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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#579484#9319. Bull Farmlmeowdn#TL 39ms5768kbC++142.4kb2024-09-21 14:09:532024-09-21 14:09:53

Judging History

你现在查看的是最新测评结果

  • [2024-09-21 14:09:53]
  • 评测
  • 测评结果:TL
  • 用时:39ms
  • 内存:5768kb
  • [2024-09-21 14:09:53]
  • 提交

answer

//Shirasu Azusa 2024.09
#include<bits/stdc++.h>
#define fi first
#define se second
#define eb emplace_back
#define mp make_pair
using namespace std;
typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef __int128 i128;
template<typename T,typename U>
T ceil(T x, U y) {return (x>0?(x+y-1)/y:x/y);}
template<typename T,typename U>
T floor(T x, U y) {return (x>0?x/y:(x-y+1)/y);}
template<class T,class S>
bool chmax(T &a,const S b) {return (a<b?a=b,1:0);}
template<class T,class S>
bool chmin(T &a,const S b) {return (a>b?a=b,1:0);}
int popcnt(int x) {return __builtin_popcount(x);}
int popcnt(ll x)  {return __builtin_popcountll(x);}
int topbit(int x) {return (x==0?-1:31-__builtin_clz(x));}
int topbit(ll x)  {return (x==0?-1:63-__builtin_clzll(x));}
int lowbit(int x) {return (x==0?-1:__builtin_ctz(x));}
int lowbit(ll x)  {return (x==0?-1:__builtin_ctzll(x));}

#define int long long
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define per(i,a,b) for(int i=(a);i>=(b);i--)
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vp;
typedef tuple<int,int,int> tiii;
int read() {
  int x=0,w=1; char c=getchar(); 
  while(!isdigit(c)) {if(c=='-') w=-1; c=getchar();}
  while(isdigit(c)) {x=x*10+(c-'0'); c=getchar();} 
  return x*w;    
}

const int N=2005;
int n,m,q,f[N][N];

int getint(char a,char b) {
  return (a-48)*50+(b-48);
}

signed main() {
  int T=read();
  while(T--) {
    n=read(), m=read(), q=read();
    rep(i,1,n) rep(j,1,n) f[i][j]=m+1;
    rep(i,1,n) f[i][i]=0;
    rep(i,1,m) {
      static char st[N*2];
      scanf("%s",st); static int t[N],vs[N];
      rep(i,1,n) vs[i]=0;
      rep(i,1,n) {
        int x=i*2-2, y=i*2-1;
        t[i]=getint(st[x],st[y]);
        vs[t[i]]++;
      }
      int xc=0,y=0;
      rep(i,1,n) if(vs[i]!=1) {
        if(vs[i]==0) {
          if(y) {y=-1; break;}
          else y=i;
        } else xc=i;
      }
      if(y==-1) continue;
      if(y==0) {
        rep(j,1,n) chmin(f[j][t[j]],i);
      } else {
        rep(j,1,n) if(t[j]==xc) chmin(f[j][y],i);
      }
    }
    rep(k,1,n) rep(i,1,n) rep(j,1,n) chmin(f[i][j],max(f[i][k],f[k][j]));
    rep(i,1,q) {
      static char st[10];
      scanf("%s",st);
      int a=getint(st[0],st[1]), b=getint(st[2],st[3]), c=getint(st[4],st[5]);
      if(f[a][b]<=c) putchar('1');
      else putchar('0');
    } puts("");
  }
  return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3960kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 5768kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 39ms
memory: 3756kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: -100
Time Limit Exceeded

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:


result: