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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#579207 | #9345. Artful Paintings | EricW | WA | 0ms | 3520kb | C++23 | 3.8kb | 2024-09-21 10:38:10 | 2024-09-21 10:38:11 |
Judging History
answer
// Program written by EricWu ~~~
#include <bits/stdc++.h>
#define lowbit(x) (x & -x)
using namespace std;
inline char gc(void) {
static char buf[100000], *p1 = buf, *p2 = buf;
return p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 100000, stdin), p1 == p2) ? EOF : *p1++;
}
#define gc() getchar()
template <class T> inline void read(T &x) {
T f = 1; x = 0; static char c = gc();
for (; !isdigit(c); c = gc()) if (c == '-') f = -f;
for (; isdigit(c); c = gc()) x = x * 10 + (c & 15);
if (f == -1) x = -x;
}
inline void readstr(char *s) {
do *s = gc(); while ((*s == ' ') || (*s == '\n') || (*s == '\r'));
do *(++s) = gc(); while ((~*s) && (*s != ' ') && (*s != '\n') && (*s != '\r'));
*s = 0; return;
}
inline void readch(char&x) { while (isspace(x = gc())); }
char pf[100000], *o1 = pf, *o2 = pf + 100000;
#define ot(x) (o1 == o2 ? fwrite(pf, 1, 100000, stdout), *(o1 = pf) ++= x : *o1 ++= x)
template <class T>
inline void println(T x, char c = '\n') {
if (x < 0) ot(45), x = -x;
static char s[15], *b; b = s;
if (!x) *b ++= 48;
for (; x; * b ++= x % 10 + 48, x /= 10);
for (; b-- != s; ot(*b)); ot(c);
}
template <class T> inline void write(T x) {
if (x < 0) x = -x, putchar('-');
if (x > 9) write(x / 10);
putchar(x % 10 + 48);
}
template <class T> inline void writeln(T x, char c = '\n') { write(x); putchar(c); }
template <class T> inline void chkmax(T &x, const T y) { x > y ? x = x : x = y; }
template <class T> inline void chkmin(T &x, const T y) { x < y ? x = x : x = y; }
#define Ms(arr, opt) memset(arr, opt, sizeof(arr))
#define Mp(x, y) make_pair(x, y)
#define endl '\n'
typedef long long ll;
typedef pair <int, int> pii;
typedef array<int, 3> piii;
using i64 = long long;
const int inf = 1e9;
void solve() {
int n, m1, m2; read(n), read(m1), read(m2);
vector rules1(m1, vector<int>(3, 0));
vector rules2(m2, vector<int>(3, 0));
for (int i = 0;i < m1;i++)
read(rules1[i][0]), read(rules1[i][1]), read(rules1[i][2]), rules1[i][0] --;
for (int i = 0;i < m2;i++)
read(rules2[i][0]), read(rules2[i][1]), read(rules2[i][2]), rules2[i][0] --;
int l = 0, r = n, ans = n;
auto check = [&](int mid) -> bool {
vector adj(n + 2, vector<pair<int, int>>());
for (int i = 1;i <= n;i++) {
adj[i].emplace_back(i - 1, -1);
adj[i - 1].emplace_back(i, 0);
}
for (int i = 0;i < m1;i++) {
adj[rules1[i][1]].emplace_back(rules1[i][0], rules1[i][2]);
}
for (int i = 0;i < m2;i++) {
adj[rules2[i][0]].emplace_back(rules2[i][1], rules2[i][2] - mid);
}
int S = n + 1;
adj[0].emplace_back(n, mid); adj[n].emplace_back(0, -mid);
for (int i = 0;i <= n;i++) adj[S].emplace_back(i, 0);
vector<int> dis(n + 2, inf), cnt(n + 2, 0);
vector<bool> vis(n + 2, false);
queue<int> q; q.emplace(S), vis[S] = 1, dis[S] = 0;
while (q.size()) {
auto u = q.front(); q.pop();
vis[u] = 0;
for (auto &[v, w] : adj[u]) {
if (dis[v] > dis[u] + w) {
dis[v] = dis[u] + w;
if (!vis[v]) {
q.emplace(v);
vis[v] = true;
cnt[v] ++;
if (cnt[v] >= n) return false;
}
}
}
}
return true;
};
while (l <= r) {
int mid = (l + r) / 2;
if (check(mid)) {
ans = mid;
r = mid - 1;
} else {
l = mid + 1;
}
}
writeln(ans);
}
int main() {
int T = 1; read(T);
while (T--) solve();
// system("pause");
return 0;
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3520kb
input:
1 3 1 1 1 2 1 2 2 1
output:
3
result:
wrong answer 1st lines differ - expected: '1', found: '3'