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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#57977#3892. Efficiently ElevatedBeevo#RE 2ms3672kbC++231.8kb2022-10-24 01:23:022022-10-24 01:23:04

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-10-24 01:23:04]
  • 评测
  • 测评结果:RE
  • 用时:2ms
  • 内存:3672kb
  • [2022-10-24 01:23:02]
  • 提交

answer

#include <bits/stdc++.h>

#define el '\n'
#define ll long long
#define ld long double

#define Beevo ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);

using namespace std;

int h, w;
int dx[] = {0, 0, -1, 1};
int dy[] = {-1, 1, 0, 0};

bool valid(int x, int y) {
    return x >= 0 && x < h && y >= 0 && y < w;
}

void testCase() {
    cin >> h >> w;

    int g[h][w];
    vector<pair<int, int>> lvl[h * w];
    for (int i = 0; i < h; i++) {
        for (int j = 0; j < w; j++) {
            cin >> g[i][j];

            if (g[i][j] > 1)
                lvl[g[i][j]].emplace_back(i, j);
        }
    }

    bool b[h][w];
    memset(b, 0, sizeof b);

    int sol = 0;
    for (int i = h * w - 1; i >= 2; i--) {
        priority_queue<pair<int, pair<int, int>>> pq;

        for (auto j: lvl[i]) {
            int x = j.first, y = j.second;

            pq.push({b[x][y], {x, y}});

            for (int k = 0; k < 4; k++) {
                int newX = x + dx[k], newY = y + dy[k];

                if (valid(newX, newY) && g[newX][newY] < i)
                    b[newX][newY] = 1;
            }
        }

        while (pq.size()) {
            int x = pq.top().second.first;
            int y = pq.top().second.second;

            pq.pop();

            if (!b[x][y])
                sol++, b[x][y] = 1;

            for (int k = 0; k < 4; k++) {
                int newX = x + dx[k], newY = y + dy[k];

                if (valid(newX, newY) && g[newX][newY] == i && !b[newX][newY]) {
                    b[newX][newY] = 1;

                    pq.push({1, {newX, newY}});
                }
            }
        }
    }

    cout << sol;
}

signed main() {
    Beevo

    int T = 1;
//    cin >> T;

    while (T--)
        testCase();

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 3556kb

input:

3 3
1 2 3
0 0 4
7 6 5

output:

1

result:

ok single line: '1'

Test #2:

score: 0
Accepted
time: 2ms
memory: 3560kb

input:

6 7
0 0 0 0 0 0 0
0 1 2 3 2 1 0
0 1 2 3 2 1 0
0 0 0 0 0 0 0
0 1 0 5 0 0 0
0 0 0 0 0 0 0

output:

2

result:

ok single line: '2'

Test #3:

score: 0
Accepted
time: 2ms
memory: 3628kb

input:

4 4
1 1 2 1
2 2 1 2
1 2 2 1
2 1 2 2

output:

4

result:

ok single line: '4'

Test #4:

score: 0
Accepted
time: 2ms
memory: 3672kb

input:

50 25
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 5 0 0 0 0 10 10 0 10 10 0 10 11 0 10 10 0 0 0 0 0 0
0 0 0 4 0 0 0 0 10 0 0 0 10 0 10 0 0 0 11 0 0 0 0 0 0
0 0 0 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
5 4 3 0 3 4 5 0 10 0 0 0 10 0 11 0 0 0 10 0 0 0 0 0 0
0 0 0 3 0 0 0 0 10 10 0 10 1...

output:

28

result:

ok single line: '28'

Test #5:

score: -100
Runtime Error

input:

500 500
999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 1000000000 999999999 100000000...

output:


result: