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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#578311 | #9327. Permutation and Queries | Afterlife# | WA | 14ms | 31432kb | C++20 | 5.0kb | 2024-09-20 18:09:52 | 2024-09-20 18:09:52 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define int long long
using ll=long long;
using poly=vector<int>;
const int N=2e6+1e3+7,P=998244353,mod=P;
int qpow(int a,int b)
{
int ret=1;
while(b)
{
if(b&1)
ret=ret*a%P;
b>>=1;
a=a*a%P;
}
return ret;
}
namespace Core {
int a[N],b[N],w[N],rev[N];
void NTT(int *a,int len)
{
for(int i=1;i<len;i++)
if(i>rev[i])
swap(a[i],a[rev[i]]);
for(int d=1;d<len;d<<=1)
for(int m=d<<1,i=0;i<len;i+=m)
for(int j=0;j<d;j++)
{
int x=a[i+j],y=a[i+j+d]*w[len/m*j]%P;
a[i+j]=(x+y>=P?x+y-P:x+y);
a[i+j+d]=(x-y<0?x-y+P:x-y);
}
}
}
poly operator *(const poly &va,const poly &vb)
{
using namespace Core;
int len=1;
while(len<(int)va.size()+(int)vb.size()-1)
len<<=1;
for(int i=0;i<len;i++)
a[i]=(i<(int)va.size()?va[i]:0);
for(int i=0;i<len;i++)
b[i]=(i<(int)vb.size()?vb[i]:0);
for(int i=1;i<len;i++)
rev[i]=rev[i>>1]>>1|(i&1?len>>1:0);
w[0]=1;
w[1]=qpow(3,(P-1)/len);
for(int i=2;i<len;i++)
w[i]=1ll*w[i-1]*w[1]%P;
NTT(a,len);
NTT(b,len);
for(int i=0;i<len;i++)
a[i]=1ll*a[i]*b[i]%P;
reverse(a+1,a+len);
NTT(a,len);
poly c(va.size()+vb.size()-1);
for(int i=0,invlen=qpow(len,P-2);i<(int)c.size();i++)
c[i]=a[i]*invlen%P;
return c;
}
poly Fix(poly a,int n)
{
a.resize(n);
return a;
}
poly Inv(poly f,int n)
{
poly g(1,qpow(f[0],P-2));
while((int)g.size()<n)
{
int nlen=min<int>(g.size()<<1,n);
poly tmp(Fix((Fix(f,nlen)*g),nlen));
for(int i=0;i<nlen;i++)
tmp[i]=(P-tmp[i]+(i==0?2:0))%P;
g=Fix(g*tmp,nlen);
}
return g;
}
int k , p;
int t[N] , rt[N];
poly calc(int k,int p) {
poly f(2) ; f[1] = 1;
int ck = 1;
for(int d = (int)__lg(k) - 1 ; d >= 0 ; d--) {
///
poly g(f.size()) ;
int l = g.size() - 1;
for(int i = 0;i < g.size();i++) g[l - i] = 1LL * rt[i] * qpow((mod - ck) % mod , i) % mod;
poly c = f * g;
for(int i = 0;i <= ck ; i++) {
c[i] = 1LL * c[i + l] * rt[i] % mod;
f[i] = 1LL * f[i] * rt[i] % mod;
}
c.resize(ck + 1);
f = f * c;
ck *= 2;
// for(int i = 0;i < f.size();i++) printf("%d ",f[i]) ; printf("\n");
if((k >> d) & 1) {
/// * (x - ck)
f.push_back(0);
for(int i = f.size() - 1;i >= 0;i--) {
if(i) f[i] = (1LL * f[i] * (mod - ck) + f[i - 1]) % mod;
else f[i] = 1LL * f[i] * (mod - ck) % mod;
}
ck++ ;
}
if(d) {
for(int i = 0;i <= ck;i++) f[i] = 1LL * f[i] * t[i] % mod;
}
}
// for(int i = 0;i < f.size();i++) printf("%d ",f[i]) ; printf("\n");
poly ans(1) ; ans[0] = 1;
while(p) {
if(p & 1) ans = ans * f;
p >>= 1;
if(p) f = f * f;
}
return ans;
}
int C(int a,int b) {
return 1LL * t[a] * rt[b] %mod * rt[a - b] % mod;
}
void solv() {
cin >> k >> p;
poly p2 = calc(k , p);
// for(int i = 0;i < p2.size();i++) printf("%d ",p2[i]) ;
// printf("\n");
int d = qpow(qpow(t[k] , mod - 2) , p) ;
for(int i = 0;i < p2.size();i++) p2[i] = 1LL * p2[i] * d % mod;
poly F(k * p + 1) ;
F[0] = 1;
for(int i = 1;i <= k*p;i++) {
for(int j = 0;j < i;j++) {
int sol = 2LL * F[j] * C(i,j) % mod;
if((i - j + 1) & 1) F[i] = (F[i] - sol + mod) % mod;
else F[i] = (F[i] + sol) % mod;
}
}
for(int i = 0;i <= k*p;i++) {
F[i] = 1LL * F[i] * rt[i] % mod;
printf("%d ",F[i]) ;
}
printf("\n") ;
poly T(k * p + 1);
T[0] = 0;
for(int i = 1;i <= k*p;i++) {
T[i] = rt[i] ;
if((i + 1) & 1) T[i] = (mod - T[i]) % mod;
}
poly K = F * T;
for(int i = 0;i <= k*p;i++) {
printf("%d ",K[i]) ;
}
printf("\n");
for(int i = 0;i <= k*p;i++) {
T[i] = (2*T[i] - 1 + mod) % mod ;
}
poly f = Inv(T , k*p + 1) ;
for(int i = 0;i < f.size();i++) {
f[i] = 1LL * f[i] * (mod - 1) % mod;
f[i] = 1LL * f[i] * t[i] % mod;
printf("%d ",f[i]);
}
printf("\n");
int ans = 0;
for(int i = 0;i <= k * p;i++) {
ans = (ans + 1LL * f[i] * p2[i]) % mod;
}
cout << ans << '\n';
}
signed main()
{
ios::sync_with_stdio(false) ; cin.tie(0) ;
int T;cin >> T;
int N = 1e6;
t[0] = rt[0] = 1;
for(int i = 1 ; i <= N;i++) t[i] = 1LL * t[i - 1] * i % mod;
rt[N] = qpow(t[N] , mod - 2);
for(int i = N - 1;i >= 0;i--) rt[i] = 1LL * rt[i + 1] * (i + 1) % mod;
while(T--) solv() ;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 14ms
memory: 31432kb
input:
6 5 2 4 1 6 3 5 1 2 3 5 1 2 5 3 5 6
output:
737594047 415935148 885629612 565671804 839 565671804 1 2 3 332748122 748683271 715408462 856826416 720558145 257731270 845971415 695772079 0 1 499122178 166374061 873463812 357704231 428413208 859401249 128865635 922107884 847008216 1 1 998244351 998244331 998244271 302 7842 55890 997999943 98656...
result:
wrong answer 1st numbers differ - expected: '2', found: '737594047'