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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#579230#9345. Artful PaintingsEricWWA 238ms3808kbC++203.9kb2024-09-21 10:49:162024-09-21 10:49:16

Judging History

你现在查看的是最新测评结果

  • [2024-09-21 10:49:16]
  • 评测
  • 测评结果:WA
  • 用时:238ms
  • 内存:3808kb
  • [2024-09-21 10:49:16]
  • 提交

answer

// Program written by EricWu ~~~
#include <bits/stdc++.h>
 
#define lowbit(x) (x & -x)
 
using namespace std;
 
inline char gc(void) {
    static char buf[100000], *p1 = buf, *p2 = buf;
    return p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 100000, stdin), p1 == p2) ? EOF : *p1++;
}
 
#define gc() getchar()
 
template <class T> inline void read(T &x) {
    T f = 1; x = 0; static char c = gc();
    for (; !isdigit(c); c = gc()) if (c == '-') f = -f;
    for (; isdigit(c); c = gc()) x = x * 10 + (c & 15);
    if (f == -1) x = -x;
}
 
inline void readstr(char *s) {
    do *s = gc(); while ((*s == ' ') || (*s == '\n') || (*s == '\r'));
    do *(++s) = gc(); while ((~*s) && (*s != ' ') && (*s != '\n') && (*s != '\r'));
    *s = 0; return;
}
 
inline void readch(char&x) { while (isspace(x = gc())); }
 
char pf[100000], *o1 = pf, *o2 = pf + 100000;
#define ot(x) (o1 == o2 ? fwrite(pf, 1, 100000, stdout), *(o1 = pf) ++= x : *o1 ++= x)
template <class T>
inline void println(T x, char c = '\n') {
    if (x < 0) ot(45), x = -x;
    static char s[15], *b; b = s;
    if (!x) *b ++= 48;
    for (; x; * b ++= x % 10 + 48, x /= 10);
    for (; b-- != s; ot(*b)); ot(c);
}
 
template <class T> inline void write(T x) {
    if (x < 0) x = -x, putchar('-');
    if (x > 9) write(x / 10);
    putchar(x % 10 + 48);
}
 
template <class T> inline void writeln(T x, char c = '\n') { write(x); putchar(c); }
template <class T> inline void chkmax(T &x, const T y) { x > y ? x = x : x = y; }
template <class T> inline void chkmin(T &x, const T y) { x < y ? x = x : x = y; }
 
#define Ms(arr, opt) memset(arr, opt, sizeof(arr))
#define Mp(x, y) make_pair(x, y)
#define endl '\n'

typedef long long ll;
typedef pair <int, int> pii;
typedef array<int, 3> piii;
using i64 = long long;
const int inf = 1e9;

void solve() {
    int n, m1, m2; read(n), read(m1), read(m2);
    vector rules1(m1, vector<int>(3, 0));
    vector rules2(m2, vector<int>(3, 0));
    for (int i = 0;i < m1;i++) 
        read(rules1[i][0]), read(rules1[i][1]), read(rules1[i][2]);
    for (int i = 0;i < m2;i++) 
        read(rules2[i][0]), read(rules2[i][1]), read(rules2[i][2]);
    int l = 0, r = n, ans = n;
    vector adj(n + 2, vector<pair<int, int>>());
    for (int i = 1;i <= n;i++) {
        adj[i].emplace_back(i - 1, 0);
        adj[i - 1].emplace_back(i, 1);
    }
    for (int i = 0;i < m1;i++) {
        adj[rules1[i][1]].emplace_back(rules1[i][0] - 1, -rules1[i][2]);
    }
    int S = n + 1;
    for (int i = 0;i <= n;i++) adj[S].emplace_back(i, 0);
    auto check = [&](int mid) -> bool {
        for (int i = 0;i < m2;i++) {
            adj[rules2[i][0] - 1].emplace_back(rules2[i][1], mid - rules2[i][2]);
        }
        adj[0].emplace_back(n, mid); adj[n].emplace_back(0, -mid);
        vector<int> dis(n + 2, inf), cnt(n + 2, 0);
        vector<bool> vis(n + 2, false);
        queue<int> q; q.emplace(S), vis[S] = 1, dis[S] = 0;
        while (q.size()) {
            auto u = q.front(); q.pop();
            vis[u] = 0;
            for (auto &[v, w] : adj[u]) {
                if (dis[v] > dis[u] + w) {
                    dis[v] = dis[u] + w;
                    if (!vis[v]) {
                        q.emplace(v);
                        vis[v] = true;
                        cnt[v] ++;
                        if (cnt[v] >= n + 1) return false;
                    }
                }
            }
        }
        
        return true;
    };
    while (l <= r) {
        int mid = (l + r) >> 1;
        if (check(mid)) {
            for (int i = 0;i < m2;i++) {
                adj[rules2[i][0] - 1].pop_back();
            }
            adj[0].pop_back(); adj[n].pop_back();
            ans = mid;
            r = mid - 1;
        } else {
            l = mid + 1;
        }
    }
    writeln(ans);
}

int main() {
    int T = 1; read(T);
    while (T--) solve();
    // system("pause");
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3808kb

input:

1
3 1 1
1 2 1
2 2 1

output:

1

result:

ok single line: '1'

Test #2:

score: -100
Wrong Answer
time: 238ms
memory: 3732kb

input:

1
1000 500 500
479 860 170
73 939 25
363 772 30
185 584 89
326 482 10
784 949 23
384 740 114
233 693 45
167 724 211
217 436 95
46 701 153
138 585 67
321 388 11
114 890 194
407 854 74
438 845 117
9 718 259
393 576 35
182 707 257
451 766 136
150 382 31
468 785 40
202 490 46
326 815 59
272 441 77
123 8...

output:

500

result:

wrong answer 1st lines differ - expected: '492', found: '500'