#include <bits/stdc++.h>
using namespace std;
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
/// You may use:

// The number of students
int N;

// The probability any given student is positive
double P;

// This function performs a test on a subset of samples.
// Its argument is a vector of Booleans of length N,
// where the i-th element is true if the i-th sample should be added to the mix.
// It returns true if (and only if) at least one of the samples in the mix is positive.
bool test_students(std::vector<bool> mask) {
    assert(mask.size() == (size_t)N);

    std::string mask_str(N, ' ');
    for (int i = 0; i < N; i++)
        mask_str[i] = mask[i] ? '1' : '0';

    printf("Q %s\n", mask_str.c_str());
    fflush(stdout);

    char answer;
    scanf(" %c", &answer);
    return answer == 'P';
}

/// You should implement:

// This function will be called once for each test instance.
// It should use test_students to determine which samples are positive.
// It must return a vector of Booleans of length N,
// where the i-th element is true if and only if the i-th sample is positive.

typedef double ld;
const ld INF=1e9;
ld dp[1009][1009],pb[1009];
int trans[1009][1009];
mt19937 rnd(time(0));
std::vector<bool> find_positive(bool typ) {
    std::vector<bool> answer(N);
        rep(i,0,N-1){
            vector<bool>msk(N);
            msk[i]=1;
            if(test_students(msk))answer[i]=1;
        }
        return answer;
    
}
int main() {
    int T;
    scanf("%d %lf %d", &N, &P, &T);
    if(T>1){
        pb[0]=1;
        rep(i,1,N)pb[i]=pb[i-1]*(1-P);
        rep(i,0,N+1){
            rep(j,0,N+1)dp[i][j]=INF;
        }
        rep(i,0,N+1)dp[0][i]=0;
        rep(i,1,N){
            dp[i][1]=dp[i-1][0];
            rep(j,2,i){
                rep(k,1,j){
                    ld prob=(pb[k]-pb[j])/(1-pb[j]);
                    ld val=dp[i-k][j-k]*prob+dp[i][k]*(1-prob)+1;
                    if(val<dp[i][j])dp[i][j]=val,trans[i][j]=k;
                }
            }
            rep(j,1,i){
                ld val=dp[i-j][0]*pb[j]+dp[i][j]*(1-pb[j])+1;
                if(val<dp[i][0])dp[i][0]=val,trans[i][0]=j;
            }
        }
    }
    // You may perform any extra initialization here.

    for (int i = 0; i < T; i++) {
        std::vector<bool> answer = find_positive(T==1);
        assert(answer.size() == (size_t)N);
        std::string answer_str(N, ' ');
        for (int j = 0; j < N; j++)
            answer_str[j] = answer[j] ? '1' : '0';

        printf("A %s\n", answer_str.c_str());
        fflush(stdout);

        char verdict;
        scanf(" %c", &verdict);
        if (verdict == 'W')
            exit(0);
    }

    return 0;
}