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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#580604 | #9315. Rainbow Bracket Sequence | Qingyyx | WA | 1ms | 7960kb | C++20 | 4.0kb | 2024-09-21 22:40:27 | 2024-09-21 22:40:28 |
Judging History
answer
#include<bits/stdc++.h>
#define ll long long
#define enl putchar('\n')
#define N 605
#define M 500005
using namespace std;
const int mod = 998244353;
const int inf = 0x3f3f3f3f;
char buf[1 << 21], * p1 = buf, * p2 = buf, obuf[1 << 21], * o = obuf, of[35];
#define gc()(p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)
inline ll qpow(ll a, ll n) { ll res = 1; while (n) { if (n & 1)res = res * a % mod; n >>= 1; a = a * a % mod; }return res; }
inline int read() { int s = 0, f = 1; char c = gc(); for (; !isdigit(c); c = gc())if (c == '-')f = -1; for (; isdigit(c); c = gc())s = s * 10 + c - '0'; return s * f; }
inline void read(int* a, int n) { for (int i = 1; i <= n; ++i)a[i] = read(); }
inline int inal(char* s) { int n = 0; for (s[0] = gc(); !isalpha(s[0]); s[0] = gc()); for (; isalpha(s[n]); s[++n] = gc()); return s[n] = 0, n; }
int n, m, S, T;
int head[N], tot, cur[N], dis[N]; ll cst;
bool vis[N];
struct node {
int to, nxt, val, ct;
}e[M << 1];
queue<int>que;
inline void add(int u, int v, int w, int c) {
// printf("%d %d %d\n", u, v, c);
e[tot] = {v, head[u], w, c};
head[u] = tot++;
e[tot] = {u, head[v], 0, -c};
head[v] = tot++;
}
inline bool spfa() {
while (!que.empty())que.pop();
memset(dis, 0x7f, sizeof(dis));
memset(vis, 0, sizeof(vis));
memcpy(cur, head, sizeof(head));
// for (int i = 1; i <= n; ++i)cur[i] = head[i];
dis[S] = 0;
que.push(S);
while (!que.empty()) {
int t = que.front();
que.pop();
vis[t] = 0;
for (int i = head[t]; ~i; i = e[i].nxt) {
int to = e[i].to;
if (dis[to] > dis[t] + e[i].ct && e[i].val) {
dis[to] = dis[t] + e[i].ct;
if (!vis[to]) {
vis[to] = 1;
que.push(to);
}
}
}
}
if (dis[T] ^ 0x7f7f7f7f)return true;
else return false;
}
inline ll dfs(int now, int lim) {
if (!lim || now == T)return lim;
int flow = 0, f;
vis[now] = 1;
for (int i = cur[now]; ~i; i = e[i].nxt) {
cur[now] = i;
if (!vis[e[i].to] && dis[e[i].to] == dis[now] + e[i].ct && (f = dfs(e[i].to, min(lim, e[i].val)))) {
flow += f;
cst += (ll)f * e[i].ct;
lim -= f;
e[i].val -= f;
e[i ^ 1].val += f;
if (!lim)break;
}
}
vis[now] = 0;
return flow;
}
inline int MCMF() {
ll ans = 0;
while (spfa())
ans += dfs(S, 0x7fffffff);
return ans;
}
int du[N];
int l[N], c[N], v[N];
void solve() {
memset(head, -1, sizeof(head));
memset(du, 0, sizeof(du));
cst = tot = 0;
n = read() * 2, m = read();
read(l, m);
read(c, n); read(v, n);
int s = n + n + m + 1, t = s + 1;
S = t + 1, T = S + 1;
int sum = 0;
for (int i = 2; i <= n; ++i)
add(i, i - 1, n, 0);
for (int i = 1; i <= n; ++i)
add(i, i + n, 1, 0);
for (int i = 1; i <= n; i += 2)
add(s, i, 1, 0);
for (int i = 1; i <= n; ++i)
add(i + n, n + n + c[i], 1, inf - v[i]);
for (int i = 1; i <= m; ++i)
add(n + n + i, t, n, 0);
for (int i = 1; i <= m; ++i)
du[n + n + i] -= l[i],
du[t] += l[i],
sum += l[i];
for (int i = n + n + 1; i <= t; ++i) {
if (du[i] > 0)add(S, i, du[i], 0);
if (du[i] < 0)add(i, T, -du[i], 0);
}
add(t, s, inf, 0);
int ans = MCMF();
if (ans < sum)printf("-1\n");
else printf("%lld\n", 1ll * (n / 2) * inf - cst);
}
signed main() {
clock_t c1 = clock();
#ifdef LOCAL
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout);
#endif
//=============================================================
int TxT = read();
while (TxT--)
solve();
//=============================================================
#ifdef LOCAL
end :
cerr << "Time Used:" << clock() - c1 << "ms" << endl;
#endif
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 7960kb
input:
2 3 2 1 2 1 2 2 2 1 2 3 1 4 2 2 1 3 2 2 2 1 2 2 2 1 2 3 1 4 2 2 1
output:
9 -1
result:
ok 2 number(s): "9 -1"
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 7900kb
input:
50 8 6 0 2 2 0 3 1 3 5 1 1 5 3 5 2 3 2 2 1 2 2 4 6 998133227 879226371 59632864 356493387 62611196 827258251 296576565 204244054 812713672 780267148 614679390 447700005 102067050 544546349 116002772 761999375 1 1 1 1 1 343766215 374461155 3 1 2 1 1 1 1 1 1 796323508 303640854 701432076 853325162 610...
output:
-1 343766215 2710758237 4996234876 -1 -1 1892561958 2539318868 1013080942 5341457976 -1 -1 2231197660 5002664193 6366657402 5995341117 -1 1903045212 6750751734 5590178776 -1 5172233034 -1 4182716768 5268471900 9549986103 9864154610 -1 5297975014 2122219134 883992368 1900878794 -1 5698622606 -1 29785...
result:
wrong answer 3rd numbers differ - expected: '2351080746', found: '2710758237'