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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#580382#8935. Puzzle: Easy as ScrabbleForever_Young#WA 0ms3972kbC++176.9kb2024-09-21 21:35:522024-09-21 21:35:53

Judging History

你现在查看的是最新测评结果

  • [2024-09-21 21:35:53]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3972kb
  • [2024-09-21 21:35:52]
  • 提交

answer

#include<vector>
#include<set>
#include<map>
#include<queue>
#include<string>
#include<algorithm>
#include<iostream>
#include<bitset>
#include<functional>
#include<chrono>
#include<numeric>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cassert>
#include<cmath>
#include<iomanip>
#include<random>
#include<ctime>
#include<complex>
#include<type_traits>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long LL;
typedef double D;
#define all(v) (v).begin(), (v).end()
mt19937 gene(chrono::system_clock::now().time_since_epoch().count());
typedef complex<double> Complex;
typedef pair<int, int> pii;
#define fi first
#define se second
#define ins insert
#define pb push_back
inline char GET_CHAR(){
    const int maxn = 131072;
    static char buf[maxn],*p1=buf,*p2=buf;
    return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++;
}
inline int getInt() {
    int res(0);
    char c = getchar();
    while(c < '0') c = getchar();
    while(c >= '0') {
        res = res * 10 + (c - '0');
        c = getchar();
    }
    return res;
}
inline LL fastpo(LL x, LL n, LL mod) {
    LL res(1);
    while(n) {
        if(n & 1) {
            res = res * (LL)x % mod;
        }
        x = x * (LL) x % mod;
        n /= 2;
    }
    return res;
}
template<LL mod> struct Num {
    LL a;
    Num operator + (const Num & b) { return Num{(a + b.a) % mod}; }
    Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; }
    Num operator * (const Num & b) { return Num{a * b.a % mod}; }
    Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; }
    void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;}
    void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;}
    void operator *= (const Num & b) { a = a * b.a % mod; }
    void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; }
    void operator = (const Num & b) { a = b.a; }
    void operator = (const LL & b) { a = b; }
};
template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) {
    os << a.a;
    return os;
}
LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; }
inline string itoa(LL x, int width = 0) {
    string res;
    if(x == 0) res.push_back('0');
    while(x) {
        res.push_back('0' + x % 10);
        x /= 10;
    }
    while((int)res.size() < width) res.push_back('0');
    reverse(res.begin(), res.end());
    return res;
}
const int _B = 131072;
char buf[_B];
int _bl = 0;
inline void flush() {
    fwrite(buf, 1, _bl, stdout);
    _bl = 0;
}
__inline void _putchar(char c) {
    if(_bl == _B) flush();
    buf[_bl++] = c;
}
inline void print(LL x, char c) {
    static char tmp[20];
    int l = 0;
    if(!x) tmp[l++] = '0';
    else {
        while(x) {
            tmp[l++] = x % 10 + '0';
            x /= 10;
        }
    }
    for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]);
    _putchar(c);
}
typedef double C;
struct P {
    C x, y;
    void scan() {
        double _x, _y;
        scanf("%lf%lf", &_x, &_y);
        x = _x; y = _y;
    }
    void print() {
        cout << '(' << x << ' ' << y << ')' << endl;
    }
    P operator + (const P & b) const { return P{x + b.x, y + b.y}; }
    P operator - (const P & b) const { return P{x - b.x, y - b.y}; }
    C operator * (const P & b) const { return x * b.y - y * b.x; }
    C operator % (const P & b) const { return x * b.x + y * b.y; }
};
P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; }
const int N = 1111;
const int LOG = 20;
const int mod = 1e9 + 7;
const int inf = 1e9 + 7;
int n, m;
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};
int rela[N];
int getr(int x) {
    int p = x;
    while(rela[p] != p) p = rela[p];
    int p1 = p; p = x;
    while(rela[p] != p) {
        int p2 = rela[p];
        rela[p] = p1;
        p = p2;
    }
    return p1;
}
char a[N][N];
int main() {
    int n, m;
    scanf("%d%d", &n, &m);
    for (int i = 0; i <= n + 1; i++) {
        scanf("%s", a[i]);
    }
    for (int d = 0; d < 2; d++) {
        for (int e = 0; e < 2; e++) {
            
            vector<char> cr(n), cc(m);
            for (int i = 1; i <= n; i++) {
                cr[i] = a[i][0];
            }
            for (int j = 1; j <= m; j++) {
                cc[j] = a[0][j];
            }
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= m; j++) {
                    if (a[i][j] == 'x') {
                        continue;
                    }
                    if (cr[i] != '.' && cc[j] != '.') {
                        if (cr[i] == cc[j]) {
                            a[i][j] = cr[i];
                            cr[i] = cc[j] = '.';
                        } else {
                            
                        }
                    } else if(cr[i] != '.') {
                        a[i][j] = cr[i];
                        cr[i] = '.';
                    } else if(cc[j] != '.') {
                        a[i][j] = cc[j];
                        cc[j] = '.';
                    } else {

                    }
                }
            }

            for (int i = 0; i <= n + 1; i++) {
                for (int j = 0; j * 2 <= m + 1; j++) {
                    swap(a[i][j], a[i][m + 1 - j]);
                }
            }
        }
        for (int i = 0; i <= m + 1; i++) {
            for (int j = 0; j * 2 <= n + 1; j++) {
                swap(a[j][i], a[n + 1 - j][i]);
            }
        }
    }
    bool flag = true;
    for (int i = 1; i <= n; i++) {
        char bg = '.', ed = '.';
        for (int j = 1; j <= m; j++) {
            if (a[i][j] >= 'A' && a[i][j] <= 'Z') {
                if (bg == '.') {
                    bg = a[i][j];
                }
                ed = a[i][j];
            } else {
                a[i][j] = 'x';
            }
        }
        flag &= a[i][0] == '.' || a[i][0] == bg;
        flag &= a[i][m + 1] == '.' || a[i][m + 1] == ed;
    }
    for (int i = 1; i <= m; i++) {
        char bg = '.', ed = '.';
        for (int j = 1; j <= n; j++) {
            if (a[j][i] >= 'A' && a[j][i] <= 'Z') {
                if (bg == '.') {
                    bg = a[j][i];
                }
                ed = a[j][i];
            } else {
                a[j][i] = '.';
            }
        }
        flag &= a[0][i] == '.' || a[0][i] == bg;
        flag &= a[n + 1][i] == '.' || a[n + 1][i] == ed;
    }
    if (flag) {
        printf("YES\n");
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                printf("%c", a[i][j]);
            }
            printf("\n");
        }
    } else {
        printf("NO\n");
    }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3780kb

input:

5 5
.CBA...
....x..
..x...C
A.....B
B..x..A
C......
.......

output:

YES
CBA..
....C
A...B
B...A
C....

result:

ok Correct.

Test #2:

score: 0
Accepted
time: 0ms
memory: 3792kb

input:

1 2
....
Nx..
..O.

output:

NO

result:

ok Correct.

Test #3:

score: 0
Accepted
time: 0ms
memory: 3776kb

input:

5 5
.U.N.X.
U....xX
Ox....X
M...xxN
Vx....S
Ix.x..X
..IBHX.

output:

YES
U.NX.
.O..X
M.N..
.VB.S
.I.HX

result:

ok Correct.

Test #4:

score: -100
Wrong Answer
time: 0ms
memory: 3972kb

input:

10 10
.BAZEMIEKUJ.
A..........K
B..x.x.x..x.
K.........xT
A.x..x.....J
Hx....x....B
Q..x....x.xW
S...x......W
S...x.xxx..Z
...x......xZ
I..x..x.x.xR
.QKO.ID..RW.

output:

NO

result:

wrong answer Jury has answer but participant has not.