=n;j++){
if(dp[j]==0)to=j;
if(dp[j]==2)from=j;
if(dp[j]){sum+=1,dp[j]=0;}}
if(sum==n){
for(int j=1;j<=n;j++){//建立环状边
int k=temp[j];
if(pr[j]!=pr[k])
add(j,k,i),add(k,j,i),pr[j]=root(k);}}
else if(sum==n-1)
for(int j=1;j<=n;j++)//建立单项边
if(temp[j]==from)add(j,to,i);
}
for(int i=1;i<=n;i++)dijkstra(i);
for(int i=1;i<=m2;i++){
string s;cin >> s ;
int from,to,lim;
from=(s[0]-'0')*50+(s[1]-'0');
to=(s[2]-'0')*50+(s[3]-'0');
lim=(s[4]-'0')*50+(s[5]-'0');
cout << (mp[from][to]<=lim) ;
}
cout << '\n';
// cout << mp[6][4] << '\n' ;
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3632kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 3584kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: -100
Wrong Answer
time: 50ms
memory: 3648kb
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110101101111111111111111111111111111111110111111110111111111011010111111111111111111101111111111110111111110111111111111111111111111111111111111111111111110001110111111111111111111111111011101111111111111111111111101111111111111111111011110100111111111111111111111100111111101110111111111101111110...
result:
wrong answer 1st lines differ - expected: '011110001101101111111111111111...1111111111111111101111111111111', found: '011110101101111111111111111111...1111111111111110101111111111111'