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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#583925#5418. Color the TreeLongvuWA 42ms20568kbC++143.8kb2024-09-23 00:07:082024-09-23 00:07:11

Judging History

你现在查看的是最新测评结果

  • [2024-09-23 00:07:11]
  • 评测
  • 测评结果:WA
  • 用时:42ms
  • 内存:20568kb
  • [2024-09-23 00:07:08]
  • 提交

answer

/**
 *    author:  longvu
 *    created: 09/22/24 22:35:37
**/
#include<bits/stdc++.h>

using namespace std;

#define sz(x) ((int)x.size())
#define all(x) (x).begin(), (x).end()
const int INF = 1e18;
const int nax = (int)(201001);
const int mod = 1e9 + 7;

template<class X, class Y>
bool maximize(X& x, const Y y) {
    if (y > x) {x = y; return true;}
    return false;
}
template<class X, class Y>
bool minimize(X& x, const Y y) {
    if (y < x) {x = y; return true;}
    return false;
}

#define Fi first
#define Se second

const int LOG = 18;

pair<int, int> rmq[nax][LOG + 1];
int euler[nax], h[nax], Log2[nax], fir[nax];
vector<int> adj[nax];
int m = 0;
void dfs(int u, int pa) {
    euler[++m] = u;
    fir[u] = m;
    rmq[m][0] = {h[euler[m]], euler[m]};
    for (auto v : adj[u]) {
        if (v == pa) {
            continue;
        }
        h[v] = 1 + h[u];
        dfs(v, u);
        euler[++m] = u;
        rmq[m][0] = {h[euler[m]], euler[m]};
    }
}

void precal() {
    m = 0;
    dfs(1, -1);
    for (int k = 1; k <= LOG; ++k) {
        for (int i = 1; i + (1 << k) - 1 <= m; ++i) {
            rmq[i][k] = min(rmq[i][k - 1], rmq[i + (1 << (k - 1))][k - 1]);
        }
    }
}

int find_lca(int u, int v) {
    int l = min(fir[u], fir[v]), r = max(fir[u], fir[v])
                                     , k = Log2[r - l + 1];
    return min(rmq[l][k], rmq[r - (1 << k) + 1][k]).Se;
}

int a[nax], dp[nax], rmqp[nax][LOG + 1];
vector<int> memo[nax];
int32_t main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    for (int i = 2; i < nax; ++i) {
        Log2[i] = 1 + Log2[i >> 1];
    }
    int tt;
    cin >> tt;
    while (tt--) {
        int n;
        cin >> n;
        for (int i = 0; i < n; ++i) {
            cin >> a[i];
            rmqp[i][0] = a[i];
        }
        for (int k = 1; k <= LOG; ++k) {
            for (int i = 0; i + (1 << k) - 1 < n; ++i) {
                rmqp[i][k] = min(rmqp[i][k - 1], rmqp[i + (1 << (k - 1))][k - 1]);
            }
        }
        auto get = [&](int l, int r) {
            int k = Log2[r - l + 1];
            return min(rmqp[l][k], rmqp[r - (1 << k) + 1][k]);
        };
        for (int i = 0; i <= n; ++i) {
            adj[i].clear();
            memo[i] = { -1};
        }
        for (int i = 1; i < n; ++i) {
            int u, v;
            cin >> u >> v;
            adj[u].push_back(v);
            adj[v].push_back(u);
        }
        precal();
        for (int i = 1; i <= n; ++i) {
            memo[h[i]].push_back(i);
        }
        int ans = 0;
        for (int hi = 0; hi < n; ++hi) {
            sort(1 + all(memo[hi]), [&](int u, int v) {
                return fir[u] < fir[v];
            });
            for (int i = 0; i <= sz(memo[hi]); ++i) {
                dp[i] = INF;
            }
            dp[0] = 0;
            for (int i = 1; i < sz(memo[hi]); ++i) {
                if (sz(memo[hi]) == 1) {
                    continue;
                }
                int l = 1, r = i;
                auto cal = [&](int z) {
                    return get(hi - h[find_lca(memo[hi][z], memo[hi][i])], hi) + dp[z - 1];
                };
                while (r - l >= 1) {
                    int mid1 = (2 * l + r) / 3, mid2 = (l + 2 * r) / 3;
                    if (cal(mid1) >= cal(mid2)) {
                        l = mid1 + 1;
                    } else {
                        r = mid2 - 1;
                    }
                }
                l--;
                minimize(dp[i], cal(l));
                minimize(dp[i], cal(min(i, l + 1)));
            }
            // cout << hi << " " << dp[sz(memo[hi]) - 1] << '\n';
            ans += dp[sz(memo[hi]) - 1];
        }
        cout << ans << '\n';
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 20568kb

input:

3
4
10 15 40 1
1 2
2 3
2 4
5
10 5 1 100 1000
1 2
2 3
2 4
4 5
4
1000 200 10 8
1 2
2 3
3 4

output:

35
17
1218

result:

ok 3 number(s): "35 17 1218"

Test #2:

score: -100
Wrong Answer
time: 42ms
memory: 20264kb

input:

3000
54
43 44 11 49 17 14 7 30 35 12 34 14 15 8 29 47 30 31 39 17 26 23 26 45 34 50 49 13 35 18 29 15 13 44 47 5 22 20 19 46 30 22 26 13 47 46 43 27 48 48 13 14 30 44
1 2
1 3
2 4
3 5
4 6
2 7
4 8
1 9
3 10
1 11
8 12
2 13
9 14
1 15
1 16
15 17
15 18
7 19
1 20
19 21
13 22
10 23
17 24
9 25
9 26
24 27
8 28...

output:

283
234
371
308
232
370
351
141
100
128
187
81
273
162
198
210
305
302
232
208
168
241
96
419
358
441
276
280
151
246
299
368
101
384
239
347
277
272
261
233
109
197
317
255
391
322
308
109
253
59
56
36
186
299
307
177
153
386
53
221
276
201
238
160
393
133
218
385
80
574
240
179
288
211
393
487
177...

result:

wrong answer 1st numbers differ - expected: '180', found: '283'