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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#579541#9226. Game of Geniuseswind_cross#Compile Error//C++144.5kb2024-09-21 14:56:362024-09-21 14:56:36

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你现在查看的是最新测评结果

  • [2024-09-21 14:56:36]
  • 评测
  • [2024-09-21 14:56:36]
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answer

#include <bits/stdc++.h>
using namespace std;

#define rep(n) for (int _i_i_ = (n); _i_i_; --_i_i_)
#define repf(i, st, ed) for (int i = (st); i < (ed); ++i)
#define repr(i, st, ed) for (int i = (st); i > (ed); --i)
#define rep0(i, n) for (int i = 0; i < (n); ++i)
#define rep1(i, n) for (int i = 1; i <= (n); ++i)
#define mem(arr, x) memset((arr), x, sizeof (arr))
#define mkp make_pair
#define edge(y, x, ver) for (int _i_ = h[x], y = ver[_i_]; _i_; y = ver[_i_ = nxt[_i_]])
#define rand_init mt19937 rnd(chrono::system_clock::now().time_since_epoch().count())
#define setdb(v) setprecision(v)
using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;

class UF {
    vector<int> p, rk, sz;
    int cnt;
public:
    UF() {}
    UF(int n) {
        cnt = n;
        p.resize(n);
        iota(p.begin(), p.end(), 0);
        rk.resize(n);
        sz.resize(n);
        fill(sz.begin(), sz.end(), 1);
    }
    int find(int x) {
        return x == p[x] ? x : p[x] = find(p[x]);
    }
    bool merge(int x, int y) {
        int fx = find(x), fy = find(y);
        if (fx == fy) return false;
        --cnt;
        if (rk[fx] > rk[fy]) swap(fx, fy);
        p[fx] = fy;
        sz[fy] += sz[fx];
        if (rk[fx] == rk[fy]) ++rk[fy];
        return true;
    }
    int size() {
        return cnt;
    }
    int size(int i) {
        return sz[i];
    }
};


class BIT {
    vector<ll> bit;
    int mx;
public:
    BIT() {}
    BIT(int n) {
        mx = n;
        bit.resize(n + 1);
    }
    void upd(int i, ll x) {
        for (; i <= mx; i += i & -i) bit[i] += x;
    }
    ll ask(int i) {
        ll res = 0;
        for (; i; i &= i - 1) res += bit[i];
        return res;
    }
};

class lazySGT {
    vector<int> lt, rt;
    vector<ll> dat, tag;
    ll v;
    void spread(int k) {
        if (tag[k]) {
            dat[k * 2 + 1] += tag[k];
            dat[k * 2 + 2] += tag[k];
            tag[k * 2 + 1] = tag[k * 2 + 2] = tag[k];
            tag[k] = 0;
        }
    }
    void build(vector<ll> &a, int k, int l, int r) {
        lt[k] = l, rt[k] = r, dat[k] = a[l - 1];
        if (l == r) return ;
        int m = (l + r) >> 1;
        build(a, k * 2 + 1, l, m), build(a, k * 2 + 2, m + 1, r);
        dat[k] = dat[k * 2 + 1] + dat[k * 2 + 2];
    }
    void update(int k, int l, int r, ll v) {
        if (l <= lt[k] && rt[k] <= r) {
            dat[k] += v;
            tag[k] = v;
            return ;
        }
        if (r < lt[k] || rt[k] < l) {
            return ;
        }
        spread(k);
        update(k * 2 + 1, l, r, v), update(k * 2 + 2, l, r, v);
        dat[k] = dat[k * 2 + 1] + dat[k * 2 + 2];
    }
    
    ll query(int k, int l, int r) {
        if (l <= lt[k] && rt[k] <= r) {
            return dat[k];
        }
        if (r < lt[k] || rt[k] < l) {
            return 0;
        }
        spread(k);
        return query(k * 2 + 1, l, r) + query(k * 2 + 2, l, r);
    }
public:
    lazySGT() {}
    lazySGT(vector<ll> &a) {
        int n = a.size();
        lt.resize(n << 3), rt.resize(n << 3);
        dat.resize(n << 3), tag.resize(n << 3);
        fill(dat.begin(), dat.end(), v);
        build(a, 0, 1, n);
    }
    void update(int l, int r, ll v) {
        update(0, l, r, v);
    }
    ll query(int l, int r) {
        return query(0, l, r);
    }
};

class ST {
    vector<vector<ll>> arr;
public:
    ST() {}
    ST(vector<ll> a) {
        int n = a.size();
        arr.push_back(a);
        int k = 31 - __builtin_clz(n);
        rep1 (i, k) {
            arr.push_back(vector<ll>(n - (1 << i) + 1));
            rep0 (j, n - (1 << i) + 1) {
                arr[i][j] = min(arr[i - 1][j], arr[i - 1][j + (1 << (i - 1))]);
            }
        }
    }
    ll query(int l, int r) {
        int i = 31 - __builtin_clz(r - l + 1);
        return min(arr[i][l], arr[i][r - (1 << i) + 1]);
    }
};

const int maxn = 50 + 5;

int n;
int a;

void init() {
    
}

void clear() {
    
}

void solve() {
    cin >> n;
    int ans = 0;
    rep (n) {
        int mn = 1e5a;
        rep (n) {
            cin >> a;
            mn = min(mn, a);
        }
        ans = max(ans, mn);
    }
    cout << ans << endl;
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    init();
    int t = 1;
    //cin >> t;
    rep (t) {
        clear();
        solve();
    }
    return 0;
}

Details

answer.code: In function ‘void solve()’:
answer.code:170:18: error: unable to find numeric literal operator ‘operator""a’
  170 |         int mn = 1e5a;
      |                  ^~~~
answer.code:170:18: note: use ‘-fext-numeric-literals’ to enable more built-in suffixes